Differentiation : Implicit Equations (Using the Product Rule) : ExamSolutions
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- Опубліковано 5 кві 2010
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Because I was differentiating the 3x^2 with respect to x not the y^4. You only do that when you differentiate a function of y with respect to x.
Thank you so much Sir, you're the best!
@ObviouslyRyan That's good. Thanks for your comment.
Damn old but gold thanks a lot sir!
Thank you for this tutorial.
you have helped me so much during GCSE and now my ALEVELS thank youu.
That was great, thank you so much.
Thank you this helped so much
@naruto2710 Yes, but I always suggest multiplying both sides of the equation by the fraction and therefore remove the option.
you've shown how chain and product rule can be incorporated with implicit differentiation. can quotient rule be used also?
cheers mate
Thanks G
@pinkette4gd Thank you for your support.
how did you find the common factors??
Subscribed.
Its a nice video keep it up sir , thanks .sir we can i get ur past exam papers
It won't help you now, but for anyone else looking, they have exam questions in each topic here: www.examsolutions.net/a-level-maths/edexcel/c4-tutorials/#diff and you can get past papers from your exam board's webiste.
2:50 ...... (3x^2)(4y^3) dy/dx + (6x)(y^4) why didnt you add dy/dx after (y^4) as well or why didn't it go there rather than after 4y^3. thanks
8 years later i have the same doubt
Whats the derivative of 2y?
If it is with respect to y then it is 2. If it is with respect to x then it is 2 dy/dx
When doing the product rule why didn't you have to write dy/dx for (6x)(y*4)?
Wait, was it because, for that part, it was the x term that was differentiated?
That is correct.
+ExamSolutions awesome thanks!
ohhhh, was hoping somebody asked that question still
dang didn't expect you here
Will we lose mark if we don't completely factorise? Ex. That last part I left it as 2+ 12x^2y^3 whereas you done 2(1+6x^2y^3)
I would doubt it. However, factorising is always a good habit to look for as it can often simplify things.
I have got the same answer but with opposite signs ! Does it matter ? Thank you
+العنود محمد Can you write down your answer and I will be able to tell you.
+ExamSolutions
So I've got dy/dx = (6xy^4-3x^2-5) / (2(-6x^2y^3-1)) it's the same but the signs are different
+العنود محمد That's okay then. If you multiply top and bottom by -1 you will then get my version. The reason you got your version I suspect was that you collected the dy/dx terms on the left hand side as opposed to me collecting on the right hand side.
ExamSolutions cool .. Thank u ^^