@Ansh pandey that channel is the one in which I just give voice over, my team mate is really busy so I was unable to upload there . Also We are thinking to upload in english too beacuse of demand .
Thank you so much! I just started watching 5 mins ago and I love your content its so help full to me especially because I suck at maths and I hate it but you explain so so so so well it makes everything so so so so much clear than before!! you deserve a sub and like! I think we need more people like you! keep up the good work! :)
The easiest way to do this is to prememorize all 100 year values from 00 to 99. Then I just add that to the century code and reduce mod7 and finally add that to a prememorized value for each of the possible 366 dates. For example, June 15, 2012 would simply be: 2+2+1=5, so Friday! June 15 always has a value of 2 (prememorized) 2000's has a century code of 2 and, year 12 always has a value of 1 (prememorized) 2+2+1=5, Friday! Anytime leapyear happens just subtract one from the answer for January or February only, all other months stay the same! I calculate any day of the week using my method in less than a second, almost instantly to 2 seconds tops if I'm thinking a bit. I do both the Julian and Gregorian calendars in both AD and BC infinitely into the past or the future.
That's really good! I use a similar technique. For June 15, 2012 above, I work from right to left. So, first I take 2012 and know my adjustment for 2000 is 6. Then, 12 becomes 1. 6+1 casts out to 0. 15 casts out to 1. and June is 5. So, I have 1+5 is 6, which is Friday. (Sunday is 0, Monday is 1, etc.). It's farily quick when you can visually see what numbers are multiples of 7 (cast out 7). My system works from 1500 thru 2300 although I have look at the other centuries. It's the Gregorian calendar.
Every 28 years the calendar repeat itself. Hence the first step for year should be to subtract 28, 56 or 84 from the last 2 digits of the year. Adding 25% to get extra numbers is amazing. Wish I knew why it works
It's simple, really. See, a normal year has 1 odd day, and a leap year has 2 odd days. So, let's take the example of a period of 4 years. In those four years, one is bound to be a leap one. (Note that 25% of 4 is 1.) So, we have to add 2 odd days for that leap year. (But we have already counted 1 of those 2 days in the main 4 years.) So, we will take 4+1 (25%) = 5.
Basically, 25% of a period of years are leap years, which have 2 odd days, so we have to add those extra odd days, which we can add by calculating 25% of the years.
I do other cool tricks that aren't heard of very often, for example since this calendar math can be viewed as just a simple addition problem, we can also solve for a missing value using subtraction! For example, if we already know the day of the week to be Friday for example, we can solve for a possible month/months or even a date from 1 to 31 or even a possible year or century. Example: Which month or months did Friday the 13th fall on in 1899? 1899 was a Tuesday year (-2+4=2) or (5-3=2). So, Tuesday was the 10th since 3 days later was Friday the 13th. So, 2+13+x=5 (Friday) x=4 because 15+(-10)=5 -10+14=4 Mod7 arithmetic Only January and October had a month code of 4 😁. So it only happened twice that year, in January and in October. Also we can say more intuitively that since 1899 was a Tuesday year, and Friday being 3 days later, which month/months had the Doomsday of 3,10,17,24,31? and obviously that is only January and October. If the question changed to what were all of the Fridays in January and October for example in 1899? We can say "the 6th, 13th, 20th, and 27th" If someone were to instead ask for example on Friday the 13th from 1883 to 1900 what year/years did that happen? We can say "only in 1893 and 1899" In this situation we just needed to find the missing year code of (4 or -3) and only 93 and 99 have that year code in that date range. Likewise, we could have instead solved for the century 😉 also if already given a year.
Just used your method to find out which months Friday the 13th falls in 2024. Year: 1.25 * 24 = 30. 30%7 = 2. Year + day = 2 + 13 = 15%7 = 1. There are only two months with a value of 4 in order to reach a day value of 5: September and December :) Thank you!
@@allenz0rzer For 2024 this is a Thursday leapyear, because 2+2=4 (Thursday) 2000’s century code is 2 and 24 year code is also 2. Fridays =5 or -2, so…. The equation would be 4+month code+13=5 17+MC=5 or simplified 3+MC=5 MC=2 Only September and December have month codes of 2 so yes September and December only are Friday the 6th,13th,20th, and 27th on a Thursday year like 2002, 2013, 2019, 2024, 2030….. etc. Month codes: Jan 4 or -3 Feb 0 Mar 0 Apr 3 May 5 or -2 Jun 1 Jul 3 Aug 6 or -1 Sep 2 Oct 4 or -3 Nov 0 Dec 2 Leap Jan 3 Leap Feb 6 or -1
Although this math may seem difficult, I don’t actually use this method when I’m solving quickly mentally. Instead I ask myself … In 2024, (Thursday leap year) 4+what =Friday? Obviously 1, and so we are asking for the 13th, so, just subtract 13-1=12 Which to me means that the key days must be 5th, 12th, 19th, and 26th.. The only two months which have these key days are September and December Key days Jan or Oct 3rd, 10th, 17th, 24th, 31st Feb, Mar, or Nov 7th, 14th, 21st, 28th Apr, July, or Jan Leap 4th, 11th, 18th, 25th May 2nd, 9th, 16th, 23rd, 30th Jun 6th, 13th, 20th, 27th Aug or Feb Leap 1st, 8th, 15th, 22nd, 29th Sep or December 5th, 12th, 19th, 26th
Jan 1, 2030. My method requires a bit more memorization but the payoff is super fast and easy calculations like sometimes less than one second maximum 2 seconds! For me a date like Jan 1 is a prememorized value of -2, 2000-2099 has a century code value of 2, and the year 30 always has a value of 2. So, in any order i add -2+2+2=2, or even more advanced, looking ahead that the -2 cancels out with any one of the other the values of 2, so just 0+2=2, or simply 2 without considering the cancelled values, so Tuesday! And whenever leap year, no need to worry about odd days or anything special just subtract 1 from the final answer if January or February, March thru December no changes are necessary.
i hope you could get back to me on this, but could you elaborate a little more, im trying to understand your method, but where are the century codes coming from for example like, 2100 and onward, and how is jan 1 = -2?
may i say one thing (if u don't mind)?... hey MR what r u doing here!!!!??? u must go to participate the upcoming international mental competition, not just to win but also to show your fantastic ability of memorizing...
December code is 4 and the date is 26 so the total is 30. Now 25% of 20 will give 5.25 which is 5, so 20+5=25/7 gives 4. The total is 30+4=34/7 gives a remainder of 6 which is a Saturday
I just simply memorized all 366 possible dates as a value from -3 to 3. Then I just add that to one of 4 possible century codes of 2,0,-2, or 3 and finally add that to a prememorized value for each of the 100 years from 00 to 99. For example, my birthdate of March 19, 1982 goes: -2+3-3=-2 so Friday! Or shortcutting, i just cancel the 3 and -3, and -2 is Friday!
Too much to memorize. About 65 years ago this is what I had learnt in school. Today’s Tuesday June 13, 2023. We want to know the day in 2015. Step 1. 2023-2015=8 Step 2 number of leap years: Take the year before 2015 which is 2012. 2020-2012=8 8/4=2 leap years Add to step1. 2+8=10 10/7 =1 and remainder 3. Go back 3 days from today Tuesday. Answer is Saturday. I’ve done this for the viewers. Hope this helps.
Oh, I accidentally viewed this video and Im a software developer and this trick/algorithm can help me a lot in the future. I didn't know this exists. Thank you so much!
Basic Method: 2012 for eexample. 12 x 0.25 = 3. Leap year so 2. 2 + 12 = 14. 14/7 =2. 2 is code for tuesday. But calnder for jan 1st 2012 shows sudnay?
@mathOgenius hi i love your videos! verry cool but im trying to do one of my siblings dates which is july 20, 2010 but im getting monday but the calender says its tuesday could you please see if im doing something wrong thank you!
Can you do July 4, 2024. It's a leap year, so based on your computation, you have to deduct 1. So 24 x 1.25 = 30, then subtract 1 which is = 29. Then 29+5+4 = 38. 38 divided by 7 = 5 with a remainder of 3. So it should be Wednesday. But actually, looking at the calendar, it is actually Thursday. Can you explain further? Thanks!
Can you show me how to calculate 01/01/1801. Is this correct? 1801 = not a leap year, so January will be value 6 25% of 1 is 0.25 so = 0 0 + 1 = 1 1 plus 1800's year code of 3 = 4 4/7 = 0 with 4 remaining? 1st of Jan = 1 + 6 = 7 7+4 = 11 11/7 = 1 remainder 4 4 = Thursday, which is the correct answer but I'm not sure of the logic
For Year Code And For Example 2061, You Just Found 25% Of 61, And You Didn't Divide It By 4... 25% Of 61 = 15 and 61/4 = 1 61 + 15 + 1 =30 77/7 = 0 0 Will Be CODE For 2061
Finding 25% of a number is the same as dividing the number by 4 because 25% is 25/100 which when simplified is 1/4 which is dividing a number by 4. So, 25% of 61 or 61 divided by 4 is 15.25 which is 15 so so 61+15= 76/7 gives the remainder of 6 so the year code for 2061 is 6
I learned this in 1997. But the month numbers are different. I think maybe it's because this way is based on the 2000's, and the way I learned is based on the 1900's.
Sir, Your skill is Awesome.Appreciations. I have still an easier method by which we can calculate 20 queries in just 5 minutes all by mental calculations. How much time you will take by your method? Please reply. Thank you.
Hi Sir I have a doubt. If we take the year 3467 ( example ) suppose, 5 Feb 3467, we get the answer Monday with this trick. But the real answer is Tuesday. Please help me. 😢
Please see my other replies for a detailed answer. The explanation starting at 2:22 seems to suggest that you subtract 1 in ALL months during leap years but that is not true. The years 2000 and 1992 are leap years so DON'T subtract 1 for months other than January and February. Your months are March and September. I suspect this is the reason you are getting wrong days.
How is there Thursday on sept 14 ,1752? =>Year code will be 6+5=11 (as calendar repeats every 400 years,so we will consider 2152) So 11+14+4=29 29/7=1(remainder) 1= Monday 🤔😢
simple, 52/2 is 26 then 26/2 is 13 , now 13+52 is 65 , divide by 7 we have 2 remainder , add 5 , so 7 , now date is 14, 7+14 is 21 and month code of September is 4 so 25 , now divide by 7 gives reminder 4 , so thursday.
2005 is not a leap year so take 1 and add 6 from January to get 7 and add the year code which is 6 and 13 and subtract 7 over so you get 6 left over so Saturday is your answer.
In the example he used January 1st 2032, there he had to subtract -1. You would also need to do it for 1st of February 2032. Basically for any date on January and February in 2032 you would need to subtract -1. Now move on to the rest of the months for example March or April or May in 2032, you will notice that you don't need to subtract -1 anymore. So I think if you are using the month table table shown in the video you don't need to worry about -1 as the -1 is mentioned in the table
Can you pls find the day of 30 may 2023. Here month code (may) =0 And year code is (2023) =5.75 And i m getting answer 0(sunday) But on google it is showing tuesday.
Ok for the first stragety it's confusing bc Eg January 1 2022 22÷4=5.5 so 5 22+5=27 27÷7=3 rem 6 so Saturday but now let's do January 2nd 2022 22÷4=5.5 so 5 22+5=27 27÷7=21 rem 6 so Saturday but that's not correct bc January 1 was Saturday so it has to be Sunday but it says it's saturday
Your first line is correct. January 1, 2022 is a Saturday. Your second line is not correct. You need to perform the calculation differently on days that are NOT the first day of the year. Since 2022 is not a leap year, the calculation involves adding the month code, the day code and the year code and then dividing by 7. The REMAINDER of that calculation is your answer, not the calculation! Very important. Month code is 6 (from chart) Day code is 2 (January 2) Year code is (22 + 5) ÷ 7 = 3 with remainder 6 so 6 is the year code for 2022 6 + 2 + 6 = 14 ÷ 7 = 2 with remainder 0 = Sunday January 2, 2022 is Sunday
Have fun with this cool Trick!
Thank you 😺
@Ansh pandey that channel is the one in which I just give voice over, my team mate is really busy so I was unable to upload there . Also We are thinking to upload in english too beacuse of demand .
Your voice is best
I have tried calculating 19 aug 2000 using this trick im getting friday , but it is saturday .
@@kriya5723 see august code is 1 , date is 19 so total is 20 , year code is 0 so, 20/7 gives remainder 4 , which is for saturday.
You are a really really smart person, most of my math problems are solved by you , Love from Fiji Islands , Thank you and stay Safe.
glad to help !
Sir, You are the one of the finest math's teacher on UA-cam... :)
Thanks you !
How do you do for 12 August 2004
@@mugaruraronald7684 Thursday
♥️
From where we get 25%
Thank you so much! I just started watching 5 mins ago and I love your content its so help full to me especially because I suck at maths and I hate it but you explain so so so so well it makes everything so so so so much clear than before!! you deserve a sub and like! I think we need more people like you! keep up the good work! :)
The easiest way to do this is to prememorize all 100 year values from 00 to 99. Then I just add that to the century code and reduce mod7 and finally add that to a prememorized value for each of the possible 366 dates. For example, June 15, 2012 would simply be:
2+2+1=5, so Friday!
June 15 always has a value of 2 (prememorized)
2000's has a century code of 2
and,
year 12 always has a value of 1 (prememorized)
2+2+1=5, Friday!
Anytime leapyear happens just subtract one from the answer for January or February only, all other months stay the same!
I calculate any day of the week using my method in less than a second, almost instantly to 2 seconds tops if I'm thinking a bit. I do both the Julian and Gregorian calendars in both AD and BC infinitely into the past or the future.
That's really good! I use a similar technique. For June 15, 2012 above, I work from right to left. So, first I take 2012 and know my adjustment for 2000 is 6. Then, 12 becomes 1. 6+1 casts out to 0. 15 casts out to 1. and June is 5. So, I have 1+5 is 6, which is Friday. (Sunday is 0, Monday is 1, etc.). It's farily quick when you can visually see what numbers are multiples of 7 (cast out 7). My system works from 1500 thru 2300 although I have look at the other centuries. It's the Gregorian calendar.
very cool trick, thanks mathOgenius, you are actually a math genius :D
Every 28 years the calendar repeat itself. Hence the first step for year should be to subtract 28, 56 or 84 from the last 2 digits of the year. Adding 25% to get extra numbers is amazing. Wish I knew why it works
It's simple, really. See, a normal year has 1 odd day, and a leap year has 2 odd days. So, let's take the example of a period of 4 years. In those four years, one is bound to be a leap one. (Note that 25% of 4 is 1.) So, we have to add 2 odd days for that leap year. (But we have already counted 1 of those 2 days in the main 4 years.) So, we will take 4+1 (25%) = 5.
Basically, 25% of a period of years are leap years, which have 2 odd days, so we have to add those extra odd days, which we can add by calculating 25% of the years.
you are by far the easiest to understand math teacher!
Show day of week on March 12 1975
Between 2000 and 2099, rings a bell??? @@maureenjohnson3053
I honestly think that u shud go to any of the TV program where maths is given importance❤️
Go 100K Brudah...!!
I learned a lot from you 💯
Thank you so much for sharing your knowledge with us ❤🎉
This is deceptively simple. Definitely gonna impress my friends with this. Thank you!
I wanna ask if there is a fast method for multiplying, adding, and subtracting decimals
I do other cool tricks that aren't heard of very often, for example since this calendar math can be viewed as just a simple addition problem, we can also solve for a missing value using subtraction! For example, if we already know the day of the week to be Friday for example, we can solve for a possible month/months or even a date from 1 to 31 or even a possible year or century.
Example: Which month or months did Friday the 13th fall on in 1899?
1899 was a Tuesday year (-2+4=2) or (5-3=2). So, Tuesday was the 10th since 3 days later was Friday the 13th.
So, 2+13+x=5 (Friday)
x=4 because 15+(-10)=5
-10+14=4
Mod7 arithmetic
Only January and October had a month code of 4 😁. So it only happened twice that year, in January and in October. Also we can say more intuitively that since 1899 was a Tuesday year, and Friday being 3 days later, which month/months had the Doomsday of 3,10,17,24,31? and obviously that is only January and October.
If the question changed to what were all of the Fridays in January and October for example in 1899?
We can say "the 6th, 13th, 20th, and 27th"
If someone were to instead ask for example on Friday the 13th from 1883 to 1900 what year/years did that happen?
We can say "only in 1893 and 1899"
In this situation we just needed to find the missing year code of (4 or -3) and only 93 and 99 have that year code in that date range. Likewise, we could have instead solved for the century 😉 also if already given a year.
Name checks out
Just used your method to find out which months Friday the 13th falls in 2024.
Year: 1.25 * 24 = 30. 30%7 = 2. Year + day = 2 + 13 = 15%7 = 1. There are only two months with a value of 4 in order to reach a day value of 5: September and December :)
Thank you!
@@allenz0rzer For 2024 this is a Thursday leapyear, because 2+2=4 (Thursday)
2000’s century code is 2 and 24 year code is also 2.
Fridays =5 or -2, so….
The equation would be
4+month code+13=5
17+MC=5 or simplified
3+MC=5
MC=2
Only September and December have month codes of 2 so yes September and December only are Friday the 6th,13th,20th, and 27th on a Thursday year like 2002, 2013, 2019, 2024, 2030….. etc.
Month codes:
Jan 4 or -3
Feb 0
Mar 0
Apr 3
May 5 or -2
Jun 1
Jul 3
Aug 6 or -1
Sep 2
Oct 4 or -3
Nov 0
Dec 2
Leap Jan 3
Leap Feb 6 or -1
Although this math may seem difficult, I don’t actually use this method when I’m solving quickly mentally. Instead I ask myself …
In 2024, (Thursday leap year)
4+what =Friday?
Obviously 1, and so we are asking for the 13th, so, just subtract 13-1=12
Which to me means that the key days must be
5th, 12th, 19th, and 26th..
The only two months which have these key days are September and December
Key days
Jan or Oct 3rd, 10th, 17th, 24th, 31st
Feb, Mar, or Nov 7th, 14th, 21st, 28th
Apr, July, or Jan Leap 4th, 11th, 18th, 25th
May 2nd, 9th, 16th, 23rd, 30th
Jun 6th, 13th, 20th, 27th
Aug or Feb Leap 1st, 8th, 15th, 22nd, 29th
Sep or December 5th, 12th, 19th, 26th
@@thecalendarninja This got my brain to explode. I clearly prefer my method. Thank you and have a great day!
Jan 1, 2030. My method requires a bit more memorization but the payoff is super fast and easy calculations like sometimes less than one second maximum 2 seconds! For me a date like Jan 1 is a prememorized value of -2, 2000-2099 has a century code value of 2, and the year 30 always has a value of 2. So, in any order i add -2+2+2=2, or even more advanced, looking ahead that the -2 cancels out with any one of the other the values of 2, so just 0+2=2, or simply 2 without considering the cancelled values, so Tuesday! And whenever leap year, no need to worry about odd days or anything special just subtract 1 from the final answer if January or February, March thru December no changes are necessary.
i hope you could get back to me on this, but could you elaborate a little more, im trying to understand your method, but where are the century codes coming from for example like, 2100 and onward, and how is jan 1 = -2?
I have recently found your channel have to say You are dammmmm amazing 👏😉😀
Thank you !
Can you give some tips tricks for fast multiplication and division of point numbers (like 1/99=?)
1/99 is so easy it's----0.0101
You can do this easily by taking 1 as 0.9 repeating
Bhaiya :Math is everything !!!!
Me : same ..... We love maths 🙏🙏🙏
Yeah army😁
@@lonely-girl920 😂😂😂 yups 💜
may i say one thing (if u don't mind)?... hey MR what r u doing here!!!!??? u must go to participate the upcoming international mental competition, not just to win but also to show your fantastic ability of memorizing...
Shut up
個人認為，你們是目前世界上最好的數學天才。多謝分享。多謝。
Thank you !
Dec 26 2020..first method.. Reminder is 4..but in calender its different
December code is 4 and the date is 26 so the total is 30. Now 25% of 20 will give 5.25 which is 5, so 20+5=25/7 gives 4. The total is 30+4=34/7 gives a remainder of 6 which is a Saturday
I just simply memorized all 366 possible dates as a value from -3 to 3. Then I just add that to one of 4 possible century codes of 2,0,-2, or 3 and finally add that to a prememorized value for each of the 100 years from 00 to 99.
For example, my birthdate of March 19, 1982 goes:
-2+3-3=-2 so Friday! Or shortcutting, i just cancel the 3 and -3, and -2 is Friday!
i wanna learn you way
Your voice Is so relaxing and you explain so calmly. When I watch Your videos I feel like I am meditating and I learn so much
How to find dates before 1752 considering the eleven day lag?
So how do you calculate the day before 1752? How do you adjust for 11 days
as you mentioned?
Add 11 to the final answer you got it
Solving math in mind is make us feel cool.
Too much to memorize.
About 65 years ago this is what I had learnt in school.
Today’s Tuesday June 13, 2023.
We want to know the day in 2015.
Step 1. 2023-2015=8
Step 2 number of leap years:
Take the year before 2015 which is 2012. 2020-2012=8
8/4=2 leap years
Add to step1. 2+8=10
10/7 =1 and remainder 3.
Go back 3 days from today Tuesday.
Answer is Saturday.
I’ve done this for the viewers.
Hope this helps.
Hi great video. What do I do when numbers are very low, like 2000-2005? I get fractions when I divide by 7 at the end
Do not divide just take the exact number. Like take 5 from 2005 and add the month code and date in it.
@@12vibhor34 you forgot to add 25 percent, rounded off to the lower integer.
Oh, I accidentally viewed this video and Im a software developer and this trick/algorithm can help me a lot in the future. I didn't know this exists. Thank you so much!
sameee lmaooooo
Your flow of video is got damn good now! ;)
for year x
x +x/4 =y
y/7 = z (reminder)
z is year code
4+4+z =a
a/7 = b (reminder)
Can you explain 27 September 1992,it doesn't work for me. It shows Thursday repeatedly
92/2 =23
92+23=115
reminder =3
+ 1(90's)= 4
27+4+4=35
35/7 =0 .....Sunday
Basic Method: 2012 for eexample. 12 x 0.25 = 3. Leap year so 2. 2 + 12 = 14. 14/7 =2. 2 is code for tuesday. But calnder for jan 1st 2012 shows sudnay?
When 14/7 the result is 2, but the remain is 0, so 0 is the code, wich is for sunday
@mathOgenius hi i love your videos! verry cool but im trying to do one of my siblings dates which is july 20, 2010 but im getting monday but the calender says its tuesday could you please see if im doing something wrong thank you!
year code is 5,month code is 5, date is 20 so sum is 30 and dividing by 7 gives remainder 2 for Tuesday.
@@mathOgenius what about 18 december 2003? Is the year code 0?
@@yacinebob4639 its 3
You are the best maths trick teacher in youtube thank you
Can you do July 4, 2024. It's a leap year, so based on your computation, you have to deduct 1. So 24 x 1.25 = 30, then subtract 1 which is = 29. Then 29+5+4 = 38. 38 divided by 7 = 5 with a remainder of 3. So it should be Wednesday. But actually, looking at the calendar, it is actually Thursday. Can you explain further? Thanks!
This channel is a gem 💎
Can you show me how to calculate 01/01/1801. Is this correct?
1801 = not a leap year, so January will be value 6
25% of 1 is 0.25 so = 0
0 + 1 = 1
1 plus 1800's year code of 3 = 4
4/7 = 0 with 4 remaining?
1st of Jan = 1 + 6 = 7
7+4 = 11
11/7 = 1 remainder 4
4 = Thursday, which is the correct answer but I'm not sure of the logic
Yes it's correct
For Year Code And For Example 2061, You Just Found 25% Of 61, And You Didn't Divide It By 4...
25% Of 61 = 15 and 61/4 = 1
61 + 15 + 1 =30
77/7 = 0
0 Will Be CODE For 2061
Finding 25% of a number is the same as dividing the number by 4 because 25% is 25/100 which when simplified is 1/4 which is dividing a number by 4. So, 25% of 61 or 61 divided by 4 is 15.25 which is 15 so so 61+15= 76/7 gives the remainder of 6 so the year code for 2061 is 6
You are doing a great job 👍 keep it up 🙂
You are amazing!! TYSM!! Lots of love from SL
Thank you very much sir we need for 21st century only cuz we may not be alive for and further calculation😂😂 very well explained ❤
OMMS ( Oh My Maths and Science) it is literally amazing trick ( your trick dude)
Oh My Goodness This Guy Is A God For Me Cuz I Used to Hate Math and now I love it. Thanks! My guy
How do you do the calendar which day is 2022
Do it similar to 1800
Sir, how about years ending in 00 - 03 such as 2000 - 2003?
What is the year code for 1700 ?
do it similar to 2100
@@mathOgenius thanks sir!
What are tidal forces? pls explain me .
Which grade r u
You are just awsome
2001 April 1 which day
Please answer using your code
Iam not getting the correct answer
Please reply soon
Thank you
Maja aa gya😁
Bhut maja aa rha hai ase tricks sekh k
Mehrbangi sir ase bedio upload karna k lee a🙂
this man is a genius himself
I learned this in 1997. But the month numbers are different.
I think maybe it's because this way is based on the 2000's, and the way I learned is based on the 1900's.
How do you know what year is a leap year just be looking at the date?
According to Gregorian calendar... The same calendar repeats every 28 years not 400 years once. Check them.
Congrats on 100k bro
Sir, Your skill is Awesome.Appreciations. I have still an easier method by which we can calculate 20 queries in just 5 minutes all by mental calculations. How much time you will take by your method? Please reply. Thank you.
Shall try to do stay blessed thank you for sharing from Sri Lanka
Hi Sir I have a doubt. If we take the year 3467 ( example ) suppose, 5 Feb 3467, we get the answer Monday with this trick. But the real answer is Tuesday. Please help me. 😢
You are a genius. Great work
Which day was on 29 dec 2000
I had been learning this from cls 8 in my Mental Ability Test (MAT) in my coaching institute.
I like that how you talk English it is like quitely speaking English
How do I calculate 5th March 2000? Or 2001? Also I am getting the wrong day of Sep 2 1992. Please solve my problem. Thank you.
Please see my other replies for a detailed answer. The explanation starting at 2:22 seems to suggest that you subtract 1 in ALL months during leap years but that is not true. The years 2000 and 1992 are leap years so DON'T subtract 1 for months other than January and February. Your months are March and September. I suspect this is the reason you are getting wrong days.
How would I calculate the day on 1 February 2080 when all codes add up to less than 7
Nice mr Paryag Sharma sir ❤
YOUU ARE A GENIUS. THANKYOU SO MUCH
gr8 input. i like the most .keep posting
How is there Thursday on sept 14 ,1752?
=>Year code will be 6+5=11 (as calendar repeats every 400 years,so we will consider 2152)
So 11+14+4=29
29/7=1(remainder)
1= Monday 🤔😢
simple, 52/2 is 26 then 26/2 is 13 , now 13+52 is 65 , divide by 7 we have 2 remainder , add 5 , so 7 , now date is 14, 7+14 is 21 and month code of September is 4 so 25 , now divide by 7 gives reminder 4 , so thursday.
@@mathOgenius thank u
@@mathOgenius 25 divided by 7 gives reminder 5, not 4 ??
@@anunnaki-gandi3585 u r actually dumb 7x3=21, 25 -4=21 therefore the remainder is 4
You are super OP
This is so powerful
Thanks sir
Superb calucation thank you
Amazing trick sir thanks 😊
Where does the 25% come from and why do we have to calculate 25%
Thank you sir ❤
Exellent trick thanku so much
How to calculate for 2000 3000 ,if last two digits are 00's
for 3000 do it like 1800's
I can't get this to work. Even the easy part to calculate Jan 1. Use 2050. Not a leap year so 50+25%=62.
62/7=8.857.so which day is that?
Sharma ji ka ladka maths mei awwal hai!!
Thanks man😊🎉❤❤
Thankyou sir 😊
How would you calculate what day is 1 January 2005. Thanks
2005 is not a leap year so take 1 and add 6 from January to get 7 and add the year code which is 6 and 13 and subtract 7 over so you get 6 left over so Saturday is your answer.
5/5/2005 is 6÷7 to get the core #?
So should we do no Know??
Do you always -1 on the day when its a leap year?
I was trying my friends bday and kept getting a day off, it was a leap year.
I am guessing the month table already accounts for -1. And I think -1 applies for jan and Feb according to the table
In the example he used January 1st 2032, there he had to subtract -1. You would also need to do it for 1st of February 2032. Basically for any date on January and February in 2032 you would need to subtract -1. Now move on to the rest of the months for example March or April or May in 2032, you will notice that you don't need to subtract -1 anymore. So I think if you are using the month table table shown in the video you don't need to worry about -1 as the -1 is mentioned in the table
What is the year code for 2002.. I couldn't able to find... Can anyone make it for me
How do we calculate the day when all codes add up to less than 7. Ex: 1 Jan 2080. Thanks
Can you pls find the day of 30 may 2023.
Here month code (may) =0
And year code is (2023) =5.75
And i m getting answer 0(sunday)
But on google it is showing tuesday.
May 30, 2023
Month Code 0
Day Code 30
Year Code = 23 + 5 = 28 ÷ 7 = 4 with Remainder 0
(0 + 30 + 0) = 30 ÷ 7 = 4 with Remainder 2 = Tuesday
Wow awesome good idea 💡!!!
Plz make a series on reasoning
how do i know if its a leap year?
The gregorian calendar was actually created on 1582
i love rhis video...thanks bro
Great.Keep it up😊😊
Ok for the first stragety it's confusing bc
Eg January 1 2022
22÷4=5.5 so 5 22+5=27 27÷7=3 rem 6 so Saturday but now let's do January 2nd 2022
22÷4=5.5 so 5 22+5=27 27÷7=21 rem 6 so Saturday but that's not correct bc January 1 was Saturday so it has to be Sunday but it says it's saturday
Your first line is correct. January 1, 2022 is a Saturday.
Your second line is not correct. You need to perform the calculation differently on days that are NOT the first day of the year.
Since 2022 is not a leap year, the calculation involves adding the month code, the day code and the year code and then dividing by 7.
The REMAINDER of that calculation is your answer, not the calculation! Very important.
Month code is 6 (from chart)
Day code is 2 (January 2)
Year code is (22 + 5) ÷ 7 = 3 with remainder 6 so 6 is the year code for 2022
6 + 2 + 6 = 14 ÷ 7 = 2 with remainder 0 = Sunday
January 2, 2022 is Sunday
What if the remainder is 0. Ex: 1 December 2056. How do you work this out
0 is equals saturday my g
how to know that a particular is leap year sir?
it should be divisible by 4 and the second condition is it its in 100's it should be divisible by 400.
I know this is 2 years old, but if you see this question, could you maaaaybe explain why do we need exactly 25%
I am incorrectly getting Saturday for 24 February 2288 as it is not a leap year. The answer is Friday. Please explain. Thanks
it is a leap year
do u have ways to solve linear simultaneous equations ?
yes there is a video on this channel on word problems , look at that
bro Pls reply me
What is your qualifications in college .....in math.....reply