The integral starts at 0, and floor(0) is 0, so you have to add an extra 1. Another way of thinking about its final value is that it would just be 99 1s in binary, which is 2^100 - 1.
I'm stupid at math but can't believe i actually solved it...i guess if I change the ceiling function to the floor function, the answer would change to 2^0 + 2^1 + ... 2^98 ? not sure though
The integral starts at 0, and floor(0) is 0, so you have to add an extra 1.
Another way of thinking about its final value is that it would just be 99 1s in binary, which is 2^100 - 1.
Nevermind. The width of the bar at x=0 would be 0, so there's no area under that part. So the answer 2^100 -2 is correct.
Thats ceil not floor, so the video is crct..
@qqqalo nice job for spotting the mistake!
Getting nervous for the January sitting, I've heard so many people saying how hard the last one was!
@AdamJackson-kf9eg yeah, I heard the first sitting was rough! What are you doing over the next few days to prepare?
@@JPiMathstrying not to overdo it haha! I feel like mindset / confidence with unfamilar problems is most important now. :)
Can you do some more tmua problems !
@@Nishaan478 which ones in particular?
I'm stupid at math but can't believe i actually solved it...i guess if I change the ceiling function to the floor function, the answer would change to 2^0 + 2^1 + ... 2^98 ? not sure though
0 to 1 = 0 so start form 2^0+2^1+...
Thats ceil not floor so the video is crct..