Ang galing😭 thank you po talaga, in a short period of time, naintindihan ko agad compared sa lesson na binigay ng teacher namin na inabot pa ng ilang pages di ko pa rin makuha. Salamat po talaga💗
thank you for this video it really helped me! But I have a question - what if the last class in the frequency is something like: "25 and above"... will the width change if that is the case? or should i still use the width that I got from the other classes..? I would really appreciate your reply ~ thank you and God bless ^^
Sir thank you for the video I have a question the that you shown us on the video is already arranged or we need to arrange it by the given numbers I am strugling to find out where to start plsss help me sir thank you
Sir thank you for the video I have a question the that you shown us on the video is already arrange or we need to arrange I am strugling to find out where to start plsss help me sir thank you
you mean lower class boundaries? minus 0.5 lang po sa lower class limit. ito po and video ng frequency distribution n diss po dyan kung pano nakuha and LB ua-cam.com/video/euLusjeuHZM/v-deo.html
@@simplymath5274 for example sir, we can find in the column of the cumulative frequency the last value "45", which is the lowest cumulative frequency, since I have to find the value lower than it, what will the value be?
in Q3. PEMDAS rule: start with the ( ) 60-43 = 17, then it becomes 17/18, next 17 x 11=187, it becomes 187/18, last 187/18 +85.5 = 95.8888, round off to two decimal places 95.89
Wala po akong mahanp na nagtuturo kubg panu makuha ung frequency isusubmit ko ung module ko na walng sagot kasi diko alam panu kumuha ng frequency dinmaan kasi tinuro
Ang galing😭 thank you po talaga, in a short period of time, naintindihan ko agad compared sa lesson na binigay ng teacher namin na inabot pa ng ilang pages di ko pa rin makuha. Salamat po talaga💗
Salamat
Helpful , I understood the concept within some few minutes with your explanation
I get the answer of so many questions from this video 🙏😍
Huhu finally nagets ko na siya, thank you poooo!❤
God bless u I found it brief and memorable thank u
welcome
Maybe I can compare this exceptional explanation to organic chem and khan ,thank you!
Thank you very much
Good and precise thankyou
Woww salamt po very well exlained
Thank you
thank you po sorang helpful ng mga vids niyo :))
thank you please subscribe
Thank you very much it helped me alot ,
You're the best. TYSM
That was simple. Thankyou. Idk why my math lecture is very complicated.
Welcome
Excellent work.
My module savior this quarantine 💝
Thank you!
Thank you. please subscribe and share the channel with your friends
Big help! 👏
Thanks for the videos.
Glad you like them!
Thank you so much youre the best
Thanks
How did you get the total of 95.5?
Thank you for the video, very helpful. I had a question: is it okay if we use the classes as given and get approx. answers like- 81.16 for d4?
ang smooth mag turo, thank you for this!❤️
Kala ko po Sir mag ro-round up like dun sa example nyo na "95.89" hindi na po pala. Thank you po at naliwanagan ako
This video is really helpful
thank you
thank you for this video it really helped me! But I have a question - what if the last class in the frequency is something like: "25 and above"... will the width change if that is the case? or should i still use the width that I got from the other classes..? I would really appreciate your reply ~ thank you and God bless ^^
The class width should be the same from the first class up to the last class.
Thank you so much ❤
How can I interpret the answer for the 3rd Quartile?
Ano pong pinagkaiba ng find in /100 of the 4th decile sa " the computed value of the 4th decile is ____". Thanks in adv po 💙
thank you🙏
Please why is the class boundary mostly .5
Thank you po^^
What about sir pag walang frequency? Paano hanapin yung frequency?
I think Q3 is 95.84 po
Thany you very much
Sir thank you for the video I have a question the that you shown us on the video is already arranged or we need to arrange it by the given numbers I am strugling to find out where to start plsss help me sir thank you
hi po! paano po kapag ang kn ko is 6.25 then ang
Hello po sir paano po nakuha yung width ("11") sa P70 hindi ko po nagets yun eh
minus the upper and lower class
paano po pag nakuwa ko po sa kn/10 is 61 po eh may 61 rin po duon sa cf?
Pano po pag nakalagay sa class limit 65.5 need papoba mag subtract ng 0.5? Is it possible that the boundary will become 65 nalang po?
depende po sa usapan nyo ng teacher mo kung mag ra rround off b o hnd at kung mag round off ay isang decimal places
Hello po what if kong ung answer ng kn is lower than pa po sa 1st class less CF. ano po ung lalagay zero?
that will be kn - 0
SIR PAANO YUNG FORMULA DI KO NA GETS YUNG PAG CALCULATE IBA YUNG LUMALABAS
Sir thank you for the video I have a question the that you shown us on the video is already arrange or we need to arrange I am strugling to find out where to start plsss help me sir thank you
yeah, you need to arrange first the data in ascending order.
Thanks for teaching me but what if the total of Cf is less than the kn?
You over think! You need to rest
😂😂😂😂😂@@kenyiemma7005
Thank 🙏🙏
Welcome
You were too fast
paano po kuhanin yung frequency?
What if the kn is 6 what will be the less than cf?
the cf will be zero
❤
hindi po ba 81 yun kasi n+1 yung formula
I didn't get where the 60 came from?
(3x80)/4 = 60 or (80/4)*3 = 60
Di niyo po pinapakita kung paano niyo po sinusolve yung final answer?
Sir paano po makuha ang LB paano i compute? Help naman po at example sir bigay kayo dko po kase gets yung sa modules ko eh
you mean lower class boundaries? minus 0.5 lang po sa lower class limit. ito po and video ng frequency distribution n diss po dyan kung pano nakuha and LB ua-cam.com/video/euLusjeuHZM/v-deo.html
Thank you ❤️
You’re welcome 😊
Panooo nyo po na compute na 95.89 po eon?Huhu nakukuha ko po kasi 95.84 dun po sa quartile 3 huhu
60-43 = 17, 17x11=187, 187divided by 18 + 85.5
saan po ba galing yan 56 sir?
Saan po kinuha 60,32,56
yung cf po ba na ilalagay pag nagsolve na ako is yung nasa pinakababa ng cf sa table?
THe cf before the quartile , decile or percentile class
what is the lower cumulative frequency of the lowest cumulative frequency sir? wala napo kasi sa table sir, so do I put 0?
I don't get your question, but if you are asking about the lowest cf it will be the frequency of the class where the lowest data entry is located.
@@simplymath5274 for example sir, we can find in the column of the cumulative frequency the last value "45", which is the lowest cumulative frequency, since I have to find the value lower than it, what will the value be?
@@pabataojovemilleralexis7811 same question po, baka 0 na po ata
Bat yung samin sa cf is baliktad nauuna yung 80 or parehas lng dn
magsimula kung saan nakalagay ung lowest data entry. kung nasa taas don k mag simula, or kung nasa baba sa baba k mag start
Pano poba nakukuha yang frequency nayan😭
Pano namn po kung yung w is unequal? Anong gagamitin kung interval?
data equal ang w
thanx bro
welcome
Hi po mam bkit ang layu sa akin 95.5 then ung sayu ay 95.89?paano po
I'm even confused, pls explain how you got 95.89 instead of 95.5
Gwapa ang gabasa e ss
thank you :)
Welcome, please subscribe.
Paano po nakuha yung class width?
64-53 or 74-63
how is the width 11? IS IT NOT 10
subtract any consecutive lower or upper limits. e.g. 64 -53 =11 or 74 -63 =11
@@simplymath5274Why it's doing like that ?
Is it wrong calculating 96- 86 ?
Sir pano po nakuha yung Final Answer?? Pa sagot po please
Nasa Last step po yung Qsub3 =85.5 + (63-43/18) 11
Jan po
follow mo lang po ung process.
Hindi namn itinuro panu nacompute yung sa mga final answer🥺
gamit k ng calculator.
Paano nyopo nakuha yong 95.89 na sagot?
60-43 *11 /18+85.5
@@simplymath5274 sir hindi po ba 95.84 yung sagot sa q3?
@@Slim-vd6bl hindi po
Grabe na guluhan ako sa last part san mo na kuha yng 11?
11 ay ang class width, para makuha ang class width i minus mo ang dalawang magkasunod n either lower limit or upper limit (64-53 = 11) or (74-63 = 11)
Please explain slow in India English please
Hi, hindi ko ho gets paanong computation po ginawa para makuha final answer
in Q3. PEMDAS rule: start with the ( ) 60-43 = 17, then it becomes 17/18, next 17 x 11=187, it becomes 187/18, last 187/18 +85.5 = 95.8888, round off to two decimal places 95.89
Diko maintindihan bakit ¾x 80 naging 60 paano????
(3x80)/4 =60
Wala po akong mahanp na nagtuturo kubg panu makuha ung frequency isusubmit ko ung module ko na walng sagot kasi diko alam panu kumuha ng frequency dinmaan kasi tinuro
ito po ang video about constructing frequency distribution. ua-cam.com/video/euLusjeuHZM/v-deo.html
Tq🥲
Welcome, Glad it helps. Please subscribe and share the channel with your friends. Thank you
mali yung answer mo minamadali kunti lang ang solution
Permission to use your video on my report, Sir, thank you po! 🤍✨
my pleasure
Thank you very much it helped me alot ,