This video was literally my lightbulb moment for understanding crosswind components. I’m not a student pilot yet, but I love watching aviation videos, and crosswind components have always confused me. Thank you!
I like the fact that we can grasp the concept without need of any calculator or mechanical device! The example she used is quite literally the foundation and origin which the e6B computer and mathematical formulas for creating computerized calculations was probably derived from. This is teaching on the highest level....the theoretical level of Math and Physics in calculating crosswind component!
I get everyone of these problems wrong. My error seems to be right in the beginning: how are you getting the 40° and 20° angles? Just a guess? If you don’t get that right, you mess the entire problem up, which I do!
How do I find the maximum wind velocity I’m so confused by This question Determine the maximum wind velocity for a 45° crosswind if the maximum crosswind component for the airplane is 25 knots please help!
Airplane is good for 25 knots crosswind - so start with x axis 25. Keep going up from there when you hit angle of 45 degree. They will cross arc of 35 and hence your answer. I may be wrong but if your answer matches, this is how you find it. See the chart carefully there are 4 things going. Angle between runway and wind which is way out from 0-90. Arcs are wind velocity in knots. Crosswind component is part of the wind which will hurt the plane and will be lower than total wind speed. Headwind is other component of the wind, which is good for flying the plane. So we should be worried about cross wind only as straight headwind is a good thing and helps us flying. Hope this helps. I may be wrong. Read and think yourself too.
Thank you for the clear explanation without all the jargon that makes it confusing for us students:)
This video was literally my lightbulb moment for understanding crosswind components. I’m not a student pilot yet, but I love watching aviation videos, and crosswind components have always confused me. Thank you!
What a smart and up to the point pilot. Thank you ! Your instruction got me through my A&P training and currently through my private
Wow. The 2nd example just opened my mind how crucial it is to know this math. Thanks again.
I like the fact that we can grasp the concept without need of any calculator or mechanical device! The example she used is quite literally the foundation and origin which the e6B computer and mathematical formulas for creating computerized calculations was probably derived from. This is teaching on the highest level....the theoretical level of Math and Physics in calculating crosswind component!
Cyndy because of your videos and the way you explain in detail I passed my private pilot last week thank you
Did you go further than a PPL?
@@thepenmen22 not yet I Purchased a Comanche 250
I’m currently adding a glass cockpit of Garmin avionics and I’m scared to death of the written test LOL
@@stevenovi7093 Oh that's awesome, nice! The written for your instrument rating? Or what's the plan? Either way, cool! Thanks for the update!
Your explanations are so good and helpful! Thank you for all your videos.
This reminder was needed!
Simple and clear explanation!
Finally this makes sense. Thank you
Love your videos. Super helpful.
Great video. Thank you much!
Yay. Thank you. An explanation I finally understand. ;-)
Very useful vid! My light bulb as moment as well! Video camera is a 1980's era VCR? ;)
Thank you so much! Captain
Awesome 👍
Thanks Alot it was great help information
your videos are the BEST! thank you very much
I get everyone of these problems wrong. My error seems to be right in the beginning: how are you getting the 40° and 20° angles? Just a guess? If you don’t get that right, you mess the entire problem up, which I do!
Very good,
How do I find the maximum wind velocity I’m so confused by This question
Determine the maximum wind velocity for a 45° crosswind if the maximum crosswind component for the airplane is 25 knots please help!
Airplane is good for 25 knots crosswind - so start with x axis 25. Keep going up from there when you hit angle of 45 degree. They will cross arc of 35 and hence your answer. I may be wrong but if your answer matches, this is how you find it.
See the chart carefully there are 4 things going. Angle between runway and wind which is way out from 0-90. Arcs are wind velocity in knots. Crosswind component is part of the wind which will hurt the plane and will be lower than total wind speed. Headwind is other component of the wind, which is good for flying the plane. So we should be worried about cross wind only as straight headwind is a good thing and helps us flying. Hope this helps. I may be wrong. Read and think yourself too.
thanks for the video :-)
Very kool.
Lovely
great but if you just mentioned an example to show us when we consider the wind has a tailwind it will be fantastic for a beginner needs to learn
Best videos
Checking this against sin and cos methods reveals a discrepancy. For the first one I get a cross at 11.5 and head at 13.7.
I did not understand should give simple exemple
I love your teaching skills, but whatever room your talking in makes you slightly difficult to understand. Like a barrel or a room with bad acoustics.
I will like to meet her and kiss her😂😂😂 thanks you so much
Videos quality bad