There are a few comments saying his FA is wrong. It's right (source: the textbook), but he set it up incorrectly. Should be 4(2.5) - FA(4/5)(3.75) = 0, FA = 3.33. He probably didn't calculate his expression manually; instead, he just checked the textbook and wrote down the answer.
@@blackwingBF 4(2.5) - FA'(3.75) = 0 will give you the force that is vertical to the beam, but that's FA', not FA. You could imagine it as if the beam was straight but the support was at an angle. The reactionary force of the support would also be at an angle, so when you calculate the moment, you would find the component of the support's force that was upright and not the actual reactionary force of the support. Or something like that.
I was banging my head trying to understand the FA until I scrolled down and read the comments. Otherwise this helps a ton in understanding the reactions and moments.
There are a few comments saying his FA is wrong. It's right (source: the textbook), but he set it up incorrectly. Should be 4(2.5) - FA(4/5)(3.75) = 0, FA = 3.33. He probably didn't calculate his expression manually; instead, he just checked the textbook and wrote down the answer.
thank you
Why isn't it just 4(2.5) - FA(3.75) = 0? Cause I thought for the moment, the Force has to be vertical to the pole, so you don't need to time 4/5.
@@blackwingBF 4(2.5) - FA'(3.75) = 0 will give you the force that is vertical to the beam, but that's FA', not FA. You could imagine it as if the beam was straight but the support was at an angle. The reactionary force of the support would also be at an angle, so when you calculate the moment, you would find the component of the support's force that was upright and not the actual reactionary force of the support. Or something like that.
Why do you have Bx going in the positive x direction? It's not pulling the beam, it's resisting in the negative x direction.
I was banging my head trying to understand the FA until I scrolled down and read the comments. Otherwise this helps a ton in understanding the reactions and moments.
I believe your Fa is incorrect, you should have multiplied the sin(51.1), but you divided.
true
So wait in the moment of B where we get Fa, our answer is Fa = 2.13 kN?
yaa..i think the same.. thats why i dont get the anwer
you, my friend, are still a statics master
I think it should be < Fa(sin 53.130) = Fa' >
yah but there is a simpler way
Fa*3=4k*2.5
Did you need to calculate FA' ?
Couldn't you just have calculated Fa directly using the fact it's 3m away and perpendicular?
@@joshuacroy3888 Right. I understand. There are lots of ways to skin this cat, especially with moments. But I think it's more complicated his way.
Anyhow, I wanted to say thank you for all these videos! They've been very helpful!
Sir you find wrong FA prime value.
WRONG Fa
he said simple math but then he makes a mistake lol.
😂😂😂😂😂
you lost me with the F of A prime
chữ xâu vl thề đề nghị chỉnh lại cách viết để sinh viên hiểu chì