Grade 10 Systems of Linear Equations Introduction and review
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- Опубліковано 3 сер 2024
- Welcome to Grade 10 mathematics. In this course you will learn many new concepts including quadratics and trigonometry. This course is a very important foundation for everything you will do in grade 11 and 12. In this lesson I review some vocabulary from grade 9, show three different graphing techniques for lines including table of values, x and y intercepts and slope and y-intercepts. Finally we will rearrange from standard to slope y-intercept form and vice versa.
Thank you so very much for this. It has helped me a bunch. Just got a 97% on my unit test thanks to you!
Good for you! You must have been well prepared!
Thank you so much. it is very clear!
thank you !
You are most welcome! ❤️
Amazing video!
Hi, the playlists are a bit fragmented. For the playlists, could you index it?
So,
Unit1 - Linear Systems
Unit2 - Analytic Geometry
Unit3 - Quadratic Relations
Unit4 - Quadratic Expressions
Unit5 - Quadratic Equations
Unit6 - Trigonometry
... and so on....
Thanks for the resource!
I’ll see what I can do when I return from Vancouver. iPhone editing doesn’t work well!
@@mshavrotscanadianuniversit6234 Thanks !
I have a MathSmart 10 book, and I was wondering if it is applicable?
I looked at it on indigo books and I’m sure it would be helpful as it covers all of the same topics. And it’s Canadian so they must have attempted to cover the grade 10 curriculum requirements.
♥️♥️♥️
Hope these videos make you an awesome math student! 😊❤️😊
Ms Havrot's Canadian University Math Prerequisites yes they do! Thank you for everything. You have changed a lot of people’s life for the better♥️
Hello there, I hope all is well. I came across this kind of problem: 3x-5y=-13
4x+2y=0
I approached it by multiplying the top row by -4 and bottom row by 3 to eliminate the x so I can find y. Is my method correct? I've seen this done I'm another way but I want to see if this is also acceptable.
Yes, that would work just fine. You have a few options with any problem.
@@mshavrotscanadianuniversit6234 oh, because the values for x and y I got were different from the other person. He multiplied the top row by 2 and bottom by 5.
I did both solutions and the answer is the same (as it should be). Y = 2 x = -1
Perhaps check your calculations.
Here is your work:
-12x + 20y = 52
12x + 6y = 0. Adding together gives you
26y = 52. y = 2. Etc
@@mshavrotscanadianuniversit6234 Ah yes, apparently I left my answer in a fractional form, y being 52/26 and being x -1 as result of 4x= -104/26. Thanks for the help.
Also, I'm learning about instantaneous rate of change and average rate of change. Do you have a video on those?