Introduction to Line Integrals - Focus on Parameterizing Curves

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  • Опубліковано 25 жов 2024

КОМЕНТАРІ • 22

  • @NakiaRimmer
    @NakiaRimmer  2 роки тому +3

    @12:20 : r(t) should have 3-4t in the first component

  • @sophiebaird3400
    @sophiebaird3400 9 місяців тому +1

    Thank you SO much! Things that have confused me for a long time finally click when I hear you explain them!

  • @CaptainBobSim
    @CaptainBobSim 2 роки тому +2

    You are an outstanding teacher! Thank you for this video!

  • @adithyarajapakshe3791
    @adithyarajapakshe3791 3 роки тому +1

    wow! well explained and helpful, thanks, Mr.Rimmer!!

  • @muwongeevanspaul9166
    @muwongeevanspaul9166 3 роки тому

    Am so greatiful, thanks so so so so much....I have clearly understood line integrals....

  • @Pozizzle
    @Pozizzle 3 роки тому

    Fantastic explanation!

  • @louismotte5079
    @louismotte5079 3 роки тому

    thank you mr Rimmer very helpful, and i am glad to have found your videos :)

  • @azizkash286
    @azizkash286 Рік тому

    amazing video sir

  • @anysianas5099
    @anysianas5099 2 роки тому +1

    you saved my semester I was about to drop my class because it did not understand parametrization

  • @jam9339
    @jam9339 11 місяців тому

    sobrang maestra ito

  • @henriquenunes7196
    @henriquenunes7196 11 місяців тому

    Great video😊

  • @toniocartonio572
    @toniocartonio572 3 роки тому +1

    Hi, how do you parametrize a vertical line? Great vid btw

    • @NakiaRimmer
      @NakiaRimmer  3 роки тому

      Hello! Great question. In 2 dimensions a vertical line has equation x = k for some constant k. There is no mention of y in the equation at all. This means that y is free to be anything you want but x is stuck on k. So you would parametrize it by have x = k and y = t. You would allow t to go from your smallest y to your largest y if it is a line segment. If it is the entire line, then t would go from -infinity to infinity. Let me know if you were asking about a vertical line in 3 dimensions.

    • @toniocartonio572
      @toniocartonio572 3 роки тому

      @@NakiaRimmer Yes, I was asking in two dimensions, thanks. And if the parametrized line, for example, starts from (2;2) and ends in (0;2), how would parametrize it? Is it y=2, x=t?

    • @NakiaRimmer
      @NakiaRimmer  3 роки тому +1

      @@toniocartonio572 Yes, but the issue you run into is that t starts at 2 and end at 0. t is going backwards, usually you want t to go forwards. What you can do is let x =-t and then t would go from -2 to 0. The thing with parametrizations is that there is no unique way to do it, so you should parametrize whichever way is easiest for you.

  • @bgvlogs6601
    @bgvlogs6601 2 роки тому

    For the ending isn't x=3-4t why did you put 3+4t in your parameterized vector r(t)= < 3+4t, 2+6t, 1+6t > ?

    • @NakiaRimmer
      @NakiaRimmer  2 роки тому

      Yes, thank you for catching that mistake. I’ll pin a comment with the correction.

  • @elpatron8375
    @elpatron8375 3 роки тому

    Great video, very well explained and very helpful as well, thanks!