Good effort. Suggest following corrections to be made to get the concept right. 1. Loadlines restrictions (legal limits) are applicable for density of SW 1025, if there is no draft restriction at port it doesn't matter whether you are overdraft in port. It's called FWA/DWA. 2. Limiting draft winter at Skaw, displacement for SW(1025) should be taken not FW(1000) on same note above. 3. Cargo to load at Luga = (Winter DW-consumables) + consumption to Skaw (though negligible but technically incorrect!) Thanks
First thing amazing explanation and wonderful work. Helping many officers for self study. Q1 - For winter zone calculation at limiting point in skaw, how did you get water density of 1.000 q2 - For UST luga, You have taken 1.025 initially then 1.000 Please clarify. Thank you and keep up the good work you are doing.
Good explanation but you shall consider taking max cargo intake for density of SW 1025 since the Load Line convention allows to submerse your draught for FWA/DWA based on the density in the dock.
You can load 92658 disp at load port. The ship will sink equal to FWA above W line in fresh water which is allowed by ILLC. If you load 90000 disp she will arrive at Dunkirk with draft 14.1(-)DWA.
Yes.... the submersion of load line is allowed in FW and Dockwater as per the ILLC. However, this concept was deliberately not included in this video for a purpose as we intend to do a separate video on the topic of FWA and DWA. There we shall be explaining the concept in a clear and detailed manner! Deadweight calculations/ stowage plans and loading sequences in themselves are huge topics and therefore all other related concepts shall be taken up separately! Stay tuned!
Considering she will consume bunkers from ust luga till passing Skaw, shouldn't we load the amount equal to the bunkers which will be consumed in order to maximize cargo intake?
Thank you for these information sir. More useful these videos sir. I found only Part 1 to Part 7 videos. Can you please advise me, Remaining 2 videos. Eagerly awaiting for your suggestions. Many thanks in advance.
iF WE TAKE BUNKER IN SKAW WE SHOULD ALSO MINUS FROM THE DISPLACEMENT ON THW LIMITING POINT? CAN WE MAKE PLUS FOR CARGO THE CONSUMPTION OF BUNKER THAT WILL LOOSE FOR THE SKAW? GREAT JOB!THANKS FOR CHANNEL!
Sir, can u explain how we get that displacement in Dunkirk And also when we reach skew, we need to be at winter zone draft corresponding to fwd draft, . And we need not submerge our winter zone in fw draft right?
good day sir, why when adding all to cargo loaded at ust luga, there is difference between diesel oil and fw quantities bit confused as at skaw cargo loaded was 75,830 disp was 90,398 but at same cargo dwt changes to 90,426 at ust luga Thanks for the support.
Suppose my summer draft is 13.5 and i load from summer port to discharge at summer port.. now density at load port is 1.020 . So do i convert my displacement of summer draft to 1.020 or keep displacement of summer draft @1.025 and let it submerge beyond 13.5 m draft ?? Awaiting reply
I have one question, In some other videos not yours but other channels, they applied density correction to dead weight . Please explain do we need to apply density correction to displacement or to dead weight ?
The density correction could be applied to either displacement OR deadweight. Both will yield the same result. It's just a matter of your convenience, however, applying to displacement makes the calculation clearer and you can compare the results with loadicator more conveniently.
@@vijaymanhas947 Imagine that at draft 12.00 mtrs the displacement is 90000 mt at density 1.025 [obtained from tables] The light ship of vessel is 12000 mt. Let us calculate the density correction density correction = 2195 mt Case 1 : Disp @ 1.025 = 90000 mt Density correction (-) 2195 mt Corrected displacement = 87805 mt Light ship (-) : 12000 mt Deadweight : 75805 mt Case 2 : Disp@ 1.025 = 90000 mt [1.025] Lightship (-) = 12000 mt Deadweight@ 1.025 = 78000 mt Density Corrn (-) 2195 mt Corrected deadweight = 75805 mt Hope it clears.
@@funnel2tunnel360 so first we have to find density correction value. But with interpolation method it is not coming correct. To find the value of density correction =2195 mt , we need to apply interpolation in first case. Case 1: 90000 ×1.000/1.025 = 87805 my 87805 -12000= 75805 Mt Case 2: 90000 -12000 =78000 Mt 78000×1.000/1.025= 76097 Mt I have this doubt
Hello sir , i ve one doubt while explaining loadline n zone you have mention loading port is in summer zone n disch port is in winter as you are in nov month, my quest is when you are in month of nov so loading port ll be or ll be not in winter zone as you are already in nov month n winter start from 1 nov to 31 march????
Correct me if I'm wrong, but isn't it that we do not need to apply density correction on displacement for Loadline restrictions? So if vessels draft at winter point exceeds its winter loadline draft at @ 1.000 density, its fine, for as long as it will be at its winter draft or less if calculated to SW density.
Hahaha i also confused ..... As i know to maximise cargo sir... 92658mt at skaw.. forget the dnsty... So 92658-lighht ship-fuel,fw,balst,constant,etc.. PLUs f.o. u will consume frm skaw to loading port
Unpumpable ballast in itself means the quantity of ballast water which cannot be pumped out using pumps. Lower the quantity of unpumpable ballast higher is the quantity of cargo you can carry. So a smart Chief Officer will always strive to pump out maximum ballast during loading so that he is left with minimum unpumpable ballast quantity
Im confused with u man.... Hahaha ..corect me but 14.185 m with dsplacemnt 92658mt at skaw... U will deducted by lightship and other weights at skaw... Den plus ur fo or do u will consume from loading port .. the answer is ur max cargo ... Sorry if i am wrong... Make it simple because my iq is so low..thnx..
Click here for part 2 : ua-cam.com/video/KH7n4XCJneE/v-deo.html
Good effort. Suggest following corrections to be made to get the concept right.
1. Loadlines restrictions (legal limits) are applicable for density of SW 1025, if there is no draft restriction at port it doesn't matter whether you are overdraft in port. It's called FWA/DWA.
2. Limiting draft winter at Skaw, displacement for SW(1025) should be taken not FW(1000) on same note above.
3. Cargo to load at Luga = (Winter DW-consumables) + consumption to Skaw (though negligible but technically incorrect!)
Thanks
Yes I think same to you
First thing amazing explanation and wonderful work. Helping many officers for self study.
Q1 - For winter zone calculation at limiting point in skaw, how did you get water density of 1.000
q2 - For UST luga, You have taken 1.025 initially then 1.000 Please clarify.
Thank you and keep up the good work you are doing.
Perfectly explained God Bless You
Very informative topic... Godbless
Thank you for these informations sir. You're quiet excellent in explaining these crucial topic. I've learned a lot.
Thank you dear colleague for the video. The video is very useful and the information is very easy to understand.👍
Thank you for the very clear explanation sir you help us a lot. More power to you ❤️🙏
Excellent explanation. Thank you.
Glad you liked it ... cheers 🍻
Thanks alot for such a easy explanation with full detail.
Incredible good explanation. Congratulations Captain. All the best.👏👏👏
tq sir very useful understanding
Good morning friend
For preparation of second mate / DNS/ BSC nautical science/NCV come in #kundanpatna
very informative video thanks.
Thank you, Sir.
Great 👍
This Video such useful for every officer it was pretty much clear in every steps you did...thank you for the great effort and ideas you share to us...
Thanks mate!
Excellent video
Thanks very much
Thank you very much for this beautiful explanation sir. It was very useful for young officers awaiting promotion.
Thanks Vivek! Glad you liked it. Help others by sharing. Cheers!
!!super!!
Very good sir, please continue for other aspects or vessel types. 👌
Amazing 👍
Good explanation but you shall consider taking max cargo intake for density of SW 1025 since the Load Line convention allows to submerse your draught for FWA/DWA based on the density in the dock.
Good explanation 👏
You can load 92658 disp at load port. The ship will sink equal to FWA above W line in fresh water which is allowed by ILLC. If you load 90000 disp she will arrive at Dunkirk with draft 14.1(-)DWA.
Yes.... the submersion of load line is allowed in FW and Dockwater as per the ILLC. However, this concept was deliberately not included in this video for a purpose as we intend to do a separate video on the topic of FWA and DWA. There we shall be explaining the concept in a clear and detailed manner!
Deadweight calculations/ stowage plans and loading sequences in themselves are huge topics and therefore all other related concepts shall be taken up separately! Stay tuned!
thank u very much
Considering she will consume bunkers from ust luga till passing Skaw, shouldn't we load the amount equal to the bunkers which will be consumed in order to maximize cargo intake?
That quantity in present circumstances is hardly of any value and hence was not taken into consideration.
Thank you so much sir
Thank you for these information sir. More useful these videos sir. I found only Part 1 to Part 7 videos. Can you please advise me, Remaining 2 videos. Eagerly awaiting for your suggestions. Many thanks in advance.
If the depth for cross point ( sound channel ) you can load to summer draft but if the unloading port have available depth also
iF WE TAKE BUNKER IN SKAW WE SHOULD ALSO MINUS FROM THE DISPLACEMENT ON THW LIMITING POINT?
CAN WE MAKE PLUS FOR CARGO THE CONSUMPTION OF BUNKER THAT WILL LOOSE FOR THE SKAW?
GREAT JOB!THANKS FOR CHANNEL!
Sir, can u explain how we get that displacement in Dunkirk
And also when we reach skew, we need to be at winter zone draft corresponding to fwd draft, . And we need not submerge our winter zone in fw draft right?
Pls make a discharg sequence 5 holds bro
You can load more cargo for 1.025 winer mark, not for 1000 and check again draft limit point. You can sink winter mark to FWA.
excellent video
Glad you liked it!
Thanks for your explanation , IN loading port for vessels less than 100 m in length which loadline zone will be applicable ? please clarify ?
Do you have example for calculation 2 grades ? Thank you
We Shall be uploading 2 grades video soon:) stay tuned
good day sir, why when adding all to cargo loaded at ust luga, there is difference between diesel oil and fw quantities bit confused as at skaw cargo loaded was 75,830 disp was 90,398 but at same cargo dwt changes to 90,426 at ust luga
Thanks for the support.
Suppose my summer draft is 13.5 and i load from summer port to discharge at summer port.. now density at load port is 1.020 . So do i convert my displacement of summer draft to 1.020 or keep displacement of summer draft @1.025 and let it submerge beyond 13.5 m draft ?? Awaiting reply
how to find displacement in Fresh water
I have one question, In some other videos not yours but other channels, they applied density correction to dead weight . Please explain do we need to apply density correction to displacement or to dead weight ?
The density correction could be applied to either displacement OR deadweight. Both will yield the same result. It's just a matter of your convenience, however, applying to displacement makes the calculation clearer and you can compare the results with loadicator more conveniently.
@@funnel2tunnel360 I tried as you said but result is not same .
@@vijaymanhas947
Imagine that at draft 12.00 mtrs the displacement is 90000 mt at density 1.025 [obtained from tables]
The light ship of vessel is 12000 mt.
Let us calculate the density correction
density correction = 2195 mt
Case 1 :
Disp @ 1.025 = 90000 mt
Density correction (-) 2195 mt
Corrected displacement = 87805 mt
Light ship (-) : 12000 mt
Deadweight : 75805 mt
Case 2 :
Disp@ 1.025 = 90000 mt [1.025]
Lightship (-) = 12000 mt
Deadweight@ 1.025 = 78000 mt
Density Corrn (-) 2195 mt
Corrected deadweight = 75805 mt
Hope it clears.
@@funnel2tunnel360 so first we have to find density correction value. But with interpolation method it is not coming correct. To find the value of density correction =2195 mt , we need to apply interpolation in first case.
Case 1: 90000 ×1.000/1.025 = 87805 my
87805 -12000= 75805 Mt
Case 2: 90000 -12000 =78000 Mt
78000×1.000/1.025= 76097 Mt
I have this doubt
Finding out density correction doesn’t require any interpolation.
Density corrn =
(SW Disp x Density) / 1.025
Hope it clears!
Hello sir , i ve one doubt while explaining loadline n zone you have mention loading port is in summer zone n disch port is in winter as you are in nov month, my quest is when you are in month of nov so loading port ll be or ll be not in winter zone as you are already in nov month n winter start from 1 nov to 31 march????
please can you let me know the details and pictures of cargo vessel whose weight is 50000tons
Correct me if I'm wrong, but isn't it that we do not need to apply density correction on displacement for Loadline restrictions? So if vessels draft at winter point exceeds its winter loadline draft at @ 1.000 density, its fine, for as long as it will be at its winter draft or less if calculated to SW density.
Hahaha i also confused ..... As i know to maximise cargo sir... 92658mt at skaw.. forget the dnsty... So 92658-lighht ship-fuel,fw,balst,constant,etc.. PLUs f.o. u will consume frm skaw to loading port
Hi Sir! Thanks. @7:30 in the video, where we will get this map mentioning the Loadlines zones???? Please suggest.
You can mail to us at ask@funnel2tunnel.com and we shall reply yo you!
Sir, is it possible to improve the Loadables by removing the unpumpable Ballast
Unpumpable ballast in itself means the quantity of ballast water which cannot be pumped out using pumps. Lower the quantity of unpumpable ballast higher is the quantity of cargo you can carry. So a smart Chief Officer will always strive to pump out maximum ballast during loading so that he is left with minimum unpumpable ballast quantity
How come density chnaged at luga fr sw to fw...pls corrrect me
Hello funnel2tunnel can u help me to summarize the content of ur video? Please i really need it
And your load port is in winter zone now)
Im confused with u man.... Hahaha ..corect me but 14.185 m with dsplacemnt 92658mt at skaw... U will deducted by lightship and other weights at skaw... Den plus ur fo or do u will consume from loading port .. the answer is ur max cargo ... Sorry if i am wrong... Make it simple because my iq is so low..thnx..