402.3A4 Accumulation Points and Closure of a Set

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  • Опубліковано 22 гру 2024

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  • @meryembusracelik4912
    @meryembusracelik4912 Місяць тому

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    @shahriarjami Рік тому +5

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    • @MatthewSalomone
      @MatthewSalomone  Рік тому +1

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      @abdirazaqali8921 Рік тому +1

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    @waboaugustusmakholwa9762 2 роки тому +1

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    @lizzynyags7585 Рік тому +1

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  • @clydefrog6974
    @clydefrog6974 2 роки тому +2

    Does this definition mean that there are infinitely many accumulation points when A is a subset of the natural numbers? (Since we say there exists y in A, then n=1,2,3,4,5,6,... would only require finitely many elements of N in the sequence).
    I am currently enrolled in elementary real analysis, so I am sorry if my comment makes no sense, still learning the basics!
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    @j.r.9966 Рік тому

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  • @marthasamuel
    @marthasamuel 2 роки тому +1

    can an accumulation point be outside a Set?

    • @MatthewSalomone
      @MatthewSalomone  2 роки тому +4

      Yes! This is one of the key elements of the definition. For example, A = (0,1) has 0 and 1 as accumulation points. Some sets *do* contain all their accumulation points - these are **closed** sets.