Outsmarting Rational Equation: Strategies for Success!

Outsmarting Rational Equation: Strategies for Success!
Join us on a journey to outsmart rational equations! In this video, we unveil powerful strategies and techniques to tackle even the trickiest of rational equations. Whether you're a math enthusiast, student, or educator, this comprehensive guide will equip you with the skills to conquer any rational equation challenge. Get ready to unlock the secrets of rational equation mastery and elevate your problem-solving abilities!
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📚 Key Highlights:
Step-by-step breakdown of the solution process
Insights into the unique aspects of the tough rational equation
Tips and tricks for mastering similar challenges
Application of substitution, manipulations and algebraic identities
🎓 Suitable for students, math enthusiasts, and anyone looking to explore the wonders of rational equations. Let's unravel the mystery together! 💡✨
#mathematics #equations #rationalequations #problemsolving #mathskills #mathtutorial #algebra #mathhelp #educationalvideo #mathenthusiast
Timestamps:
0:00 Introduction
0:47 Substitution
1:54 Solving rational equation
4:08 Reciprocal equation
6:10 Factorization
7:15 Quadratic equations
11:26 Solutions
We'd love to hear from you! Did you manage to solve the equation? What other math problems would you like us to cover? Let us know in the comments below!
🎓 Happy learning, and see you in the next video! 🎉
Thanks for Watching !!
@infyGyan ​

[@user-kp2rd5qv8g]

Let t = sqrt(x). Then, 1/[9(t^2+4t)] [4t^4+16t^3+36] = 4/3 > t^4 +4t^3+9 = 3t^2+12t > t^4 +4t^3-3t^2-12t+9 = 0. Note that the coefficient of t is (-1) times 3 the coefficient of the coefficient of t^3 and the constant term is 9. Let us therefore write the quartic expression as (t^2+at-3)(t^2+bt-3) > a+b = 4 and ab = 3 > a=1 and b+3. So, we have (t^2+t-3)(t^2+3t-3) = 0 which in turn gives x+ 1/2[7 +/-sqrt(13)], 3/2[5 +/- sqrt(21)].