Nucleophilic Aromatic Substitution - Benzyne Intermediate and Meisenheimer Complex

This organic chemistry video tutorial provides a basic introduction into nucleophilic aromatic substitution reactions. It discusses the conversion of para-chloronitrobenzene into para-nitrophenol using an addition elimination reaction mechanism that passes through a resonance stabilized carbanion intermediate known as the Meisenheimer complex. This video also discusses the conversion of para-bromotoluene into meta and para-methylaniline using an elimination addition reaction mechanism that passes through the benzyne intermediate.
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[@Doc_McStuffins]

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[@scoobydoo02]

Never quit. I love this!!!!

[@PunmasterSTP]

Meisenheimer? More like my, so much higher...in educational value than almost every other video on UA-cam. Thanks again so much for making and sharing these!

[@husseinfedilla6814]

Beautiful

[@1BigMan.Tshepo]

W video man, big up.

[@dathuyadav8822]

Nice

[@musicmeister1313]

ok, but what are the other reagents that can go through the benzyne intermediate 😠😠?

[@raiyanrahman79]

In Chlorobenzene there should slight negative charges in Ortho and para position due to resonance. Then why does a Neucleophile attack the H in the ortho position? Wouldn't it make more sense if it attacked the H in meta position where the electron density is relatively lesser?

[@Spogeboii]

Will NAS occur if there is an activating group and a good leaving group? Or is this process restricted to a deactivated ring and a nucleophilic reagent?

[@ansingh1338]

Same doubt...

[@PunmasterSTP]

Doesn't the reaction starting at 14:56 have an activating group (methyl) and a good leaving group (bromo)?

[@tom_winguill]

9:40 3️⃣50 C

[@alexfrostbound4401]

You are a breathing miracle

[@gerstensaft2936]

In the last reaction. How's the ratio of meta to ortho and para? 1:2:1 (orto:meta:para)
Or is para more likely to happen than ortho because of steric hindrance of the CH3 group?

[@janrenehaak]

I think that the methyl-group isn´t so bulky, so their is no hindrance. Because of that I suggest, that the ratio ist 1:2:1 as you said. I hope this didn´t come too late :D

[@deepamishal4683]

17:30 which one is major and minor

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[@tom_winguill]

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[@PunmasterSTP]

From your asking that question, I take it you two have chemistry together?

[@crenapun57]

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