another way to prove Young's inequality is through the Jensen inequality. By taking f(x)=exp(x) and differentiating twice we have that f(x) is convex. So by applying the Jensen inequality we have that f(x/p+y/q)=< f(x)/p + f(y)/q , so exp(loga + logb)=< exp(ploga)/p + exp(qlogb)/q => ab=
Math actually has a meaning, so visualizing it is important, productive and even essential. The integrals are not meaningless symbols - they correspond to areas under a curve. Ever heard of geometry? A lot of what math does is related to the quantification of space - including its shapes.
Thanks from Turkey for the explanation. It was much more descriptive than the videos I found in my own language.
Amazing explanation! Thanks
very logic and clear, the diagram is helpful to remember this inequality, thanks!!!
Thank you from Germany, your videos are pretty helpful. Keep it up man!
another way to prove Young's inequality is through the Jensen inequality. By taking f(x)=exp(x) and differentiating twice we have that f(x) is convex. So by applying the Jensen inequality we have that f(x/p+y/q)=< f(x)/p + f(y)/q , so exp(loga + logb)=< exp(ploga)/p + exp(qlogb)/q => ab=
Beautiful explanation!!! Thanks a lot
Great explanation, thank you!
Very nicely explained 👍
This is amazing! Thank you for this brilliant explanation and illustration.
Excellent video sir!
Brilliant, thanks a lot!
Fabulous!!! Thank you!
Nice! thanks, mate.
Good way to explain
Cool and helpful stuff, thanks!
非常感谢
very helpful, thanks!!!
perfect
p-1 needs to be >1 otherwise your function y would be concave not convex?
thx alot sir .plz can you show me how we proof hölder inequality using minkowski inequality
You can easily prove this using AM-GM inequality
If a>0 and b>0 and if 0
Can be easily proved by am gm inequality
What is Young's Inequality for convolution..??
So a picture can act as a valid proof?
Math actually has a meaning, so visualizing it is important, productive and even essential. The integrals are not meaningless symbols - they correspond to areas under a curve. Ever heard of geometry? A lot of what math does is related to the quantification of space - including its shapes.
u only know p>1, not p-1>1, thus the area proof isn't sufficient enough
NVM the proof is correct, but maybe nicer to entertain the case when y(x) concaves down (even though its the same)
your accent is very irritating
That's completely uncalled for. I think his accent is fine.
Zunaira, your presence is very toxic.
yeah. why don't you ask your money back.
Does it matter?