Great video, thanks! Just one question: at 3:55 top right hand of screen your aldehyde has CH2 where it was previously CH3. Wouldn't it still be CH3? If not, please could you tell me where that hydrogen went?
When there is an internal Alkyne you will get an OH and H addition on both Carbons that are triple bonded. These will be reduced to alkenes with alcohol groups. This is called an Enol. The Enol will be an intermediate which tautomerizes to a ketone on either of the Carbons which were involved in the triple bond. So you may get two products with ketones that have different side chains or with a symmetric side chains you will get 1 product.
this is great, but can you show the mechanism with hydroboration please?
Great video, thanks! Just one question: at 3:55 top right hand of screen your aldehyde has CH2 where it was previously CH3. Wouldn't it still be CH3? If not, please could you tell me where that hydrogen went?
Thank you! That was very helpful!
thank you for these videos
Can't it form keto product after the first enol?
Thank u 😘❤️😊 very much 😊 very much 😊😘😊😊😊😊 good explanation 👍😁😁👍😊😁😊👍😊😊😊😊😊
Thank you so much I'm cryinh
Thank you!
What about non-terminal Alkynes, I can't tell where go add the H or OH.
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When there is an internal Alkyne you will get an OH and H addition on both Carbons that are triple bonded. These will be reduced to alkenes with alcohol groups. This is called an Enol. The Enol will be an intermediate which tautomerizes to a ketone on either of the Carbons which were involved in the triple bond. So you may get two products with ketones that have different side chains or with a symmetric side chains you will get 1 product.
In non terminal alkyne... Ketone will be product...
Bahi samaj nahi aye
plz do not like up contents with last video
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Mechanism???!!!!👹🤬🤬