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Rash Quanty Maths
Приєднався 8 чер 2024
EXPONENTIAL EQUATION WITH COMPLEX NUMBERS
Learn how to solve exponential equations with complex numbers.
Переглядів: 57
Відео
TaTU Math Olympiad Radical Equation 2x + 2y = 5(xy)^0.5
Переглядів 14619 годин тому
How to Solve Radical Equations Using Indices and Algebraic Identities
Math Olympiad Exponential Equation 8^y^2 2y+2 4^y^2 2y+2=48 P
Переглядів 7414 днів тому
How to solve math Olympiad Exponential Equation 8^y^2 2y 2 4^y^2 2y 2=48. The Application of Algebraic Identity.
Simplify without Calculator (39^3 +19^3)/(20^3 +39^3)
Переглядів 15421 день тому
we tackle a unique algebra problem that involves simplifying a complex fraction: (39^3 19^3)/(20^3 39^3) without using a calculator! Follow along to see the steps and logic required to break down this expression using algebraic identities and clever problem-solving techniques. This method will strengthen your skills in simplifying large expressions efficiently and is perfect for those intereste...
GH TaTU Beautiful Olympiad Maths Problem Solved (6+√35)^x+ (6 - √35 )^x=142
Переглядів 10821 день тому
Join me as we solve a fascinating math Olympiad problem from GH TaTU, featuring the equation (6 √35) ^x (6 √35)^x=142 Using clever techniques and algebraic methods, we’ll break down each step for a clear solution. This is perfect for students preparing for competitive exams or anyone who loves challenging math puzzles. Don't miss out!
MATH 101 Math Olympiad: Solve √71 + 12√35
Переглядів 11621 день тому
In this Math Olympiad tutorial, we dive into solving the advanced expression √71 12√35 using algebraic techniques. Perfect for students preparing for competitive exams or anyone wanting to strengthen their math skills! Follow along to see step-by-step simplification and learn valuable problem-solving strategies.
TaTU Math Olympiad: Solving nonlinear equations for entrance exams. Find (x, y) values step-by-step
Переглядів 34421 день тому
Learn the step-by-step approach to finding (x,y) solutions, perfect for students preparing for entrance exams or anyone interested in advanced problem-solving techniques. Be sure to subscribe for more math challenges and solutions!
Solving an Advanced Square Root Equation | Technical University BSc Math Entrance Exam
Переглядів 19228 днів тому
√(3&(19x 49)/(19x-49))-2/√(3&19x-49)=1 Learn step-by-step how to break down and solve this advanced algebraic problem. Perfect for math enthusiasts or anyone preparing for exams. Don't forget to like, share, and subscribe for more math solutions!
A tricky Maths Olympiad Exponential Equation: x^8 4^x=0
Переглядів 166Місяць тому
we'll be solving the exponential equation x^8 4^x=0; Join me as we explore step-by-step how to tackle this tricky equation and uncover its solution. Perfect for anyone looking to sharpen their skills in exponential equations!
A Special Maths Olympiad Equation |x +1| = |x|
Переглядів 330Місяць тому
we're tackling an interesting absolute value equation: |x 1| = |x| This equation reads as 'The absolute value of x 1 is equal to the absolute value of 𝑥
Simplifying fractional expressions involving numbers in tetration form
Переглядів 33Місяць тому
A step-by-step procedure of Simplifying fractional expressions involving numbers in tetration form
Simple Exponential Equation
Переглядів 177Місяць тому
Step-by-step procedure of solving an exponential equation 4^x 4^x 4^x = 48
How to solve Simultaneous Equations xy =50, xz = 100, zx = 200
Переглядів 66Місяць тому
Solving Simultaneous Equations: xy = 50, xz = 100, zx = 200 | Step-by-Step TutorialIn this video, I'll guide you through solving a set of simultaneous equations: We’ll explore different methods for solving these equations, simplifying the relationships between variables and finding the values of x, y, and z This tutorial is perfect for anyone looking to strengthen their algebra and equation-sol...
GH Simplification of exponential fraction without calculator
Переглядів 25Місяць тому
In this video, I walk you through the simplification of the following expression step-by-step: ((1/3)^7 (1/9)^6 (1/3)^17)/((1/3)^17-(1/9) ) Using algebraic techniques, I'll show you how to break down and simplify this seemingly complicated fraction with ease. Perfect for those looking to master algebra and improve their problem-solving skills! 👍 If you find this video helpful, don't forget to l...
Solving the Tetration Equation ^32^x + 4^x = 6 Step by Step Explanation
Переглядів 95Місяць тому
Solving the Tetration Equation ^32^x 4^x = 6 Step by Step Explanation
Interesting Maths Olympiad Equation x^2 9÷2016 + x^2 6÷2019 + x^2 3÷2022 = 3
Переглядів 162Місяць тому
Interesting Maths Olympiad Equation x^2 9÷2016 x^2 6÷2019 x^2 3÷2022 = 3
A Tricky Exponential Equation 1÷8^x +1÷4^x = 80 Solved
Переглядів 422Місяць тому
A Tricky Exponential Equation 1÷8^x 1÷4^x = 80 Solved
Maths Olympiad GH Tricky Exponential Equation Solved
Переглядів 85Місяць тому
Maths Olympiad GH Tricky Exponential Equation Solved
No Calculator is allowed:- Simplification of (0.25^5 + 0.5^6 +0.25^7)÷(25^7 - 0.5^2)
Переглядів 822 місяці тому
No Calculator is allowed:- Simplification of (0.25^5 0.5^6 0.25^7)÷(25^7 - 0.5^2)
Maths Olympiad Quadratic Equations application
Переглядів 143 місяці тому
Maths Olympiad Quadratic Equations application
logarithmic equations (log x^2)^ 0.5 - log x^0 5 = 0
Переглядів 183 місяці тому
logarithmic equations (log x^2)^ 0.5 - log x^0 5 = 0
GH Solving exponential equation with factorial ((X^3 - X) ÷Xǃ)^2 = 1
Переглядів 5103 місяці тому
GH Solving exponential equation with factorial ((X^3 - X) ÷Xǃ)^2 = 1
Simplification without calculator (555^3 +222^3)/(333^3 +555^3)
Переглядів 2,2 тис.3 місяці тому
Simplification without calculator (555^3 222^3)/(333^3 555^3)
GH Math Olympiad application of difference of two squares
Переглядів 803 місяці тому
GH Math Olympiad application of difference of two squares
GH Fine Exponential Equation Problem Solved
Переглядів 213 місяці тому
GH Fine Exponential Equation Problem Solved
GH Nice Maths Olympiad Equation involving Factorials (y^2+3/2 y)!/3!=5!7! y= ??
Переглядів 363 місяці тому
GH Nice Maths Olympiad Equation involving Factorials (y^2 3/2 y)!/3!=5!7! y= ??
A challenging Math Olympiad problem involving roots equations
Переглядів 213 місяці тому
A challenging Math Olympiad problem involving roots equations
nice
Very good
Thank you.
Thank you sir
You are welcome
Excellent ❤❤❤
Thanks 😊
Very fantastic ❤❤❤
Thank you.
Nice
Graci
It is too complex
I believe you can understand it.
Muy largo, pero es untrabajo de paciencia. ¡Excelente!
Tibi gratias ago pro vigiliis. tuas valde gratum est
Wow! Very exciting
Thanks
Great
Thank you.
My best master from Tatu 🙏
Thank you.
x& y are symtric So (x,y)=(-7,8)
Your contribution is a great one. You assistance is much needed. Thank you Snr.
Thank you.Thats a good one
Welcome
Ineresting
8:19 8:19 ❤
Thank you.
Thank you.
Nice❤
Thank you.
mathematics is alive.
There is application of math in everything.
I love you solution. Thank you
Thank you brother.
This equation be trickish ooo
Really?
I hope you enjoy the solution.
I have enjoyed the video. Keep it up.
Thank you. I would always do my best to give the good tutorials.
Wow! I have really learnt from this videos. I was imagine how the equation would be solved. Thank you for the education. ❤❤
Thank you. I am glad you enjoyed it.
In fact. I have learnt new things from your tutorials. Thank you
Thank you. I really appreciate your time.
Well explained sir
Thanks and welcome
Hello there! You can solve this problem in less than a minute! divide zx/xy = z/y= 200/50 =4. Then multiply the result by zy -> zy*z/y=100*4=z*z=400. Therefore z=20. Now we simply substitute in the second and third equation, which gives us y=5 and x=10. Hence x+y+z=35.
Wow!!! That is great. Thank you for your contribution to knowledge. I really appreciate.
Never knew you were such a genius
Thank you Sir. I am hambled
Great 🎉
Thank you.
Consider complex numbers, there are many other solutions. All -1/2+iK with real y are solutions.
Ok. Thank you.
Splendid
Initially, I thought the question was invalid 😂but I have learnt something new now. Thank you 👌
you are welcome. Please subscribe for more exciting tutorials.
You are welcome. Please subscribe for more exciting tutorials.
Commander.i trust you
Thank you.
The best maths teacher ever, after over 2 decades I still remember this handwriting ❤👍🏽
Thank you. Please subscribe to my channel and hit the notification bell for notification any time I upload new tutorial videos.
X=2
That is correct.
I love this. Thank you.
You are so welcome!
Great job
Thanks
(125 + 8)/ (27 + 125) = 133 / 152
Please I don't get you.
I think there is a mistake at the very beginning. When you take square root of both sides. I believe that from then on you should continue with 2 options: ((x^3-x)/x!)^2=1 should turn into (x^3-x)/x!=1 and (x^3-x)/x!=-1 Is that right?
That's ok. However Factorial values are greater or equal to 0. Working with the -1 would make it complex to deal with.
x_1=5, x_2≈1.38
Great job. I really learned from this tutorials. Thank you.
Thanks for the complement.
Great. I really love this equation and solution
Thank you🙏
Why didnt you kick out 111³ ? Then you would have ended up with 133/152 which 7/8
Great that is a smart way. Thank you I really appreciate your suggestions. Well noted. Thank you.
@@RashQuanty Your welcome, any problem can be solved very complicated. SOmetimes its not easy to recognize the easy way ;)
I agreed with you.
Nothing here is simple and easy to understand. 😆 I completely don't get it at all.
Really. Tell me your specific challenge and I would see if I can help.
Really? Take a critical look at it you can understand it.
factoring each term by 111^3, that is, say, 555^3= [5(111)]^3=(5^3)(111^3), could give the same result much quicker
Great my friend. I really appreciate your method. I would consider using that in future. Your comments are always welcome. Please subscribe to get more updates on our new videos. Thank you
Maths is wonderful...Bring forward more such questions
Thank you. I am glad you appreciate our content. I would surely do more of such. Thank you.
🙏🙏
Great job
Is it possible u add voice explanation instead of the music in de background
Noted. I would do the voice version and upload. Subscribe for free so that when I upload it you would get notifications. Thank you.
Exciting video
Thanks
TAKE 111CUBE COMMON UP DOWN AND GET 133 UPON 152 WHICH IS SIMPLIFIED TO 7 UPON 8.
COULD HAVE BEEN DONE BY MUCH SIMPLER METHOD.
I would be grateful. If you share that with me. Thank you.
@@RashQuanty At start, remove 111^3 from all terms. That leaves (5^3 + 2^3)/(5^3 + 3^3). This equals 133/152, or (19*7)/(19*8). Which = 7/8.
3^m(27-9+3)=189 3^m×21=189 3^m=9 m=2