My chemistry teacher idolises you and constantly tells us to watch your videos when going over the subject after we are done, it was a great advice from her :)
Sir are u considering of entering for the Pearson teaching awards and other online teacher awards . We will vote for you ! Last time , hegarty maths won....
I've been watching these videos and they've made SO MUCH stuff just click in my head that my teachers never had the ability to do. Thanks so much for doing these and after my exams I'm going to buy you so many mansions and helicopters :P
There's something special about teaching people this level of stuff in a way that makes the majority of people be able to understand. Too many teachers have a job they can't do, they know the subject but fail to TEACH it, often feels like someones just reading you a book and you're left scratching your head. Thank you for this video, have subscribed and will be looking at the others, us med students that have robot professors appreciate it!
watched every video on chem 2 the day before my exam last year, went from less than 5 marks to a D which isnt bad for a nights work, thanks for the great vids.
I just wanted to thank you so much for everything that you've done I just had my chemistry As unit 2 paper and because of all of your videos and your effort that you putted into it I'm hopeful. Again thank you so much!
Very useful! Ty so much. I have a mock exam tomorrow and am the dumbest in my class, lol not anymore I tell ya! Can't wait to prove them haha you have given me a much neededed confidence sir Ty so much
This is so helpful thank you so much! Will be letting all my friends know that your videos are amazing! Nervous for the chemistry exam in May but hopefully i do well!!
Sia Sutha ॐ Ah excellent - thank you so much! Fingers crossed! BUT, do plenty of work in preparation and your chances of doing well will be much higher!
I really appreciate you spending time making these videos. They are really helpful. You explain really difficult concepts and make them sound so simple! Thank you so much, will definitely be subscribing!
For the new spec, do we specifically need to know the production of methanol, haber process, contact process and hydration of ethene to produce ethanol and the equations for these?
E Rintoul. Would there be no change in equilibrium if the number of moles on both sides of the revesible reaction are equal when there is an overall change in pressure?
Mo Tayee Oh dear, didn't realise I had missed it. It's the same concept entirely. If you increase the concentration of one of the reactants, the position of equilibrium will shift in order to oppose the change and so will remove more of that substance. That make any sense?
Exothermic releases heat. Therefore when you decrease the temperature the equilibrium will shift to the exothermic reaction so that the mixture will become warmer to oppose the decrease in temperature.
Kind of the wrong video to post this on, but could you do a video of all the reagents we need to know for the exam e.g. silver mirror test, NaOH and their conditions?
***** It's something that I may consider as it is actually required for A2. I think it will probably go near to the bottom of the list for now though - sorry!
I would just like to say that your videos are so helpful! I also have a quick question as I always seem to struggle with equilibria.. Each time the temperature decreases, does the yield always increase? Hence, when the temperature increases, does the yield always decrease? Sorry if that's a silly question, I just can't seem to get my head around it -_-
how do you work out which way is endo and which was is exo for the temperature equilibrium. Is it using the enthalpy change? E.g- working out exothermic-- if its a minus number, its right, if its a positive, its left? If so, will the enthalpy change be given in exam? Thanks again sir
+TechnoJord99 Yeah, the enthalpy change that is given will always be for the forward reaction (left to right) or it will be specified as to which reaction of the 2 in the equilibrium. If it is negative, it's exothermic and if it's positive then it's endothermic. Obviously if the forward reaction is exothermic, then the backward reaction will be endothermic by that exact same amount. And yeah, you'll be given all data in the exam! Has that helped?
moneyhoneyhoney That's a good question... Stick with pressure as described in the video for gases. The concentration works in a similar way in that the position of equilibrium will shift to reduce the change, but it doesn't work as per the molar ratios of the pressure examples.
A Dahir It's all about Le Chatelier's principle. If we decrease the temperature of the (closed) system, we are removing energy from it. The reaction, according to the principle, will shift its position of equilibrium in order to oppose this decrease in temperature. So, it will shift into the exothermic direction in order to favour that reaction, causing more energy to be move from the reactants to the system. Does that make any sense?!
why does decreasing the temperature cause the equilibrium to shift towards to exothermic direction of the reaction? surely that would result in more temperature loss? very confused :(
never mind. ive just realised if the half of the reaction which is RELEASING energy is favoured then the overall reaction will have a higher energy. Dumb moment!
But if you oppose change, then if the temperature is decreased, would you not want an increase in temperature so it would be endothermic to get more heat?
A + B ⇌ C + D (forward reaction is exothermic) If the temp decreases, equilibrium shifts to the right, so it 'favours' the right hand side reaction. When you say it favours the right hand side reaction, do you mean it is favouring the *production* of C+D, or do you mean the reaction between C+D (to produce A+B) is favoured?
production of c+d becuz it creates heat to surroundings as its exothermic. this followes le shat eleier principle as it opposes the temp decrease by creating more heat in the closed system mate
Will all the species in the reaction always be gases? If they are not would we treat the reaction in the same way when deciding on the shift in equilibrium for a pressure change? Also, will we always be given the delta H values for the reaction to determine which way is exothermic/endothermic (how do we determine this if we are not given these values)? Oh and great videos by the way! :)
mariobros920 Hi! Yeah, I think they will use gases. And yep, you will always be given some idea as to in which direction the reaction is exo or endothermic. That helped?!
Imagine that decreasing the temperature removes energy from the system. The equilibrium shifts to undo that change. Therefore it needs to put energy back into the system. Exothermic reactions release energy and therefore increasing this reaction will add energy to the system.
Hey, Could you possibly make a video explaining Transition metals (hopefully soon) that would be much appreciated! it is by far the hardest most complicated topic I have ever come across and I just can't seem to get my head around it :| Thankyou!
Fatima Ali I'll try and reply to both of your comments here! With regard to your first comment, it's not easy enough to just say that a decrease or increase in temperature will increase or decrease the yield. To work that out we need to know about the equilibrium, namely in which direction the reaction is endo- or exothermic. For example, imagine that I have an equilibrium where the forward reaction (the one that moves from left to right) is exothermic. If I decrease the temperature of the system, the position of equilibrium will shift in order to rectify the changes that I have made. In this case the shift will be to the right (another way to say this is that the forward reaction would be favoured). The reason for this is that by me decreasing the temperature of the system, I have essentially removed so of the heat energy that was present. The equilibrium does not like this and so it acts to replace some of that heat energy. This is where it is important for us to know in which direction the reaction is exothermic. An exothermic reaction releases heat energy to the system/surroundings and so this reaction will replace some of that lost heat energy. In terms of yield, imagine that the equilibrium is A == B (where == is the equilibrium sign). In my example where a decrease in temperature shifts the equilibrium to the right (favours the forward reaction), the yield of B would increase. Does that help you at all?
Jyoti Hi there. I'm pretty sure that you don't need to learn the equations and conditions. It's more a case of applying your knowledge to a given equation!
Thank you so much for making these videos, they're a big help I wanted to ask, do we need to know about specific industrial reversible processes and details on them (e.g. ammonia production occurs at 450C) or will we be given the information on them? Thanks
+E Rintoul because my school payed for a webinar so an examiner would explain to us what they look for and someone interrupted which sounded a lot like you
+E Rintoul not really maths mic wasn't loud enough and someone watching was just telling him how to make it louder so we could hear and since we only hear your voice in your videos (which are amazing by the way) I immediately thought it was you and a lap which city do you teach in
E.g. - I2 + 2OH I + IO + H20 :Increasing the conc (OH- ions) causes the equilibrium to shift to oppose this and move in a forward direction to remove additional ions(OH-). The position of equilibrium will shift towards the right giving a higher yield of the other product (I- + IO)
+Hashim Munir I'm afraid that I don't have them for this one. I do mean to get my act together and get some proper notes made for each topic, but it's something that will more than likely have to happen over summer!
Atul Hasan Unfortunately, I can't! It's my natural way of speaking and to slow it down would mean that the videos would be much longer. By all means, as the magic of UA-cam allows, slow me down or just go back to points are re-listen!
Atul Hasan Adding captions to every part would more than likely double the time it takes to make each video! If this was my sole profession then I may, but it isn't! As time goes on I will more than likely develop them further to put more stuff into them, but for now, that can't happen!
Not gonna lie, learned more from you in about 3 hours than I have from my teacher in 8 months
rip
+Naser Alomoush Ikr, my school's in special measures ahaha
same as my friend... good luck and +respect to you :)
+Naser Alomoush Good luck as well man, watching these videos has certainly helped
+Naser Alomoush How did it go man?
I can't believe I finished 4 topics in 6 hours. Most productive studying ever
Been 4 years, how are you doing in life?
Lol I can finish 4 topics in 6 days
Your comment Motivated me to study
Been 2 years, how you doing in life?@@tywinislitandeddard9988
@@tywinislitandeddard9988 Been 3 years how u doing?
My chemistry teacher idolises you and constantly tells us to watch your videos when going over the subject after we are done, it was a great advice from her :)
+Alejandra Rodrígues That's ace! Tell her thanks from me!
Sir are u considering of entering for the Pearson teaching awards and other online teacher awards . We will vote for you !
Last time , hegarty maths won....
Abu Bardewa What's that? I'd feel like a fraud entering something like that!
No it's like online voting for best online free tutors .
Abu Bardewa Oh. Hmm. So I have to put myself forward?!
Kinda yes!😃
Anyway u deserve it .... So we will vote for u if u do it for next year.
I've been watching these videos and they've made SO MUCH stuff just click in my head that my teachers never had the ability to do. Thanks so much for doing these and after my exams I'm going to buy you so many mansions and helicopters :P
Matt Denton Well that's a good thing!
Honestly, I learned more from you in thirty minutes than my teacher in two whole lessons. Thank you so much! Keep up the awesome work.
absolute legend, got my exam tommorow, and you have made me feel way more confident with it. Thank you!
There's something special about teaching people this level of stuff in a way that makes the majority of people be able to understand. Too many teachers have a job they can't do, they know the subject but fail to TEACH it, often feels like someones just reading you a book and you're left scratching your head. Thank you for this video, have subscribed and will be looking at the others, us med students that have robot professors appreciate it!
watched every video on chem 2 the day before my exam last year, went from less than 5 marks to a D which isnt bad for a nights work, thanks for the great vids.
+Wezley Richards so did you get an E?
+Bhavik Bhardva D lol
Not bad I guess since you only revised a day before
I wont be making the same mistake this time a round though its not worth the risk
I just wanted to thank you so much for everything that you've done I just had my chemistry As unit 2 paper and because of all of your videos and your effort that you putted into it I'm hopeful.
Again thank you so much!
Arige Hassan No problem! But it's your hard work that has helped!
nice you should have more views then what you originally have and more subscribers.
M Hussain I would certainly like more views and more subscribers! By all means spread the word haha! And thanks for the kind words.
one thing (out of many) i have learnt today: a closed system does not have to be in area 51 !!!
You just saved my life. I have chemistry tomorrow by 1:45pm.
Im very late but still how your exam went?
@@manoharamurthy9923 lol you are 6 years late but it’s cool.
did it go well?
it's been 10 years but these videos are still as helpful as ever
Watching this 2 hours before exam. Thankful for the mere existence of this channel
MANS almost finished half the AS course in 4 hours
u r a very good teacher with eloquent explanations
extra note: u sound so much like Rupert Grint :}
Very useful! Ty so much. I have a mock exam tomorrow and am the dumbest in my class, lol not anymore I tell ya! Can't wait to prove them haha you have given me a much neededed confidence sir Ty so much
Looool 2 years later i find myself in your position. Hope you did well lmao.
and a year later i end up in yours, good luck loool
three years later i am in your position
And here I am after a year
here, I am after 5 years and I'm still not in the zone
This is so helpful thank you so much! Will be letting all my friends know that your videos are amazing!
Nervous for the chemistry exam in May but hopefully i do well!!
Sia Sutha ॐ Ah excellent - thank you so much! Fingers crossed! BUT, do plenty of work in preparation and your chances of doing well will be much higher!
Ngl "the rat as it would seem" killed me😂😂😂
I really appreciate you spending time making these videos. They are really helpful. You explain really difficult concepts and make them sound so simple! Thank you so much, will definitely be subscribing!
I am struggling a lot with chemistry, so thankyou so much ! Exam tomorrow , wish me luck
Vanessa Saliba Bit late, but good luck! How did you do?
How was it
@@abdallatefnsour lol
@@MrERintoul bro its done out for u she aired u for over 6 years
You taught me things I didn't knew about , thanks
So low temp will be really slow and high pressure is very costly. So would u increase the yield then.
For the new spec, do we specifically need to know the production of methanol, haber process, contact process and hydration of ethene to produce ethanol and the equations for these?
7:03 temperature, pressure as well as CONCENTRATION are factors.
a002 thanks.
You sir, are the most hopeful person on youtube, Bravo!
Well that is high praise indeed - thank you!
You said you will talk about compromise medium
You're actually the best person for this, thank you so much!
This is all i need, thank you and do u have a chem blog with more stuff on that topic?
you are so helpful........ word cant explain how thankful i am for you help ..
emmaculate Zvovuno Thank you! :)
E Rintoul. Would there be no change in equilibrium if the number of moles on both sides of the revesible reaction are equal when there is an overall change in pressure?
Honestly u are the best sir! May god bless u with everything in this world
Hi! Brilliant video but you forgot to mention concentration, what happens with it?
Mo Tayee Oh dear, didn't realise I had missed it. It's the same concept entirely. If you increase the concentration of one of the reactants, the position of equilibrium will shift in order to oppose the change and so will remove more of that substance. That make any sense?
Brilliant yep! Just practiced past papers questions and picked up the concept, thankyou!
How will decreasing temperature favour an exothermic reaction?
Exothermic releases heat. Therefore when you decrease the temperature the equilibrium will shift to the exothermic reaction so that the mixture will become warmer to oppose the decrease in temperature.
Kind of the wrong video to post this on, but could you do a video of all the reagents we need to know for the exam e.g. silver mirror test, NaOH and their conditions?
***** It's something that I may consider as it is actually required for A2. I think it will probably go near to the bottom of the list for now though - sorry!
E Rintoul hi
I would just like to say that your videos are so helpful! I also have a quick question as I always seem to struggle with equilibria.. Each time the temperature decreases, does the yield always increase? Hence, when the temperature increases, does the yield always decrease? Sorry if that's a silly question, I just can't seem to get my head around it -_-
binged this for a week and got a b on my first mock
how do you work out which way is endo and which was is exo for the temperature equilibrium. Is it using the enthalpy change? E.g- working out exothermic-- if its a minus number, its right, if its a positive, its left?
If so, will the enthalpy change be given in exam?
Thanks again sir
+TechnoJord99 Yeah, the enthalpy change that is given will always be for the forward reaction (left to right) or it will be specified as to which reaction of the 2 in the equilibrium.
If it is negative, it's exothermic and if it's positive then it's endothermic.
Obviously if the forward reaction is exothermic, then the backward reaction will be endothermic by that exact same amount.
And yeah, you'll be given all data in the exam!
Has that helped?
massive help as always, thank you very much
If the temperature increases will the yield decrease
Brilliant video again.
One question though is the increase in concentration going to have the same effect as an increase in pressure for gases has?
moneyhoneyhoney That's a good question... Stick with pressure as described in the video for gases. The concentration works in a similar way in that the position of equilibrium will shift to reduce the change, but it doesn't work as per the molar ratios of the pressure examples.
Thank you so much for your videos. Just wanted to ask why decreasing temperature would make the reaction want to lose heat?
A Dahir It's all about Le Chatelier's principle. If we decrease the temperature of the (closed) system, we are removing energy from it. The reaction, according to the principle, will shift its position of equilibrium in order to oppose this decrease in temperature. So, it will shift into the exothermic direction in order to favour that reaction, causing more energy to be move from the reactants to the system. Does that make any sense?!
i have an exercice but it's about the pressure change and they don't give out the enthalpy...
why does decreasing the temperature cause the equilibrium to shift towards to exothermic direction of the reaction? surely that would result in more temperature loss? very confused :(
never mind. ive just realised if the half of the reaction which is RELEASING energy is favoured then the overall reaction will have a higher energy. Dumb moment!
But if you oppose change, then if the temperature is decreased, would you not want an increase in temperature so it would be endothermic to get more heat?
Thanks this helped a lot. Just a question, my text book says the equation for Methanol is
2H2 + CO CH3OH
Is this still right?
Boro Jen xX That is an equation to form methanol, so I'm going to say yes!
A + B ⇌ C + D
(forward reaction is exothermic)
If the temp decreases, equilibrium shifts to the right, so it 'favours' the right hand side reaction.
When you say it favours the right hand side reaction, do you mean it is favouring the *production* of C+D, or do you mean the reaction between C+D (to produce A+B) is favoured?
Production of C+D
production of c+d becuz it creates heat to surroundings as its exothermic. this followes le shat eleier principle as it opposes the temp decrease by creating more heat in the closed system mate
Will all the species in the reaction always be gases? If they are not would we treat the reaction in the same way when deciding on the shift in equilibrium for a pressure change? Also, will we always be given the delta H values for the reaction to determine which way is exothermic/endothermic (how do we determine this if we are not given these values)? Oh and great videos by the way! :)
mariobros920 Hi! Yeah, I think they will use gases. And yep, you will always be given some idea as to in which direction the reaction is exo or endothermic. That helped?!
Yeah that's great, thank you!!
Thank you very much for this video! i just wanted to ask how similar this is to the IBDP SL chemistry course.
awsomeguy178 Absolutely no idea! Never heard of it... I suggest you pull up the specifications and have a look at them side-by-side.
Hi, thanks for the video, what would happen if you change the concentration of one side of the equilibrium?
Love your videos . So helpful for revision . Absolute legend
Do you still get marked if you're answer is a very bullet pointed and almost 'note taking' like taking answer?
You saved my life ty
when answering questions about pressure, how do you know which side has more moles ?
the big numbers
9:58 I don’t get how he said if you decrease temperature it favours the exothermic can someone please explain
Imagine that decreasing the temperature removes energy from the system. The equilibrium shifts to undo that change. Therefore it needs to put energy back into the system. Exothermic reactions release energy and therefore increasing this reaction will add energy to the system.
Eliot Rintoul thank you sir
I got all that, but what im confused is that what happens when there is solid or liquid involved what do you do then? Really sad, help me :(
thanks for the uploads, very helpful :)
Not a problem!
Hey, Could you possibly make a video explaining Transition metals (hopefully soon) that would be much appreciated! it is by far the hardest most complicated topic I have ever come across and I just can't seem to get my head around it :|
Thankyou!
icegirl901 I shall try to, yes!
thank you :)
Are you making a video on Group 7?
Going to try and get it done about 11.30 today!
4:44 I'm watching this on 1.5x speed and when he said it like that it sounded so funny pls guys you should try it 🤣
also, very helpful video .
How will you know whether the yield increases or not?
Fatima Ali I'll try and reply to both of your comments here!
With regard to your first comment, it's not easy enough to just say that a decrease or increase in temperature will increase or decrease the yield. To work that out we need to know about the equilibrium, namely in which direction the reaction is endo- or exothermic.
For example, imagine that I have an equilibrium where the forward reaction (the one that moves from left to right) is exothermic. If I decrease the temperature of the system, the position of equilibrium will shift in order to rectify the changes that I have made. In this case the shift will be to the right (another way to say this is that the forward reaction would be favoured).
The reason for this is that by me decreasing the temperature of the system, I have essentially removed so of the heat energy that was present. The equilibrium does not like this and so it acts to replace some of that heat energy. This is where it is important for us to know in which direction the reaction is exothermic. An exothermic reaction releases heat energy to the system/surroundings and so this reaction will replace some of that lost heat energy.
In terms of yield, imagine that the equilibrium is A == B (where == is the equilibrium sign). In my example where a decrease in temperature shifts the equilibrium to the right (favours the forward reaction), the yield of B would increase.
Does that help you at all?
Thank you so much, it makes everything more clearer
Fatima Ali I'm very glad! Give me a shout if you need any help with anything else.
Hi! Doesn't the temperature decrease even more when the energy is released?
This is brilliant! Thanks so much :)
thanks so much! this has really helped me :)
Resha Pillai yup
If the products had more moles, and you were trying to get maximum yield, would you use high or low pressure?
low pressure mate
2:20
This is more relevant in 2019 (if you know what I mean)
do i need to learn the equations???
and the compromise conditions?
Jyoti Hi there. I'm pretty sure that you don't need to learn the equations and conditions. It's more a case of applying your knowledge to a given equation!
Thank you so much for making these videos, they're a big help
I wanted to ask, do we need to know about specific industrial reversible processes and details on them (e.g. ammonia production occurs at 450C) or will we be given the information on them?
Thanks
OOg1712 Off the top of my head, I would say that you don't BUT it's always worth checking out the specification to see if they are required!
E Rintoul thank youuuu
I am always here a day before the exam 😅😅
Literally same
what about concentration and how it affects Equilibria
if u increase the concentration on one side equilibrium will shift to other side to equalise the concentration of both products and reactants, mate
This Is very helpful
thankyou and please continue
Do you work for some sort of webinar company
+hodo farah Nope. Why?
+E Rintoul because my school payed for a webinar so an examiner would explain to us what they look for and someone interrupted which sounded a lot like you
hodo farah Someone interrupted?!
+E Rintoul not really maths mic wasn't loud enough and someone watching was just telling him how to make it louder so we could hear and since we only hear your voice in your videos (which are amazing by the way) I immediately thought it was you and a lap which city do you teach in
hodo farah Haha amazing. I teach up north in Harrogate.
how do you know which side has the more molecules did i miss something?
the side which has a higher number eg in CH4 +H20 -->CO + 3H2 , theres 5 on the reactants side and 4 on the products side.
@@nonameee7963 bruh its been 5 months i understand now but thanks anyways
is this for ial students also?
Atul Hasan I have no idea what that is...
+E Rintoul international a level bit late soz :)
AdAm Haha no worries!
Very helpful! Thank you
can concentration effect equilibrium?
E.g. - I2 + 2OH I + IO + H20 :Increasing the conc (OH- ions) causes the equilibrium to shift to oppose this and move in a forward direction to remove additional ions(OH-). The position of equilibrium will shift towards the right giving a higher yield of the other product (I- + IO)
+MTO thank you so so much
Thank you soooo much, these videos a truly helpful, thank you Sir
Thank you so much for the videos they are so helpful.
thanks a lot video really help. although i do edexcel specification are really similar
esther adeleke That's good to hear!
6:52 that's the plan
your voice makes me love chem
"French, or something... like that" LOL
These videos are great
GENIUS
Hi is there any chance of the notes?
+Hashim Munir I'm afraid that I don't have them for this one. I do mean to get my act together and get some proper notes made for each topic, but it's something that will more than likely have to happen over summer!
4:56 this was unnecessarily funny 😭 😭
anyone else going to fail their chem exam today?
Harriet Paulden lol
im failing it tommorow
@@abderrezakboulbrachene6318 did you fail?
thanks so much me AQA as chem unit 2 is tomorrow wish me luck hahaha
You'll be fine! Read the question CAREFULLY. And breathe.
2020 people ?
Thank you!
Lol I loved the joke at 2:25 great video by the way sir
Thank you :)
John Paterson No problem :)
nice video! thank you!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
15:37
saving my life rn my exam is tomorrow and i had a depressive episode and i didnt study
tell us ur grade mate. i bet my house u failed
you are awesome...but can you just slower the rate of your lecturing speed please?
seems like your rapping :P
or please just add captions! :)
and please get a better cursor if you can :)
liked and subscribed! ;)
Atul Hasan Unfortunately, I can't! It's my natural way of speaking and to slow it down would mean that the videos would be much longer. By all means, as the magic of UA-cam allows, slow me down or just go back to points are re-listen!
Atul Hasan Adding captions to every part would more than likely double the time it takes to make each video! If this was my sole profession then I may, but it isn't! As time goes on I will more than likely develop them further to put more stuff into them, but for now, that can't happen!
Atul Hasan Anddddd, the cursor is just the cursor I'm afraid - as far as I am aware, there is no way to change it!
Thank you legend
Thank u!
you da man
Thanks...!
love you