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Great. I really love this equation and solution
Thank you🙏
Exciting video
Thanks
Maths is wonderful...Bring forward more such questions
Thank you. I am glad you appreciate our content. I would surely do more of such. Thank you.
I think there is a mistake at the very beginning. When you take square root of both sides. I believe that from then on you should continue with 2 options:((x^3-x)/x!)^2=1 should turn into (x^3-x)/x!=1 and (x^3-x)/x!=-1Is that right?
That's ok. However Factorial values are greater or equal to 0. Working with the -1 would make it complex to deal with.
x_1=5, x_2≈1.38
Great. I really love this equation and solution
Thank you🙏
Exciting video
Thanks
Maths is wonderful...Bring forward more such questions
Thank you. I am glad you appreciate our content. I would surely do more of such. Thank you.
I think there is a mistake at the very beginning. When you take square root of both sides. I believe that from then on you should continue with 2 options:
((x^3-x)/x!)^2=1
should turn into
(x^3-x)/x!=1 and (x^3-x)/x!=-1
Is that right?
That's ok. However Factorial values are greater or equal to 0. Working with the -1 would make it complex to deal with.
x_1=5, x_2≈1.38