Double Integrals over General Regions Practice Problems

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  • Опубліковано 1 лис 2017

КОМЕНТАРІ • 39

  • @annalilypearson
    @annalilypearson 4 роки тому +40

    God I’ve looked all over the internet for something that will explain double integral bounds and not a thing helped until I FINALLY found your video. This is exactly what I needed, thank you 🙏🏻

  • @joviyeung1866
    @joviyeung1866 4 роки тому +4

    Thank You for such a great explanation ! keep doing more of these and you will help a whole lot of people. THANKS!

  • @light2990
    @light2990 2 місяці тому

    I've had trouble with this for ages, this video is no nonsense and really helped

  • @alaskan2112
    @alaskan2112 5 років тому +5

    i don't usually leave comments on videos since most of the don't explain anything. but you help me a lot today thanks

  • @ahmadkouis2748
    @ahmadkouis2748 5 років тому +9

    finally someone with short video and great explaining

  • @siphilipe
    @siphilipe 5 років тому +3

    Just a great explanation. Thank you J.H

  • @iskendersefaylmaz4963
    @iskendersefaylmaz4963 3 роки тому +1

    you are really good at problem solving and fast ,thank you

  • @MrWinter2
    @MrWinter2 3 роки тому

    Thank you so much!!! This helps a lot for my class. :) ✨

  • @Graceluvbug37
    @Graceluvbug37 8 місяців тому +1

    This was super helpful, thank you

  • @byt7228
    @byt7228 5 років тому +1

    U are simply awesome. I do not understand why they do not teach us like that.

    • @Literaduranet
      @Literaduranet 8 місяців тому

      because in class no one pays attention. A teacher speaking that fast would be unbearable.

  • @lydianazombe6027
    @lydianazombe6027 4 роки тому

    great video💪

  • @sd-zj2dq
    @sd-zj2dq 2 роки тому

    thanks for such amazing and easy explanation

  • @shivayramrathy8864
    @shivayramrathy8864 Місяць тому

    thanks, king🙏

  • @priyashanthinianbazakan5380
    @priyashanthinianbazakan5380 4 роки тому

    very good explanation. thank you so much

  • @everchann
    @everchann 15 днів тому

    best video, thank you so much!

  • @AMtothePM600
    @AMtothePM600 Рік тому +1

    Nice job. Deserves more likes

  • @tiomemo8958
    @tiomemo8958 Рік тому

    best channel thank you

  • @user-qt1dy4tb8f
    @user-qt1dy4tb8f 2 роки тому

    Perfect explication thanks you soo much 💞💞

  • @famzsamir3244
    @famzsamir3244 4 роки тому +1

    step by step in your explanation..

  • @ladyanne4294
    @ladyanne4294 5 років тому +1

    hey thank you from uganda

  • @mohamedfadll4827
    @mohamedfadll4827 2 роки тому

    Thanks alot ❤️

  • @fgfjfjf3
    @fgfjfjf3 3 роки тому

    wow , thank you 1 million time

  • @valeriadevlog
    @valeriadevlog Рік тому

    Finally got what i wanted

  • @rohitpratapnair2260
    @rohitpratapnair2260 3 роки тому

    Nice😍

  • @mechtarin
    @mechtarin 5 років тому

    Thank you

  • @motb5182
    @motb5182 5 років тому

    Thanks alot

  • @nezokuchan9577
    @nezokuchan9577 4 роки тому +1

    Thank u so much 😍😍 but I had question why in the last problem in 9.42 the function that u integral is y+1-(x²+1) ???

    • @akhilkumar3090
      @akhilkumar3090 3 роки тому

      I have the same question, i think its bcoz we already have dx and dy terms, so we need some kind of dz

    • @JPL454
      @JPL454 Місяць тому

      @@akhilkumar3090 The volume is given by the integral of 1, the integral with respect to z goes from x^2 +1 to y+1 so he basically skips that step and alredy gives us that expression

  • @hassanali-ii8yx
    @hassanali-ii8yx 3 роки тому +2

    you must explain how you have drawn the surfaces z=y+1 and……
    so this is not math

  • @zahidhissam419
    @zahidhissam419 3 роки тому

    how did you get the limit 33 to 1 ? can someone explain to me?

    • @Furfur-rj2tw
      @Furfur-rj2tw 3 роки тому

      Because U = y^5 + 1
      So the integrals with respect to U are
      (1)^5+1
      And
      (2)^5+1
      Because before it was with respect to y now it it was with respect to U , and U equals the Y value to the power of 5 plus 1.
      So you just substitute the Y integrals you had and you will get the U definite integrals.

  • @felipe60395
    @felipe60395 Рік тому +1

    hamblin hamblin mcgill

  • @davidukpabi1173
    @davidukpabi1173 Рік тому

    😊😊😊😊😊😊😊ppppppm

  • @davidukpabi1173
    @davidukpabi1173 Рік тому

    P

  • @jafaralturfy5053
    @jafaralturfy5053 3 роки тому

    Thank you