Linear Algebra: Norm

Поділитися
Вставка
  • Опубліковано 6 сер 2024
  • In this video, we discuss the idea of Norm and how it relates to vectors.
    00:00 - Introduction
    00:12 - Definition of Norm
    02:11 - Properties of Norm
    05:45 - Unit vectors
    07:00 - Example 1
    08:14 - Example 2
    09:12 - Example 3
    10:00 - Normalization
    12:51 - Example 4
    16:18 - Unit vector and direction
    17:59 - Example 5
    22:34 - Example 6
    28:36 - Norm interpreted geometrically

КОМЕНТАРІ • 41

  • @rudolfmosoma9364
    @rudolfmosoma9364 5 місяців тому +3

    Short and simple.. You such a great teacher, wonder if you will be assisting with Stats and Discrete Mathematics 😭😭

  • @pinkkitty6553
    @pinkkitty6553 8 місяців тому +3

    fancy way of saying magnitude of vector, thanks that cleared a lot of doubts.

  • @sinajalali8974
    @sinajalali8974 Рік тому +1

    Well explained. I understand it now. Thank you

  • @rishiraj6602
    @rishiraj6602 11 місяців тому +2

    Very clearly explained, thank you :)

  • @mixerbd791
    @mixerbd791 2 місяці тому +1

    Nice explanation and presentation.
    Thanks Sir.
    Love feom Bangladesh.

  • @Mohammad_alhayajneh
    @Mohammad_alhayajneh 2 роки тому +9

    Thanks alot bro ,you are explain it very smooth and easy ,i appreciate your effort ❤

  • @enass.muhammed7469
    @enass.muhammed7469 2 роки тому +1

    Thank You so much, you have a unique and organized way in explaining the subject!!!

  • @vincentmudimeli4430
    @vincentmudimeli4430 2 роки тому +2

    man your lesson make maths especially complex concept like matrx look easy thanks keep the good wwork going

  • @memit0
    @memit0 8 місяців тому +2

    Thank you broski you are amazing!!

  • @hayyan_azzam
    @hayyan_azzam 9 місяців тому +5

    i pay so much for uni just to find better explaination on yt for free, thank you

  • @garnikmikayelian4271
    @garnikmikayelian4271 5 місяців тому

    Thank you so much, everything was very clear. You really helped me ✍️✍️

  • @bilecode8114
    @bilecode8114 2 роки тому

    Great guy!. you must be appreciated buddy.....

  • @EngrSajeed
    @EngrSajeed Рік тому +1

    God bless you you deserve likes

  • @yufeiliu1596
    @yufeiliu1596 2 роки тому +1

    thanks a lot

  • @Mar1lyn02
    @Mar1lyn02 Рік тому +1

    Sucks that, this video is watched too few. Thanks for the good effort mister!

  • @MathwithWaqasShah
    @MathwithWaqasShah 2 роки тому +1

    nice lecture sir .

  • @manav11142
    @manav11142 3 роки тому +3

    How to imagine an n dimensional triangle? To apply the pythagorus thm

    • @MathforThought
      @MathforThought  3 роки тому +1

      You just take the square root of the difference of each component square.

  • @ghassanebrabish8255
    @ghassanebrabish8255 2 роки тому +1

    Hey man so for Ex 6 why point M would not just be equal 2/5*(PQ)?

    • @MathforThought
      @MathforThought  2 роки тому

      M is a point. Not a vector. It doesn't really make sense to say a point 2/5th of the way. You could say a direction vector is 2/5th of the way though. M as a point has to be in reference to something in order to make sense of which way it's going.

  • @-mwolf
    @-mwolf 3 роки тому +2

    So I saw the norm definition of ||x|| subscript p = sum of all x^p and then taking the pth root of that. Could you explain what the p stands for? Is it the norm in higher dimensions?

    • @MathforThought
      @MathforThought  3 роки тому

      Sorry could you point out where I did that? I can't find the timestamp.

    • @-mwolf
      @-mwolf 3 роки тому

      @@MathforThought No, you only did it in this video with ||x||2 = ((x1)²+...+(xn)²)^½ . I was just wondering what it means to have e.g: ||x||3 = ((x1)³ +...+(xn)³))^⅓ But I guess it's just the norm of a vector in a higher dimension? Would have been cool if you mentioned that.

    • @MathforThought
      @MathforThought  3 роки тому +2

      @@-mwolf Ahh I see what you are saying. I didn't use p anywhere in the video but some people do use p as a way to refer to the dimension of the norm yes.

    • @-mwolf
      @-mwolf 3 роки тому

      @@MathforThought Thanks!

    • @pipertripp
      @pipertripp 2 роки тому +2

      the Euclidean norm is the "2 norm" and is part of a more general class of norms call "P norms" where:
      ||v|| = (sum i=1 to n: abs(v_i)^p)^(1/p)
      sorry if that's hard to read. The "dot product" that everyone learns in first year physics is the Euclidean norm. The "1 norm" is just the following, based on that formula I wrote above:
      ||v||_1 = abs(v_1) + abs(v_2) + ... + abs(v_n)
      the underscores are subscripts and the carets are super scripts. I hope that that was useful.

  • @derjemand1021
    @derjemand1021 2 роки тому +1

    thanks

  • @user-bq8ng1fi5b
    @user-bq8ng1fi5b 8 місяців тому +1

    perfect

  • @Goat_Dips
    @Goat_Dips 3 роки тому +4

    A piece of advice: if you're going to do word problems as in 19:25, have them written down beforehand. That would slightly save students' time. Thanks!

    • @MathforThought
      @MathforThought  3 роки тому +3

      Thanks! I didn't do it initially since I didn't know how much space I needed ahead of time.

    • @-mwolf
      @-mwolf 3 роки тому +7

      Just fast forward 5 seconds for as long as he's writing

  • @Tareq--ri6qe
    @Tareq--ri6qe 2 роки тому +1

    ❣️

  • @YohanesZakariasRadjaHedo-mr9rj
    @YohanesZakariasRadjaHedo-mr9rj Місяць тому

    Sudah....

  • @iqramushtaq2461
    @iqramushtaq2461 11 місяців тому

    What is the norm of X=[1+1+1+1,,,,,,,1]

    • @MathforThought
      @MathforThought  11 місяців тому

      You just square root each component squared.