in minute 6.00 you didn't rearrange the carbcation from secondary to tertiary. is this just to complete the example about the secondary substrate or this is the right mechanism of this reaction? because if you rearranged the carbcation the product would be different.
How are we supposed to know when the nucleophile splits up and when it doesn't? Also, for the 3rd reaction, how did you know to use the double bonded O for bonding as opposed to the one part of the alcohol group (I've always seen the alcohol group referred to as the nuceophile)??
He had to do it because he is showing an SN1 reaction. If he deprotonates the oxygen like you're saying, then he'll have a strong nucleophile which will then go thru an SN2. I think he picked a complicated example that's a little confusing.
I have a feeling that the mechanism for that reaction isn't the best. If you think about it, he has to use the carboxylic acid as is, so that the nucleophile is not too strong (because he is showing SN1). That's why he didn't deprotonate the hydroxyl group there. It's not the best example he could come up with.
No. Iodide is a good leaving group because it's a very weak Bronsted base. Not all strong nucleophiles are also strong bases, even though almost all strong bases are good nucleophiles.
Hi khan. Can tell me the name of program you are doing courses and lessons on youtube? I want it for writing drafts and structure of molecules. Thankd bro
U briefly understand the meaning organic substrate how they react with solvent attacking the nucleophile to form the stable products however the product formed need some help of writing the trickiest stru.
in minute 6.00 you didn't rearrange the carbcation from secondary to tertiary. is this just to complete the example about the secondary substrate or this is the right mechanism of this reaction?
because if you rearranged the carbcation the product would be different.
how would you rearrange the substrate to tertiary?
@@herbertgunther8951 hydride shift
@@kyle9008 is not possible with this substrate, or do i overlook sonething?
@@herbertgunther8951 It's a benzene ring. You're right. Can't put a positive charge there.
How are we supposed to know when the nucleophile splits up and when it doesn't? Also, for the 3rd reaction, how did you know to use the double bonded O for bonding as opposed to the one part of the alcohol group (I've always seen the alcohol group referred to as the nuceophile)??
He had to do it because he is showing an SN1 reaction. If he deprotonates the oxygen like you're saying, then he'll have a strong nucleophile which will then go thru an SN2. I think he picked a complicated example that's a little confusing.
can`t water deprotonate formic acid and the O- is then the nucleophile?
I have a feeling that the mechanism for that reaction isn't the best. If you think about it, he has to use the carboxylic acid as is, so that the nucleophile is not too strong (because he is showing SN1). That's why he didn't deprotonate the hydroxyl group there. It's not the best example he could come up with.
Sir how can i get hindi or Gujarati languages videos
in the first example, isn't iodide a bad leaving group because in a protic solvent like ethanol, iodide is a strong nucleophile?
No. Iodide is a good leaving group because it's a very weak Bronsted base. Not all strong nucleophiles are also strong bases, even though almost all strong bases are good nucleophiles.
What happens if you have weak nucleophile but polar aprotic solvent?
sn1
Hi khan. Can tell me the name of program you are doing courses and lessons on youtube? I want it for writing drafts and structure of molecules. Thankd bro
Zak, did you get the answer? I also want to know the name of the program.
U briefly understand the meaning organic substrate how they react with solvent attacking the nucleophile to form the stable products however the product formed need some help of writing the trickiest stru.