Solving 'impossible' integrals in seconds
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- Опубліковано 28 вер 2024
- At first glance I thought these integrals would be nearly impossible to solve. But there is a technique where you can solve them nearly instantly!
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Solve in seconds... as long as you know some obscure integral formula for substitution... If you don't know this formula, you're screwed. Yup, great challenge.
different places teach different obscure integral formulas depending on the program, some common integral formulas are more useful in different scenarios. for example, i take economics, so they never teach trigonometric identities because we never use them, whereas they are essential for most of physics. certain types of physics rarely use e, whereas economics uses it constantly. pun intended.
Even without the formula, it takes like 30 sec to solve
actually, let u = a+b-x ,then its new definite intergral will always equal to the orginal one, you should memorise the proof itnstead of the stpuid formula which may be some simpified version for exam purpose only
Its a common technique and is taught by the name of “king’s rule” all over india. Different places have different different formulas for simplifying integration but its scattered all over the world. No one has a complete knowledge of integration
@@evlredsun There's virtually no area of physics that doesn't make extensive use of the constant "e".
Plzz don't shame JEE main, this is the easiest question of definite integral...from NCERT class Xll part -2....
Yes.....we have these type of integral problem for 6 marks in our 12th pre board exams
r/iamverysmart
And he is saying JEE MAINS entrance exam for IITs somebody please tell him about JEE ADVANCED
@@multilogic2746 He said that it's a precursor to the exam to get admission into IIT.
Ya I haven't learnt any math after my 3rd sem which was 4yr ago still I solved it😅 just took some time to recognize the pattern of question and then it was done.
Le JEE Advanced - this isn't even my final form
Jee advance: i used to solve these in XI physics
This is JEE Maine not JEE Advanced
Its not that dificult if you take some tutorial class which is a must. He didnt mentioned the rule that in definite integration,
integral(a to b f(x))=integral(a to b f(a+b-x)). This rule is used to derive above expression. And this is a very basic rule even taught in schools in class 12 and its very normal
@@jyotsnasrivastava6373 exactly
@@jyotsnasrivastava6373 are you jee aspirant
That's not a level of jee main.
It's a board base questions. ...
Not even board
These kinds of questions do come in jee mains.
@@adveshdarvekar7733 rarely
@@adveshdarvekar7733 these types of ques used to come when JEE main was conducted by CBSE now it is conducted by NTA and those questions are tough
True😂😂
When I come across an integral like these (as a taxi driver) I promise I shall use this technique. 😳
😂😂😂
that's why you are a taxi driver!
@@ionut.666 Taxi driver is my day job. By night I am a business consultant, philosopher, educator and entertainer; not much need for this type of equation in any of those fields. Actually, the vast majority of occupations have no need for this technique, but it is good to know.
@pola os doubt you have any to give out.
Ted, you don't need to know this "useless" formula !
For example let's call I = ∫₀ₐ √(sinx) dx/[√(sinx) + √(cosx)] and J = ∫₀ₐ√(cosx) dx/[√(sinx) + √(cosx)] (please note that a = π/2 → π/2 is very difficult to write inside the integral).
Then we have I + J = ∫₀ₐ1.dx = [x]₀ₐ = a - 0 = a = π/2
Now let's show that J = I :
as we know sin(π/2 - t) = cost, and cos (π/2 - t) = sint, then we are led to note x = (π/2 - t) ⇒ dx = - dt and J = ∫ₐ₀√(cos(π/2 - t).(-dt)/[√(cost) + √(sint)] = ∫₀ₐ√(sint).dt/[√sint + √cost] = I
The end : I + J = π/2 ⇒ 2I = π/2 so I = π/4.
To serve you. professor essef, in mathematics (active on YT and Wiki, in astronomy and astrophysics). Paris, Saturday, May, 23, 2020.
Here's how to solve this within seconds
Step 1. Be born in India
Lmao🤣🤣🤣!!
How to solve this within milliseconds
Step 1: Be born in China 🙂
You will regret it
Corona virus bruh
Step 2. Take medical😂😂
Always answer is →π/4 .This question can be asked in 11 types
How sir
Absolutely sir
That's funny. In the U.S. medical school STEP test, if one of the answers to a question is "hepatitis," then the correct answer to the question is "hepatitis."
For those who are confused at 5:18 why did the limits changed?
When we change the variables (i.e. from x to u) we also have to change variables i.e. upper limit for x is b but we're substituting u=a+b-x so when we put x=b in u=a+b-x it becomes u=a+b-b so b cancels out and upper limit converts to a and in same way x=a in lower limit converts to b
he subsituted u=a+b-x so if you calculate value of u when x=a then u = a+b-a= b and similiarly when x=b then u will be a, hence the limits of integral changes
@@yashmehta830 exactly 👍
Thank🥺
My doubt is, initially he substituted u=a+b-x, but later he simply substituted x for u... Shouldn't that be x=a+b-u?
@@siddharthannandhakumar6187 u is a dummy variable.
You can refer following property of definite integral
Integration.
limit a to b f(x)dx = limit a to b f(t)dt
It is a class 12 level integral... And from NCERT
Yeah the problem 8n the thumbnail is in ncert ch:7- ex:7.11, Pg 347
😉
And then there's people like me, who haven't learned integrals in school at all.
Teachers hate him, Watch how he solves complex problems in seconds with this one trick!
Haha
He's given a complicated integral. What happens next will ASTOUND you!
LoL complex xD
I'm a math teacher and I Love it!! :D
with this one WIERD trick
Trust me..
I've given these exams...
The question you've given in the video is one of the easiest ones...
It's a freaking tough exam. Please do more videos on IITJEE problems... Love your channel ✌️
@@anandk9220 answer to second question is (4 -3√2)/4
@@anandk9220 answer of question1 is 3/2(e^5/2)
@@AmanKumar-vd1jc
Are you IITian or IIT aspirant?
@@AmanKumar-vd1jc
As far as I can recall, I have never ever learnt this property (used in question 1) in my class 12 math
∫ [ f(x) + x f'(x) ] dx
= x f(x) + c
Perhaps this property is studied and included primarily in JEE Math. I've not studied or appeared for JEE so I didn't have any idea about this.
@@anandk9220 preparing for IIT
Ik this turned out to be too long, bt give it a read, it's really helpful to those who were not taught this property, and even for those who know this property since I got over slightly on the intuition behind it.
There's a common property of definite integration we are taught here in India
integral from a to b of f(x)=integral from a to b of f(a+b-x)
You can prove this by putting u=a+b-x, in a manner similar to how he proved this case.
This problem he showed is a special type, where everything just cancels off.
But i wanna say why this works, like not the mathematical proof, bt a more intuitive one.
The integral from a to b of f(a+b-x) is actually nothing bt evaluating the original integral just in a backward direction (from b to a)
When you're at a, the differential is f(a+b-a)dx=f(b)dx
When you reach b, the differential is f(a)dx.
Summing up all the small strips of area, we get the same thing, the area under the curve of f(x) from a to b.
This was the intuition behind this "King's property" (that's what we call it here)
This property can be used in almost every question of definite integral to make the final integrand super easy.
To use this directly,
When I=integral from a to b of f(x),
After applying this property,
I=1/2(integral from a to b of [f(x)+f(a+b-x)]dx)
In India, we're not really taught the actual intuition behind it (most teachers don't), bt I think it's good to know this.
😲
thank you. did not know what it actually did
Thanks for the explanation. Are there any similar tricks that you could share?
This is my board questions lol😂
Shi me bhai last exercise ka h ye ,inhe to ye simple integral ke liye bhi direct formula yaad krte h😂😂
NCERT KA H😂😂
ICSE board hai na tera? 😂
I hope you used the proof based method to solve rather than applying the formula.
Help me, 5:27 me "u" ko direct "X" Mai kaise convert kiya
The guy who found out this formula was smart.
Bytheway, we in Switzerland never learned this formula. Even if it’s over 23 years ago, I don’t remember having seen it. Different education goals?
This is a trick used by many Indian students
I suspect different education system focus on different formulas to memorize.
You can probably deduce most formulas you need, but it takes time. This is not to bad in real life, because you might need an hour or two to either figure it out, or look it up, in a project that takes months (if the end result is software) or years (if the end result is engineering). Getting it right is more important at this stage than being quick.
Exams have a very limited time span, so they tend to rely on memorized formulas. After all, if you had it memorized once, you are likely to recognize it when you look it up.
But there are too many formulas available, so only a small subset it taught.
Some, like the formula for solving quadratic equations, seem to be universal, but when it comes to integrals, the shortcuts taught varies.
Point in case:
In a algebra exam at university, I had two complex logical expressions that I needed to prove equal.
In real life, I would just set up a computer and run through all 1024 combinations (if there were 10 variables, and I believe there were even fewer). But this would be pointless.
The idea here was that there was a lemma in the book that we were supposed to refer to which would solve this in seconds. Assuming you had spent either five minutes memorizing it (and it stuck), or a few hours with the proof (and not had time for everything else in the curriculum).
Well, I did well on the test, I had two questions left with two hours to go. One question I had no idea here to start, but this one I brute force over three hand written A4 papers in the time I had left. The professor had to give me full points, because I had executed it flawlessly.
So, which of these three approaches would have worked in real life?
Memorizing without understanding, and the formula would be gone six months after the test.
Learning the hard way, and it would hang around for years.
This method? I can probably do it again because I only used basic techniques that I will remember as long as my brain is in half decent shape. But it would be hard and slow work. I will not win competitions, but if that software we are building depends on it at least i can be pretty sure I got this right.
These questions basically boil down to knowing the trick. But i still think have to revise my integral knowledge
Same in America. Guess we'd rather prioritize understanding how to solve the problem rather than using tricks.
Mate, trust me, you guys are better off with the education techniques that you have in Switzerland. In India, it's all about doing these problems by learning tricks and that's about it! Who do we think about when we think of Quality, Precision, and standards? Switzerland! And I am telling you this as an Indian. Having personally studied abroad, I know that in foreign Universities, the emphasis is on learning it properly. Just the like the American guy wrote, the Universities that I have come across have emphasized on getting the basics right. When we think about Engineering, we think about the US, Europe, Japan, etc. And on top of that, India is plagued with the reservation criteria where a person's cast determines what would be his cut - off grades for entry into Governmental institutions.
You ask anyone in India and they will speak highly of the IITs, the NITs, etc. But, despite having all these bright students, India is still plagued by failures. In 2019, a mission to Moon didn't go right. The Indians took solace in the fact that the big countries like US, Russia, themselves had to try more than 10 times, while conveniently forgetting that those attempts were made in the 50s and 60s.
Indian education system is meant for culling the over - population from having bigger dreams. After all, they can't afford to have so many educated people. These tests are really hard. People prepare for years for them. Those who clear it, then take their legs off the pedal because they now think they deserve to enjoy the benefits of their personal hard work.
Another thing in which Indians will take pride is in telling everyone how a majority of scientists and engineers in the US companies are Indians. They forget that you can't be Indian if you want to be working in these companies. They apply for the PR and the eventually give the test for citizenship. Citizenship! They pledge their allegiance to the US Flag. Now US is one country where people like to celebrate their dual nationality but India isn't. India clearly doesn't allow dual citizenship. And if at all they do provide it to these eminent people, it is just to earn brownie - points. Point is, everybody wants to go to the west because there is literally nothing happening here. Only thing you can set up are big software companies. Core mechanical is down in garbage. We have been trying to produce an indigenous Light - combat aircraft and its very own engine, since the past 30 - 40 years. Guess what, nothing has happened. Imagine, a country that has an engineering institution that requires people to give the above shown tests to get into, can't produce its own products.
Now here's the last bit, I spoke to you as an Indian talking about openly about the short comings of my country. Given how UA-cam displays my name. There will be people, from my own country, disagreeing with me (which is obvious) and going after me because I do not share the same religion, caste as them. So yeah, education in India is only about these equations. The moral values of being a human is absent.
This video means so much to me. I'm an Indian preparing for iit jee. Its so tough. Thank you for making it so easy
How did your advance go
Hi, how did your advanced go
This isn't solving anything. This is applying an absurdly specific, obscure formula.
And we indians take so much pride in it by just applying a formula....
These are very easy questions to be in India JEE exams!! In India class 12 every one knows about these tricks .
Presh talwalkar can you please make a video on one of the paradox (I need it for my maths project) pls?
This isn't even boards level I literally can solve it in 10 seconds just using property of definite integral.
Exactly
Exactly, Even me too...
Me too
India? next time, get something from Ethiopia.
I did that. all were solved with same property
That is one of the coolest integration tricks I've ever seen. Thanks!
In comment section all my brothers who went for coaching for IITs
As expected comment section filled with Indian comments giving him information about jee advanced
I really enjoyed this formula, it's amazing!
a and b are two numbers having the same no. of digits and same sum of digits (=28). Can one be a multiple of the other? a is not equal to b.
This question is asked in 2019 interview of Indian statistical Institute.
It is not possible for one to be multiple of the other. Imagine that a were equal to bm for some m natural. Because a and b have the same number of digits and are not equal, 1 < m < 10. As the sum of digits of a is 28, we know that a leaves remainder 1 when divided by 9. Similarly, b leaves remainder 1 when divided by 9. That being the case, 2b leaves remainder 2, 3b leaves remainder 3, ..., 8b leaves remainder 8, 9b leaves remainder 0 when divided by 9. So it is not possible for a to be any of the numbers 2b, 3b, ..., 8b, 9b. This reasoning shows that m cannot exist.
@@ianmaateus thank you so much sir😊😊
I Would say its a senseical problem rather then difficulty but here what i did to solve this is that
i put a=a1.a2.a3..........an for a1,a2,a3,.....,an as digits of a and b=b1.b2.b3......bn for b1,b2,b3,b4,b5,.....,bn as digits of b as n on both as total digits of both are equal now here suppose ax=b for x an integer and 1
oh it HAS to equal 28? I was just gonna mention 142857...
No. Here is why : 9+9+9=27 < 28, so both a and b are at least 4 digit numbers. Same number of digits implies a/b = single digit > 1 (since a not equal to b) - e.g. 7777 or 6688/3344. So, if sum of digits is fixed (28) and number of digits has to be same, then a has to be equal to b = 7,777 or 4,444,444.
For those asking why the limits of integration have flipped in 5:18
It's because in lower limit, _x=a._ Since _u=a+b-x,_ replacing _x_ to _a_ means that _u=b_ in lower limit. The process is similar for the upper limit; thus, _u=a_ in upper limit.
Thanks !
so, when ever we do a subsitution in an integral where we affect the interval values themself, we need to accordingly change those values?
good to know, i guess
Why cube root of log4
Is remove
@@beastboy7327 x³=u and we need to convert dx to du. [(log4)⅓]³=log4. log3 same as log4.
Thank you!
Never heard of this formula before. If you don't know it, you're doomed.
Indeed. These questions seem to ask "do you know this formula" instead of "are you smart enough to study here".
Antti I would argue that these questions are more of seeing the symmetry behind. Making observations is a key part of mathematics. Noticing different parts of symmetry is valid a test for “smartness”, because if you are remembering the formula for each type of symmetry question, there are so many variations and you probably need to remember a lot of formulas. Rather, seeing the innate symmetry hidden behind all these seeming different questions leads you to discover the question-specific formulas by yourself. I personally solved all integrals presented in the video without knowing the formula before. The first one sqrt(x)/sqrt((6-x) - sqrt(x)) is written in such a way that is almost asking for u substitution u = 6 - x. These questions are blatantly OBVIOUS for anyone with some elementary training with symmetry. And these questions, as a test for the participant’s sense of symmetry, are well-made.
@@Konsistori smart student can make formula instantly
@@Konsistori It has been made into a formula due to the objective type questions in the exam. It's just an extension of the property that integral a to b f(x) dx can be written as integral a to b f(a+b-x).
We are just taught this property and the rest is up to the student in what form they want to remember it.
You are not doomed, the "symmetrical" nature of the integrals is obvious, using a simple substitution is the first thing that comes to mind if you ever seen this idea before. I never seen this formula, and probably the overwhelming majority of students taking the exam didnt either, but the fact all integrals had basically the same structure is an obvious clue.
If they wanted to make the problem significantly harder they would remove the first 2 integrals and leave just the third, that way they wouldnt clue you in that there is a general idea.
JEE Mains leads to admissions in NITs, second most prestigious institution in India, and gives the eligibiliy to write JEE Advanced Exam, which then gives admission in IITs.
This is how all Indian become Microsoft technicians?
Thank you so much.
If only teachers teach like you did, in about 6 minutes...
I would recommend you to solve Jee advanced indefinite integrals questions.
It would be an hour long video for this guy lmao.
You have to first master the chapter functions, 90 percent of engineers can't even find the range of a given function I can bet that
@@saadrizvi6630
They need not either.
When you got desmos, wolframalpha what's the need to be able to find it.
@@bhujiamonster3471 ikr it's like saying 90% of the mathematicians can't calculate the log of 48397 without a calculator lol.
@@Nobody-pv9jt
No mathematican should be able to calculate it. Even with calculator. Its irrational 😅😁
Edit: fixed spelling
I know this one since about 40 years ago, when I was taking the preparatory course for the admission exams for my university in Brazil... it actually works for any function of (sin) and (cos), does not need to be the square root... 😉
These are much simpler which used to be asked in AIEEE. The current JEE mains is much much harder.
Oh yes . This rule is also known to as "KING'S RULE "
@@ashutoshmishra7429 bhai kota me padhe ho kya?
@@BCS-IshtiyakAhmadKhan nahi bhai
Same type of question came in 24th Jan 2023 shift 1, so easy questions also do come :)
Please make more videos on problems previously asked in JEE examination!!
Your mind will blow out after seeing jee advance problem
*plot straight:*
this problem supposed to solve by a high school student (17 year old)
LMAAOOOOOO i was sitting in my coaching (day long) and was kinda tired and my teacher came to me and say do these questions to "relax"
5:29 Don't understand why replace u with x isn't it equal to a+b-x?
Let x=a+b-x
So taking derivatives both side u get
dx=dx
hence there is no harm replacing it .
Only limits of integral changes.. Which actually leads us to proof of it..
I wish I could attach a pic of proof here. :(
The replaced x is indeed a different variable from the x in the first integral. But since you are integrating over these variables, the name of the variable of the integrand which goes from a to b is irrelevant, because it's just about what numbers the variable is running through and what values the integrand has for these numbers.
@@codeRush I think you men dx = -dx
Thanks all i get it now
@@bedo2445 yes
"Solve in seconds"
They didn’t tell exactly how many seconds just to be on the safe side
The trick when to apply this king rule is that you should look for denominator which wouldn't change its value after applying the rule
Like in the question given in video
Frankly i would not like something having to "memorize" the solution (during college). But unless the pattern is so common and has a lot of applications in the real world. But of course this particular one (in video) is pretty cool though!
1:34 from where i come we call it the starter formula because it literally starts every problem solving when you cant think of anything
Just replace x with a+b-x and then add the new eq with the original eq
You are doing really old IITJEE problems try the papers 2012 onwards. You'll get the real feel of what's JEE qs are and the time will also be in minutes per qs on avg.
For the first, just substitute: x = 6 - u and you get an integral which when added to the original integral (I) obviously gives you 2I =2, so I = 1. No formulae to remember. Same for the second problem, where the substitution is: u = pi/2 -x, and 2I = pi/2, so I = pi/4. For the last problem, substitute: u^3 = log12 - x^3, and use the same technique to show 2I = 1/3 * log4/3. This is much simpler and straight from first principles.
Hey Mr.Presh I request you to please solve Jee advance questions
Point
He can solve them easily he is mathmatics major not a big deal for him .
Ashish Ashish bro the jee advanced paper was once handed to an australian scientist and he said he would leave the exam hall crying. I bet this guy can’t solve a jee advanced question in a single try. And really you only have 3 minutes per question so thats basically one try. You can search on web that jee advanced is the toughest exam in the world. And i hope u know the reason
vaibhav vinayaka hehe
He is not your personal tutor.
JEE 2020 aspirants all the best!! ❤
You ain't gonna make it to IIT dear
@@maxmunch925 tu hogya?
@@simarpreetsingh7235 ha
With sin above or cos above give the same result ==> its direct without your formula. But its an elegant formula wich has a very greater domain of aplication. Thanks
JEE aspirants know this question's answer by heart
Gives board questions
Says jee main questions
Talks about getting seat in iits. Really????
(Upper limit -lower limit)/2
take the middle point of a and b as C .. and let x' = a+b-x; So for each x , x{a
Meanwhile being jee aspirint..
I can frame logic in my mind
IT FEELS GOOD
Comeone if you feel good by this.This video is undermining jee standards..I mean these are asked for 2Mark's in boards 12th
As amazing this technique is -- how useful is it? It depends on the limits of the integral to be just right, which will be the case... rarely ever outside of Indian math exams. And that's the reason why this formula is isn't known more widely.
Indian math exams have more to do with technique than numbers.....I had a problem where I had to use this formula once, then simplify using the integration by parts method and then again this formula.....so the ambit of Indian maths isn't just limited with using some obscure formula.....
1:40😯Vedantu is world famous
Le jee mains:
Ahh I am bored from this😂
Le jee advanced:
Hold my beer😂😂
When solving such questions u forget all the formula😂
Literally solved it within 10 seconds from the thumbnail, pretty common type of a question if you are preparing for the JEE.
Hi friends
I am from Bangladesh and a aspirant of engineering versity in Bangladesh
I follow physicswala's channel for Physics
Can you guys please help me in finding a math source ???
Thanks in advance
1) This is a basic Integration problem given in NCERT Maths class12, which is the easiest book of 12th grade maths in India
2) By qualifying jee mains u dont get into IIT, if you score good then you will be selected for jee advanced exam after which you get iit if you get enough marks..nearly 1million students appear in jee mains exam,150k in jee advanced and 10k students get IIT.
3)Jee advanced is not a piece of cake, applying and memorizing these simple formulas will never help you in passing Jee advanced, however you may be able to get through jee mains with low marks.
You need to realise the curriculum is different in different countries , SAT was probably the easiest test I've done till date and I've seen people asking strategies for that. Being Indians we are exposed to this and we learn stuff at an earlier age, it's nothing great
@@sumzk For some it is great, for some it isn't. Considering the reasons of my statement to be very simple, I dont want to go deeper in this.
Which Software you use to make this wonderful video ? Please tell me .
Thank you so much. It's gonna help me in upcoming JEE
They don't ask such easy questions in IITJEE.. this problem is just an illustration of a definite integral property.
Mukunth A.G yes it is in 12th ncert
They ask some easy one's and tough ones, so they need not be tough always. They ask really tough ones in jee advanced
For the second integral (say, J) you don't need the formula. Just set x = Pi/2 - t and you get 2J = Pi/2.
For the second integral, some people might like to evaluate it;
at 0: 0/(0+1)
at π/2: 1/(1+0)
at π/4: 1/2 , sine and cosine equal
at π/6 (30 degrees) and π/3 (60 degrees) it's more difficult
but the second half balances the first half;
so, I could just about believe that the answer is 1/2 times π/2
It was a reminder to me that anything can be approximated term by term which, with the complications of integrals, I might forget.
(After I wrote this I tried to approximate one of Michael Penn's integrals and saw how difficult that can be.)
I thought People saying my child is studying in Foreign means. He is a Intellectual. But, Wait. I solved before he even see this question.
Replace x with a+b-x and add them
Can you feel true terror with the indefinite integral?
this: Yes
If you can't do it , it means you are not Indian . #NCERT_ jindabad I am also able to do it in seconds..😂😂
This standard practice question from 12th. Not IIT-JEE.
This rule is called KING RULE
he said precursor to the exam which will give you admission in iit....precursor
In the proof, why do a and b flip in the integral?
Actually the denominator was raised to the power 5 in the second ques in IIT test
Amazing ! I've seen many problems like this but don't know how to solve
As an Indian who is going to give jee advanced these questions are too easy for jee mains
An integral property can be used to solve this in second
These questions are a piece of cake for jee aspirants
Not exclusively jee mains but 12th ncert
em...if i only have 1min to solve this, i would give the answer as half the integral of 1 considering the symmetry. it doesn't take more than 5 seconds.
Kindly check up problem 3 there seems some error as the limit as 3 root of Log 4 and log 3 be requiring the alpha value.
this is exactly that knowledge which is the most superfluous to know. Indians have talent in that (knowing superfluous knowledge)...
So... The test checks if you know the formula?
A useless test that even the best scientist might fail. It doesn't proof you're good.
No man. It falls under an illustration of application of one of the properties of Def. Integrals. It's not even a JEE problem. There are 2 JEE papers, first Mains, then comes Advanced. Mains selects 220K students out of 1.2 million on the basis of their knowledge of what the question even is, and what approach could be used. Advanced selects 10K out on the basis of sheer talent, knowledge, and problem solving skills. To rank in advanced one needs almost 2 years of major level studies beforehand even getting into a college.
I agree though. Jee can't assess brilliantly one's curiosity, imagination, or talent. It gives hard conceptual probles to assess how a student prepared for Jee. For the great number of applicants and only 10K seats, the paper has to be ridiculously tough. IITians hence may not be talened or heck may not even be curious. It's absurd I agree.
Lol this need no formula, you have to make one I did this problem in my 1st attempt!
Jimmy Scionti are u mad or what???? If u have a good mind and u don’t use it in a right way then what’s the point of having an intelligent mind. This test checks not only your hard working skills but also how intelligent u are since all the questions have a trick involved .So it proves that u are good . BY THE WAY U WROTE THIS COMMENT I CAN CONCLUDE THAT U ARE A PERSON WHO DOESNT KNOW TO USE HIS MIND PROPERLY AT ALL
Simply countercoupled existence.
Sir this is the king's rule of definite integration and as a matter of fact there is one problem from this property appearing every year or at least in consecutive years in our JEE ADVANCED Exam.
9 views
But 12 likes
DRUNK UA-cam 💥💥
refresh button:am i a joke to you?
Poor Joke
what a beautiful formula
This method is known as kings rule
Hi friends
I am from Bangladesh and a aspirant of engineering versity in Bangladesh
I follow physicswala's channel for Physics
Can you guys please help me in finding a math source ???
Thanks in advance
You have literally picked up the easiest integrals in JEE mains which doesn’t even get you into IIT it’s just a pre cursor to qualify for the actual IIT exam and remember it’s the easiest question on a test kuch easier than IIT JEE advance
I'm watching this channel for entertainment purposes. I don't understand much of what you say, but it's awesome.
I don't think this level will be asked in jee main since when i saw that i also solved it in 10 sec in my mind.
I remember having this problem in class 12 calculus
This technique is known to many iit aspirants, iit entrance still throws surprizes in its exam. One of the toughest exam I would say
So that's really the problem of how hard math shouldn't be. Given enough time, most bright student can work these out, just gonna take quite a few amount of time to figure out, but then it doesn't really help with the overall knowledge or actually make the student more proficent and knowledgeble at math. These type of gimmicky question should just be took as fun challenges tbh.
It is so easy that my driver solved it in seconds
Less than a sec.... 😎 INDIAN hai bawa koi majak nhi hai 😎😎😎💪💪💪🤓🤓🤓
I am an IITian and I am telling you guys that we used to solve these kind of integrals in our minds in seconds.
so? you literally just need to know the technique he used to solve it. there is little intelligence and ingenuity in that.
@@qwertyuiop2161 it not like just remember the formula you are good to go, no, I personal solved integrals of 2 notebooks fully to actual get the skill of solving in seconds. It is skill that you get only by practicing.
You should compare out jee advance exam not jee mains.
I'm saving this videos just in case I need it when I go to college next years
I solved all the three question in mind itself. 😀😀😀😀
u = a + b +x , why at 5:26 u = x ???
I GOT THIS QUESTION IN JEE MAINS IN MARCH SHIFT WHICH WAS FINALLY GIVEN AS BONUS!! AS OPTIONS WERE INCORRECT
Easiest question in This channel 👍
I literally looked at the progression bar to check how long this video is, so that i wont spend my time learning how to use a calculator...
I am solve this in 10s via properties of integral this q from 12th ncert