This video is just perfect, with concise explanation. Now I unerstand well how to find the boundaries. Pleas Sir keep on doing the great job. thank you very much
because is you want to find the volume when triple integrating you use the function 1. If you use a function with variables you will get a hyper-volume which is essentially volume but in 4d, not 3d.
This video is just perfect, with concise explanation. Now I unerstand well how to find the boundaries. Pleas Sir keep on doing the great job. thank you very much
simplest and clearest explanations about triple integrals I've come across so far
Thanks for your comment. We look forward to creating more content for higher level math soon.
Who else was expecting "8" examples? 😂
"you can start with any order, im going to start with y because y not. "🤣🤣. great thinking there
how i wish you could appear in my exam paper like that
For the bounds of y, wouldn't you put x = 0 as well, so it's just 4 - z (like you did with the x bounds, setting y = 0)?
2 years and still no answer.. I wonder if he ever figured it out.
@@thejronny Think I was right but I don't remember. Anyway fuck it cause I'm a software dev now and never use this shit LMAO
Don't see why the bounds for z are 0 to 2 and not 2 to 4. You plug in 0 for x and y to get z = 4 and we are given the other bound of z=2.
If you take the bound of 2 to 4, you get the upper part of the tetrahedron. Bounded by 2 means the space above 2 is cut off
I think the region of integration is the tetrahedron which you removed from top of bigger tetrahedron.
Will be if: x+y+z=4 , plug 2 in x (height of z=2) resulting in y=2, and plug 2 in y resulting in x=2.
Please y is the function 1
because is you want to find the volume when triple integrating you use the function 1. If you use a function with variables you will get a hyper-volume which is essentially volume but in 4d, not 3d.
stupid , worse session ever seen