I am having trouble in my advanced calculus class (which is sort of a hybrid of intro to real analysis and calculus 3? weird course that is currently some number theory, set theory, some topology, and some things that i havent had any experience with in the past, which this helps with so thank you!)
Would a point still be an interior point if it reaches a point not in the set? for example let's say in the example set we use 3 as the point, if we "stretch out" we reach 4 which is not in the set, would the 3 then be an interior point?
Interior points of A just need to have *some* reach-out radius that only touches points of A. So yes, a reach of radius 1 from x=3 will touch 4 which is outside the set, but a reach of radius 1/2 will *only* touch points of A and that is enough to say 3 is an interior point of A.
I come from Vietnam and this is a great way to learn Math. Thank you professor Matthew
Thank you so much! Your explanation is so clear that I can understand all of them!
Love these videos! Many thanks for these. 😃
You save my master degree, thank you sir.
This video is really helpful thanks a lot
Thanks Prof,that is quite helpful
I am having trouble in my advanced calculus class (which is sort of a hybrid of intro to real analysis and calculus 3? weird course that is currently some number theory, set theory, some topology, and some things that i havent had any experience with in the past, which this helps with so thank you!)
Thank you! You made it easy ❤
The yoongi pfp 😭
thank you so much! ☺
Hi ,nice explanation.
Could you prove that the set of accumulation points are always closed for any set?
Thank you!
Thank You !!
its really helpful...bt why did you leave out points between 4 and 6?
Because the points between 4 and 6 are not in the set A
Would a point still be an interior point if it reaches a point not in the set? for example let's say in the example set we use 3 as the point, if we "stretch out" we reach 4 which is not in the set, would the 3 then be an interior point?
Interior points of A just need to have *some* reach-out radius that only touches points of A. So yes, a reach of radius 1 from x=3 will touch 4 which is outside the set, but a reach of radius 1/2 will *only* touch points of A and that is enough to say 3 is an interior point of A.
you save me thanks you
Wish I'd found these videos earlier. I needed the stick figures 😭Exam 2moro. Need 15% to pass and hoping to get them in topology😅