Also, yes! The audio is intentionally not stereo for this one. Still testing out some new setups with this channel. I hope it still sounds great and you can find it just as relaxing 😊
thank you so much dido!! i have been struggling with line/linear equations at school so i look forward to relaxing to this and also using it as a study tool😂great timing!!!
Unfortunately not. The question asks us to find the x co-ordinate to the point P which has y value -4 on the line y = 2x - 3. To find x we substitute the value of y in our point into that equation and solve for x as it will help us find x at that point. We also add 3 to both sides first to reduce the need for weird fractions. Dividing by 2 first would give us -2 = x - 3/2 and then we would have to add 3/2 to both sides which is slightly harder than doing it the way I did it. Still works but just harder! Hope this made sense 😊
Hi dido, for the lower bounds questions its not really specific to gradients. It basically wants you to find the lowest number the gradient could possibly be from the numbers given which were rounded to 2sf for example the lowest number that rounds to 4.8 would be 4.75. you basically want to make the gradient which is 4.8/5.3 the smallest it could be so picking 4.75/5.35 as the numbers that were rounded would give you your lowest bound which is always < the gradient. Its a strange type of questions that i never liked at gcse and you also have to be careful as 5.35 wouldn't round to 5.3 but its about picking the first number that wouldn't round since you cant pick 4.34999 and then saying that the bound is not inclusive of this number hence the
![[ASMR] Solving Algebra Problems 📚 ASMR Maths](http://i.ytimg.com/vi/O2RP3W9ZoYE/mqdefault.jpg)
Also, yes! The audio is intentionally not stereo for this one. Still testing out some new setups with this channel. I hope it still sounds great and you can find it just as relaxing 😊
This audio is alot better i dont like the stereo at all
@@BlackMan666 interesting 🤔 glad you liked it nonetheless 😊
me waiting for complex analysis asmr, jkjk. I'm happy with any type of math asmr, very dope!
Oooh I could give it a go 😄
thank you so much dido!! i have been struggling with line/linear equations at school so i look forward to relaxing to this and also using it as a study tool😂great timing!!!
Hope this video can help not only with relaxing but understanding some problems too 😅
thank you!!!
Could you make a video solving probabilities and the binomial theorem stuff??
Lots of love Dido ❤
Sure thing!
@@ASMRMaths thank you 😁
love doing these alongside you !
Link to the full sheet is in the description!
question 1 ) cant u shift 2 on the left making it -4/2 + 3 = y ... making y =1 ?
Unfortunately not. The question asks us to find the x co-ordinate to the point P which has y value -4 on the line y = 2x - 3. To find x we substitute the value of y in our point into that equation and solve for x as it will help us find x at that point. We also add 3 to both sides first to reduce the need for weird fractions. Dividing by 2 first would give us -2 = x - 3/2 and then we would have to add 3/2 to both sides which is slightly harder than doing it the way I did it. Still works but just harder! Hope this made sense 😊
I was doing those lines in coordinnate plane and didn’t understand, but now I uderstand it a bit better
I’m glad you understand it a bit better now ☺️
Hi dido, for the lower bounds questions its not really specific to gradients. It basically wants you to find the lowest number the gradient could possibly be from the numbers given which were rounded to 2sf for example the lowest number that rounds to 4.8 would be 4.75. you basically want to make the gradient which is 4.8/5.3 the smallest it could be so picking 4.75/5.35 as the numbers that were rounded would give you your lowest bound which is always < the gradient. Its a strange type of questions that i never liked at gcse and you also have to be careful as 5.35 wouldn't round to 5.3 but its about picking the first number that wouldn't round since you cant pick 4.34999 and then saying that the bound is not inclusive of this number hence the
I aint reading allat
Could you maybe do a video for the ACT? A lot of students like myself will be taking it and I’d love to be able study by visiting your channel
That sounds like an awesome idea!
thank you Dido! can you consider doing differential calculus? thank you so much ❤
You should do a series where you teach something new every week! (So like a math teacher)
enabled!
😂😂😂 Pls not here too!!
@@ASMRMaths you cannot escape
can you make a video related to exponential also great asmr dude
I'm a bit confused Duncan mate, why wouldn't you just screen record the content on ur iPad , in conjunction with the ASMR sound?
*Promo sm*