Hello mam ur video helped me lot but u got questions ❓ how did u divide total resistance 10:05 i didn't got u .. can u plz explain me that how u got valur of 0.038
Hi. your last problem has a bit of an issue. starting at 16:15 you say that "more resistance, less current" and that the 12R will get half as much current as the 6R because it's double the size. cool so far. Your very next calculation then incorrectly shows the opposite happening. Then when you go to solve that parallel resistor section in a different way, you end up saying that the 6R gets one third of an Amp and the 12R gets two thirds, which is also incorrect. It should read that the 6R gets 1/3A and the 12R gets 1/6A. the formula is I1 = (Rt/R1)*It and Rt for that section is 4ohms. so its ((4/6) *.5) = 1/3A and ((4/12)*.5)= 1/6A.
Well done, you mentioned current being the constant (in ohm's law)!, I thought it was resistors that was introduced after the proportional symbol was removed and a constant( resistance) was Introduced?
Because the 12-ohm resistor is 2x the resistance of the 6-ohm resistance, it will get half as much current. Since the total current is 0.5A, if we divide it by 3 we can give the 6-ohm half the resistance (0.17 amps) and the 12-ohm twice that (0.33 amps). Basically, using the proportionality to get there. A better way would have been solving for the equivalent resistance (1/R= 1/12 + 1/6; R=4), then multiplying by the current (0.5 A* 4 ohms= 2 V) to get the voltage drop, then using V/R=I to get the individual currents. (2V/6= 0.33A and 2V/12= 0.17 A)
Here's two other's I have that touch on it- more lecture style, but the conceptual one will help out a lot with remembering how the laws work- ua-cam.com/video/oH9w7jZt12c/v-deo.htmlsi=7i8huLTXmtqGwh1m ua-cam.com/video/tpheicgkW4E/v-deo.htmlsi=vsmsMaerYWa0q615 Glad I could help! I'm going to try and make some more just straight practice videos soon!
Depends on which type of circuit- in a parallel, typically you know its the same as the voltage of the battery (in a simple parallel), where in a series you typically solve for current first using the total resistance, then use V=IR, with the individual resistances to calculate the voltage drops.
Yup! One of the things I love about circuits is there is multiple ways to solve it- its a puzzle to see the easiest/ way that makes the most sense in your brain!
I had the full number stored in my calculator - 1/0.038888888888 is 25.7, one of those instances where significant figures make a noticeable difference!
I had the full number stored in my calculator- 1/0.038888888888 is 25.7, one of those instances where significant figures make a noticeable difference!
Depends, what other information are you given? If you have current and resistance, use V=IR, if it’s a simple parallel, equal to battery voltage, anything more complex would need more steps
Maybe this video will be a good place to start? It's my attempt to explain circuit conceptually, so the math makes more sense. ua-cam.com/video/oH9w7jZt12c/v-deo.htmlsi=negipWxhGFTP_Ng7
got mid term test 2morrow i been lackin big time . this video made me understand this alot more than in class . thanks a lot
Yay! Glad I could help!
Thank you for helping me complete my electronics in electric vehicles
Thank you for explaing.
thank you show much, your video made it clear for me to do the problems that i have been doing for weeks
recommend this video for everyone.
thanks
I'm glad it was helpful!
It's very helpful video I'll full understand
Thank you I finally understand this, your a life saver
Glad i could help!
Thank you 🙏. I really learnt a lot. Ur breakdown of this topic is top notch
Oh my goodness I couldn’t understand anything about this, but you made this so easy to understand!
Thank you! 😁😁😁
Glad it helped!
Wow nice explanation
you taught this better than my teacher thx so much!
Happy to help!
Not sure how you got 25.7 ohms at 10:26... my math provided an Rt of 26.31. Regardless- thank you for your help.
1 divided by .038 equals 26.31 but 1 divided by .0388 is 25.7
I'm with you on that. I was wondering the same thing.
@@clutch-400 so... is the answer 26.315? I'm a little upset that answer is 25.7 ! I think that the answer should be 26.315 !
once you get your resistance total in the fractional form you should do the reciprocal of those numbers and then divide to ger your final answer
Mine too
Hello mam ur video helped me lot but u got questions ❓ how did u divide total resistance 10:05 i didn't got u .. can u plz explain me that how u got valur of 0.038
Hi. your last problem has a bit of an issue. starting at 16:15 you say that "more resistance, less current" and that the 12R will get half as much current as the 6R because it's double the size. cool so far. Your very next calculation then incorrectly shows the opposite happening. Then when you go to solve that parallel resistor section in a different way, you end up saying that the 6R gets one third of an Amp and the 12R gets two thirds, which is also incorrect. It should read that the 6R gets 1/3A and the 12R gets 1/6A. the formula is I1 = (Rt/R1)*It and Rt for that section is 4ohms. so its ((4/6) *.5) = 1/3A and ((4/12)*.5)= 1/6A.
Yup! Great explanation
Well done, you mentioned current being the constant (in ohm's law)!, I thought it was resistors that was introduced after the proportional symbol was removed and a constant( resistance) was Introduced?
thank you so much. This helps me understand a lot more
Well explained. Thank you😊
How did you come up w .333 and .17 @time 17:43 ? Thx
Because the 12-ohm resistor is 2x the resistance of the 6-ohm resistance, it will get half as much current. Since the total current is 0.5A, if we divide it by 3 we can give the 6-ohm half the resistance (0.17 amps) and the 12-ohm twice that (0.33 amps). Basically, using the proportionality to get there. A better way would have been solving for the equivalent resistance (1/R= 1/12 + 1/6; R=4), then multiplying by the current (0.5 A* 4 ohms= 2 V) to get the voltage drop, then using V/R=I to get the individual currents. (2V/6= 0.33A and 2V/12= 0.17 A)
Thank-you for helping me,,any video for calculating equivalent resistance from the original circuit
I'm not sure what you mean, but you can think of the total resistance as the equivalent resistance of all the resistors in the circuit!
Thank you I need this for my union classes. Do you have anymore on parallel and series? I couldn’t find anymore? Thank you
Here's two other's I have that touch on it- more lecture style, but the conceptual one will help out a lot with remembering how the laws work- ua-cam.com/video/oH9w7jZt12c/v-deo.htmlsi=7i8huLTXmtqGwh1m ua-cam.com/video/tpheicgkW4E/v-deo.htmlsi=vsmsMaerYWa0q615 Glad I could help! I'm going to try and make some more just straight practice videos soon!
Thank you so much for saving my college fees not to go free😊
Yay glad I could help!
I’m from Kuwait and this helped me so much we speak Arabic but learn it in English idk why
Glad I could help! And i don't know either... I always feel bad for my students who are having to learn in English before they speak it fluently!
Very nice presentation. But at the end when adding up the currents you said it was for a series circuit, when in fact it is a parallel circuit.
Thanks! And that sounds about right… oops! Thanks for pointing out the error!
Hope this isnt a silly question but, any chance you have a tutorial on how to do electrical calculations on an iPhone?
Do you mean like using the calculator on your phone? Not sure quite what you are looking for... but I don't think so...
Yes pull down from top for calculator, then turn phone 90 degrees for scientific calculator.
The 1/x is the reciprocal function. Hope this helps.
How u calculate the voltage drop across each rezistor
Depends on which type of circuit- in a parallel, typically you know its the same as the voltage of the battery (in a simple parallel), where in a series you typically solve for current first using the total resistance, then use V=IR, with the individual resistances to calculate the voltage drops.
@@KcoolScience u can also calculate in paralel per rezistor
@georgegeorgel7254 in a parallel circuit its gonna be the same across each resistors
Really clean expression. Thanks to you :)
Awesome- glad it was helpful!
I you separately solve v divided by each resistance it gives you each individual current then add them up and it gives you total current
Yup! One of the things I love about circuits is there is multiple ways to solve it- its a puzzle to see the easiest/ way that makes the most sense in your brain!
Do you have a video for combination circuits? if not can you do one?
There is a combination circuit at the end, but I can make one with more complex circuits!
Thanks now I understand 🎉
Hello. I am new to parallel circuits and I am lost on how you got 25.7 ohms. The closest I got was 25.64 ohms. Solved.
I had the full number stored in my calculator - 1/0.038888888888 is 25.7, one of those instances where significant figures make a noticeable difference!
@@KcoolScience Thanks. Do you have videos on Kirchoffs loop law? Like solving for two batteries on a parallel circuit? Thank you for the videos.
Parallel is 6+12/12×6? 14:39 why 4ohms?
I guess here is some mistake of her.
What about the the prospective fault current and prospective short current whats the difference between them?
I will be honest, I have never heard either of those terms before(i teach at the high school level, degree is in chem not physics), so I don't know!
Again how do you get 25.7....... 1/ 0.038 I get 26.3 when I decide 1 by 0.038. what did you do to get the final number ?
I had the full number stored in my calculator- 1/0.038888888888 is 25.7, one of those instances where significant figures make a noticeable difference!
Thanks, great explanation
Glad it was helpful!
If the Voltage isn't present how do you find it?
Depends, what other information are you given? If you have current and resistance, use V=IR, if it’s a simple parallel, equal to battery voltage, anything more complex would need more steps
Very helpful thanks 🙏
Glad i could help!
Thank you . Well explained
Yeah something like that. Lol I'll keep searching for combination explanations. I think I got it tho. Thanks
how did you get 25.7????
As explained in a previous comment, I made a rounding error and used "0.038" instead of "0.038888," 26.31 Ohms would be more precise.
Tysm i have a exam at next week Thursday
The last step was reversed. It should be 2 volts/6 ohms(.333) plus 2 volts/12 ohms (.166) = 0.5A
Oops!
14:28 should be .25 ohms not 4. Great video and thank you for the information!
Thanks for the help
Thank u very much
@11:17 same haha
Quite confusing how comes 3/12= 4 ohms
Reciprocal hun Rtot=12/3=4
It’s the inverse! 1/Rtotal= 3/12 (so really 12/4= 3)
Thank you
So amazing
Thank you!
Amoung?
HOW DID YOU GET 25.7? I THINK YOU COMPUTE IT WRONG?
As explained in a previous comment, I made a rounding error and used "0.038" instead of "0.038888," 26.31 Ohms would be more precise.
I’m gonna get kicked outa the school
Lmao
Thanks for the teaching me
My pleasure!
Good video tho the keyboard lol 😢
Apologies educative
Lol. I can't spell half the time myself...And I used to win spelling bees along time ago!
And this is why I don't teach English!
still confused
You are so sweet ❤️❤️❤️
You are so kind! 🥰
Iam lost
Maybe this video will be a good place to start? It's my attempt to explain circuit conceptually, so the math makes more sense. ua-cam.com/video/oH9w7jZt12c/v-deo.htmlsi=negipWxhGFTP_Ng7
This is horrible
Thank you!!
You're welcome!
Thank you