Years ago, I worked for a company out of Indianapolis that painted high voltage towers and substations. We painted the steel towers while energised. At times if we wasn't holding on good we would get a little jolt, it wouldn't hurt, but you knew it. I done this for several years before transferring my book to another local and other type of painting. In the time I painted high voltage towers or subs, I never seen anybody get into a line. But, a good friend from tower painting did years later working in a sub station for a different company that pushed " the safety issue" too far, and he got into an energized line. Thanks for the info, very interesting.
Oh cool. I tried this but with a compact curly bulb, it seems the longer bulbs work the best. I suppose the voltage difference at each end is greater that way.
at 6:00 P =I^2 * R = V^2/ R , since V=I * R P110 = (110v)^2 /2 ohm P220 = (220v)^2 /2 ohm P220 = 4 * P110 whats wrong with the power consumption in this way? higher the volt, more the power loss by 4 times
Years ago, I worked for a company out of Indianapolis that painted high voltage towers and substations. We painted the steel towers while energised. At times if we wasn't holding on good we would get a little jolt, it wouldn't hurt, but you knew it. I done this for several years before transferring my book to another local and other type of painting. In the time I painted high voltage towers or subs, I never seen anybody get into a line. But, a good friend from tower painting did years later working in a sub station for a different company that pushed " the safety issue" too far, and he got into an energized line. Thanks for the info, very interesting.
The Field.... Great video... Well done... Thank You
Thats really cool, thanks for sharing and Keep up the Great work!
Thanks again. You too.
Thanks buddy, It was really helpful
Why increasing voltage decreases the current? or if the question is wrong then, how power Station put power into wire? (By creating voltage?)
Very informative! Thanks for making this video!
Oh cool. I tried this but with a compact curly bulb, it seems the longer bulbs work the best. I suppose the voltage difference at each end is greater that way.
Thanks for sharing!!
So it could kill you if you were up a little higher? Wouldn't the resistance still be to high? Pretty crazy video. Thanks for sharing.
Cool video!
Your meter doesn't have separate inputs for voltage / current?
"There's no way..." :::arc jumps into the man's antenna wire::: j/k this was fascinating.
Can I take advantage of this effect to charge up a smartphone?
JamieJamez
There was a kickstarter for something like that...
...wasn't sure if it was a scam though.
your phone charger will die right away if the voltage surpass the maximum voltage of your charger can take.
Are you a chemistry or a physics major?
at 6:00 P =I^2 * R = V^2/ R , since V=I * R
P110 = (110v)^2 /2 ohm
P220 = (220v)^2 /2 ohm
P220 = 4 * P110 whats wrong with the power consumption in this way? higher the volt, more the power loss by 4 times
Yes.
P=0
The formula should be like this Pg = Pd + Pl
not -
1 volt of energy...seriously