Calculus: Differentiation of natural log functions : ExamSolutions
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- Опубліковано 18 бер 2009
- See how to apply differential calculus to differentiating natural log functions. Check out more videos like this. • Differentiation (1)
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Are the maths videos of 2009 really helping? Yes.
IKR? and some people expect you to pay...
*What?* Still searching youtube for maths help?
wel..-skip
Thanks - comments like this always give me encouragement to continue with the project
Thankyou dearly for the clear, concise and informative explanations:)
+poino11 I appreciate your comment. Thank you.
Cannot thank you enough, finally beginning to understand this.
Alexis Quintana Good
Stick at it and you will get there - good luck.
By far, one of the best maths channel on the net.
Wow! everyone else made this sound way more complicated than it truly is.
Thanks!
Aaron
A donation is always appreciated to help with running costs.
you were more informative than my math teacher that took 2 hours to explain this concept
i'm really struggling on my integral calculus.. lucky i found this video saves my day.. thank you soooooo much. :)
I, (we) use the standard results when we differentiate a single term, such as ln x, ln t, ln p, ln q etc. So the chain rule is used when we have ln (several terms). Making y=ln(t) allows us to find dy/dt and then this is used to find dy/dx via the chain rule.
@Jessycar1BrumBeep From the teaching point of view, it is important to understand where the formula dy/dx = (f '(x)) / (f(x)) comes from. I often find a lot of people do not know this and this was the point of the exercise. Thanks for your comment though.
Excellent explanation. Thank you.
So easy to understand.. Thx for the help!
Excellent explanation. Thank you for your videos.
I have watched numerous of videos on youtube about math, and this was the first one I actually came away totally understanding it
Thank you so much in helping us to learn maths for free. Thank you very very very x100000 much !!
Herwin Ng You're welcome
I dont know how these video havent gone viral
very helpful explanation. just what I was after. thank you.
thankyou so much , you're an amazing human!!
Ur Tutorials are great..Great Work..
Thank You for making this! it's brilliant, because now i am able to understand it better. :)
OMG!! thaank youuu sooo much i understand it from your explanation
this is very in valuable. thanks man
Thanks you helped alot!
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brilliant explanation sir
Old UA-cam videos are more helpful than my maths lecturer 😪
Glad you like them!
Thank you!
U r one of the best maths teacher so far.thank you so much for clearing out my confusion.I hope u keep going.
I hope to keep this going. Thank you for any support
@sweetrawker You are welcome
You are a god send man!
year 12 student, understood it very well, ty for the help
Fab !! tysm :)
The standard results are used. Differential of ln x with respect to x is 1/x. The differencial of ln z with respect to z would be 1/z, the differential of ln t with respect to t would be 1/t and so on.
Bruhhhhh you made this seem sooooo easy!!!!!
love it.....
thank you so much! it helped me a lot =)
very good teaching thankyou
Lovely explanation, went right over what I needed.
Cracking video Jeff
This is so awesome..Thanks. I've been trying to understand this for days but this video simplified all that in minutes.....ha.haa N the acsent too is clear which improves concentration
thank you very much sir
Thank you! Need to rewrite my notes now but I've finished C3... that's 1 out of 7 exams I'm sitting this Jan I've covered the unit entirely for. And 1 out of 7 I can start past papers on :) Owe it to you!
it's an amazing video it really helped me
cooooooooool thanxx a lot
I got an A in maths thanks to you. Thank you!!!
Congratulations and thanks for any support you give to help me keep this going.
+Wendy Ydnew hey i wanna get an a just like u, i just want to know ur revision routine, what u did, it will be really helpful
+ExtremeTG I watched these UA-cam videos and may a few notes.. did a load of pastpapers
Wendy Ydnew and what do you think would had help you move up to an A*
+ExtremeTG To get A* you need 90%+ in Core 3 and 4. I think I should of done more work in applying my knowledge rather than learning facts. Definitely dont just do AQA past papers, but also try Edexcel and Ocr
Took Calculus I last semester. My Business Calculus final is in 2 hours. Thanks for refreshing my memory. :)
@pimpmymail No it applies to any composite function f[g(x)]
u are very good in teaching! keep it up! love ur videos :)
make dua.
Great explanation, struggled with this in class
Pleased it helped. Best wishes
Pleasure
@awesomelydee Hopefully but please remember that this is all done in some of my spare time and so I cannot guarantee this.
y=ln(x^2-1)^1/2
Really helped on others, but then i came across these
damn nice! u helped me a lot!
Cheers
Thank you so much
You're welcome, thanks for watching and supporting this work.
Thaaaaaaaaaank you so much
Most if the comments are from years ago. i hope you are all doing great!
Yep, and I am doing great.
@MrValzen when you have a log function to the power of something you take the power and multiply it by the log.
e.g. y=ln(x^2-1)^1/2=1/2ln(x^2-1)
dy/dx=x/(x^2-1)
@milaad123 Thank you
@TimothyGregoryMusic Pleasure
I have donated a small amount (tbh, not as much as the site is worth at all), but believe me I'll donate again in future.
could you show how to differentiate 2^(cotx) and x(5^(3x))
@BintuHurairah Cheers. good news.♠
how would I workout f(x)=7x-4 where f(x)=x I know the answer is 2/3 but how do i get to that answer?
Where does the ln go?
the last minute in the video scared me for next term..
Hi .Ive been figured out quite long time to solve it . do you know how to do it .
e^3ln x = 27 /8
can you show the workinng to get the answer
x=3/2 i think
Use log rules to bring the 3 into the lnx giving e^ln x^3=27/3
then since e to the power of the natural log of anything equals the thing inside the natural log (in this case the x^3) you'd get x^3=27/8
then cube root to get x=3/2
Can you simplify the derivative for the third question (dy/dx = cos x / sin x) to cot x?
+mmmmmmmmmmnmnnnnnnnn Yes.
+ExamSolutions Thank you!!
cos(x)/sin(x) = 1/tan(x) = cot(x)
what do we get if we differentiate -ln(ln cosx)
(1/cosx) x (-sinx)
=-sinx/cosx
=-tanx
@kiogeedwardkaranja Pleasure
@1029Memory Good luck
the derivitive of sin x is cos x
Found this was great but didn't understand why the differential of ln types are 1 over, so checked out this video here: /watch?v=fmKqJ69YaTk
Cos 32°40' tan9°44} √sin20°19
@manaphy490 A2
very helpful but I have a problem for determining the derivative of y= Sin4xCos5x
(4sin(4x))(-5sin(5x))
saved my ass cheers
dy/xdx= 1/lnx
0:26- equation 1 is different to 2:25.
pretty much dy/dx=g'(x)/g(x)
I dont understand
if u suppose to multiply dy/dt by dt/dx, then 1/(3x^2-1) should be multiplied to same thing 1/(3x^2-1) not 6!
Sorry but I don't understand your question. Maybe someone else can offer help.
multiplying dy/dt by dt/dx does not mean you do that. dy/dt is 1/(3x^2-1) and dt/dx is the differential of (3x^2-1), as we replaced the (3x^2-1) by t. Therefore it should be 1/(3x^2-1) multiplied by 6x. Hope that made sense.
You are a goddamn mathmatical god
what about this qustion -->
y = ln ( 1 / x )
re-write as y=ln(x^-1) which then is y= -1 ln(x)
So differentiating is -1/x
Ohh I see.. Thanks btw!
Not that I am aware of. There are no common factors.
1 person missed the like button and pressed dislike!! :(
brilliant explanation Sir
Thanks! Really helped me out
Good to hear