Finding Stationary Points for an Implicit Equation : ExamSolutions Maths Tutorials
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- Опубліковано 12 лют 2013
- Tutorial on finding stationary points for an implicit equation.
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Advanced info says this is on the paper in about 3 hours, lets pray aqa clutches up
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This helped so much! Thank you :D
ok thanks. just needed to clarify. i havent done maths in quite a few years so this helps a lot. Thank you very much :)
Wow thanks sooo much this reallyyyy helped me
if a questions says "show that y^3+12xy+16=0 has no stationary points" what am i supposed to do
i'm not sure which values i should use to calculate the discriminant because it's an implicit equation
Thank you
anything divided by 0 is undefined not 0
a/b=0 if you multiply both sides by b then a=0.
are you supposed to take dy/dx to left hand side or right hand side , they both give different answers
It doesn't matter. You should get the same answer if you take dy/dx to the left or to the right-hand side of the equation.
Many thanks for all your videos. I do get confused when at 6:45 when you start tidying up, why (2y)^2 becomes 4y^2 though. Please you you explain?
E Newham 2y x 2y = 4 y^2
but why not a/0=b :. b=0
At 7:03 of the video,i thought the equation was 5y^2= - 20.
How did the 20 become positive?
I added 20 to both sides so 20 = 5y^2 then switched it around.
ExamSolutions Thanks
sorry just to double check, why do you equate the numerator to 0, and not the denominator
If you set the denominator to zero then finding any solution becomes impossible as anything divided by zero is undefined. It'll become basically an infinitely big number that isn't or cannot be defined.