Love the clever way to solve problem. However, the solution’s argument for the W Lambert function (-Ln (9)/5) is outside the domain of such function [-1/e, ∞). The curve X^5 - 9^x does not intersect the X axis, the closest value (y=-0.345) occurs when x=0.589.
Rafael is absolutely right - given that (-ln(9/5) < -1/e, the conclusion of this exercise should have been to prove at the end that there are no real solutions to above given equation. In relation to that, It would have been useful to theoretically explain this outcome by sketching W(x) function and concentrating particularly on the meaning of the point -1/e in order to understand the concept behind the proof.
I am a math student(pursuing under graduate degree in India) from india and i just watched your video by UA-cam suggestion and I like you way to solving problem with explain in very eazy language and I like it thank you please made more videos like this for improving students mathematical knowledge. Thank you🎉❤
The domain of the W function of a real number is [-1/e, ∞). The argument (-ln 9)/5 is less than -1/e. Consequently, W((-ln 9)/5) does not have a real number value. The two curves do not intersect in the real number plane, as can be confirmed by plotting them using the online graphing app Desmos.
@@syedmdabid7191 Product logarithm is multivalued function in real number. W0: [-1/e, ∞) -> Real number W1: [-1/e, ∞) -> Real number Dom W= [-1/e, ∞) 3 > e > 2.5 ln x ↗ ln 9 > ln (e²) = 2 >5/e (ln 9)/5 > 1/e -(ln 9)/5 < -1/e -(ln 9)/5 ∉ [-1/e, ∞) W [-(ln 9)/5] ∉ Real number => The solution can only be in complex numbers; there is no solution in real numbers.
Its first time I saw the lambert W Function, when I study Calculus I and II, my lecture never taught this Lambert W Functions. I'm very blinde about this them... Please make more video especially about this Lambert W Functions. For your respect, thanks very much.
Thank you very much, professor. This was the first time I saw the Lambert function used to solve an equation. This is amazing! And it's nice to learn new things!
I like wrapping my mind around these Olympiad problems. They are most cleverly put together. They're designed to make us think outside the box to come up with a simple, elegant approach to the problem at hand.
I first came accross this type of problem when I was trying to answer a question regarding compound interest vs simple interest : ax = b^x where "a" and "b" are known quantities.
The equation has no solution in the real domain. You can check that by plotting a graph. You can try to solve the equation in the complex domain, but then you have to be careful with the logarithms.
Спасибо учитель,я не понемаю твое слова,но понемаю твое решения задач,я блогадарень тебя,очень хочу с тобой обшатся,я из УЗБЕКИСТАНа,знешли ты такое государства
I only watched the video because I couldn't solve it and I realised that it probably has no solution because the graphs of Y = x^5 and y = 9^x do not intersect. I thought I will be impressed if he can solve it and tell us the solution but he didn't give us any solution at all, he simply played with symbols. He should have been honest from the beginning and said this actually has no solution.
The domain of the Lambert_W function in R is all z s.t z >= -1/e but -ln(9)/5 < -1/e, therefore -ln(9)/5 is not a solution and the ‘equation’ has no solution. Graph x^5 and 9^x in Desmos ad you will see that they do not intersect.
im really confused about this function , i saw that its defined on [-1/e,+oo[ so yhere is no solution , but my calculator shows there are two solutions, one of them is ~ -0.72 , and the other is complex
@@padraiggluck2980 i know , i discovered that calculater makes mistakes here , -0.7 is not true at all , cuz (-0.7)⁵= -(9-⁰'⁷) ≠ 9-⁰'⁷ , but the complex solution is true , they actually do not intersect in real plane
@@SCOrganisationx=-0.72 can't be a solution, for x^50. I wouldn't trust that calculator.... The complex solution might be (approximately) correct, however.
@@WK-5775 yes, when i tried to put x=-0.72 the two numbers were identical but in different signs, i use a calculator app and it is very strong, but i think it is an error in the app that it does not take the sign into account in complex (no relation to the complex numbers 😅) equations, but the other solution is correct 😁
So what is x that solves the equation? Give us the value. Plotting f(x) = x^5 - 9^x I have satisfied myself that f(x) is always < 0, with the maximum of about -0.34 occurring near x = -0.6, i.e. there is no real solution to f(x) = 0. Am I wrong?
no, you are correct. There is no real solution. But, for some equation of the "n^x = x^n" sort, it is very useful to keep the W in mind. There are infinite solutions in the complex plane, meaning there is no single solution( because the lambert function takes in a number for its power, but in this case the number is absent, meaning it can be anything from the real plane.)for the equation, rather a set of infinite ones. there is a total of 5 formulas for solutions, hence 5 infinite sets of solutions(not counting the lamber power). I can give you one right now, approx. 7.92822 -31.61131 i, where i=√-1.
Какой приятный парень. Но я не понял решения в конце - что за функцию он ввел, когда приравнял А на Е в степени А к просто А? Чему же равен Х? Что за функция в решении?
Its a pleasure serving you in this regards and we are glad you gained some values from this video tutorial sir. We will do our best possible to serve you and others better in this endeavor. Maximum respect sir...🙋🙋
Well, when I first saw this I thought “there’s no way 9^x ever meets x^5 , right? Cause a power function is always above the x-axis…and there’s no way for any x^a (a>0) to catch it since such functions flatten out from 0 to 1…so…what is this guy smoking?” Perhaps I’m missing something? Like a good hit. :p 三八弟
@@onlineMathsTV Oh I see your solution must be an element of the Complex numbers...ok..haha...This is all new math for me, but I get it now. ps You can google "Wolfram Alpha" and then enter "productlog(A)" ...which is equal to W(A) pps Can I offer a little unsolicited advice? Let your audience know the domain of your x whenever you introduce a function. Also, point out that W(A) will only have real number solutions if A is greater than 1/(-e).
Hmm, he divided "mindlessly" by x on both sides of the equation (video 3:10 ), so he basically assumed x to always be positive. I guess you could do that if you consider that logarithm functions are defined for positive values of x only, am I right?
you can check that 0 isnt in question. and the fact that X can be negative is not to be underminded. in fact, x has a possibility to be negative, as there are infinite solutions for the equation. Since we are solving a complex equation, its not necessary to check if x
The lamber W function. Basically, when you have an expression alike "x*(e^x)" you can extract the "x" by applying the W function. hence W(a*e^a)=a. The function is really hard to understand and doesnt operate on one single formula, so you just have to take it for granted.
This is only one of the 5 solutions. Can you share the other 4 solutions? I listed all 5 solutions using log function below in the reply to my comment. If you can show the full solutions that will be helpful.
Love the clever way to solve problem. However, the solution’s argument for the W Lambert function (-Ln (9)/5) is outside the domain of such function [-1/e, ∞). The curve X^5 - 9^x does not intersect the X axis, the closest value (y=-0.345) occurs when x=0.589.
2222232-81=
000000032
-49
Rafael is absolutely right - given that (-ln(9/5) < -1/e, the conclusion of this exercise should have been to prove at the end that there are no real solutions to above given equation. In relation to that, It would have been useful to theoretically explain this outcome by sketching W(x) function and concentrating particularly on the meaning of the point -1/e in order to understand the concept behind the proof.
A complex solution is still a solution!!!
I am a math student(pursuing under graduate degree in India) from india and i just watched your video by UA-cam suggestion and I like you way to solving problem with explain in very eazy language and I like it thank you please made more videos like this for improving students mathematical knowledge. Thank you🎉❤
The domain of the W function of a real number is [-1/e, ∞). The argument (-ln 9)/5 is less than -1/e. Consequently, W((-ln 9)/5) does not have a real number value. The two curves do not intersect in the real number plane, as can be confirmed by plotting them using the online graphing app Desmos.
- ln9/5 is greater than --1/e because the interval semi close interval.. So, -- 1/ e is real. Negative number is real, not imaginary.
-0.881024 + 0.59038 i. Is the approximate answer to the Lambert W function.
@@syedmdabid7191
Product logarithm is multivalued function in real number.
W0: [-1/e, ∞) -> Real number
W1: [-1/e, ∞) -> Real number
Dom W= [-1/e, ∞)
3 > e > 2.5
ln x ↗
ln 9 > ln (e²) = 2 >5/e
(ln 9)/5 > 1/e
-(ln 9)/5 < -1/e
-(ln 9)/5 ∉ [-1/e, ∞)
W [-(ln 9)/5] ∉ Real number
=> The solution can only be in complex numbers; there is no solution in real numbers.
Oh but you see, there actually are multiple branches of the lambert function, spanning the entire complex plane and real line :>
Oh but you see, there actually are multiple branches of the lambert function, spanning the entire complex plane and real line :>
Its first time I saw the lambert W Function, when I study Calculus I and II, my lecture never taught this Lambert W Functions. I'm very blinde about this them... Please make more video especially about this Lambert W Functions. For your respect, thanks very much.
Thank you very much, professor. This was the first time I saw the Lambert function used to solve an equation. This is amazing! And it's nice to learn new things!
Lambert function😮 is new for me.
yea for me too
Thank you teacher you are so good for math.
Incredible professor, thanks
You are most welcome sir.
And thank you for thanking us and appreciating our little effort sir.
We all here love you ❤️❤️💕💕💖💖
Nice solution
You are really great mathematics and very good you are great preacher
Спасибо, профессор, Вы великолепны!
I like wrapping my mind around these Olympiad problems. They are most cleverly put together. They're designed to make us think outside the box to come up with a simple, elegant approach to the problem at hand.
love from sri lanka....😍
Thanks a million sir
I first came accross this type of problem when I was trying to answer a question regarding compound interest vs simple interest : ax = b^x where "a" and "b" are known quantities.
You really love math and teaching!!!
🎉well said sir
This is great approach master. I love this, and i have learnt some thing new sir. Thanks master 🎉🎉❤❤
Happy to hear that!
Nice
🎉🎉🎉🎉
Hy.
This equation don't have real solution.
The graphic of f(x)=x^5-9^× is strictly negative. Tx
Bravo👍👍👍
You are the master here because you are good at what you do🙏🙏🙏
Respect👌👌👌
Professor, what does W mean in solving multiple equations?
Lambert function
답이 없는 문제임.엉터리 해법
@@조광일-h5i 본인이 모르면 답이 없는 것인가요? lambert function이라고 위에 답을 주었는데도 인터넷도 한 번 안 찾아보고 엉터리라고 말하다니..같은 한국인인 제가 부끄럽네요.
@@조광일-h5i학무위키라도 읽어라
@@태권정-z8yㅋㅋㅋㅋ 바보야
very good algebric problem
I never went to olympiad. but as sweet you solve this, I really enjoy and occuping with it. Many thanks dear bro!
Great work.From India.
Great Lambert function (W)
Thanks for watching and commenting sir.
Much love from all of us @onlinemathstv to you sir 💕💕💖💖🙏🙏.
Brilliant work again thanks so much teacher
Thanks for the encouragement sir.
Much love
I didn't get past the 2nd line, you're good Sir, very good.
great approach but.....😍😍😍😍😍😍
What's wrong with the content sir? We are very open to corrections and criticism.
Hi sir
Please I need to understand as to how you immediately introduced logs on this without first tackling in normal way as others in this class.
very good
Thank you my good friend
Incrível!
Aproksimativno resenje je kompleksan broj x=2.004857+i×1.584805
i attempted another solution using the same reasoning:
define W: W^5 = 9^W. x=W QED
Nice explanation sir
Many thanks to you for the acknowledgement sir.
Much love from everyone @OnlinemathsTV ❤️❤️😍😍💕💕💖
I understood, THANKS A LOT
You are welcome, and we are glad u gained some values from this video tutorial sir.
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Nice explanation professor thanks 🙏🙏🙏
The equation has no solution in the real domain. You can check that by plotting a graph.
You can try to solve the equation in the complex domain, but then you have to be careful with the logarithms.
x = e^(2ln3/5) in the real plane
@@pureffm But there is no intersection point between x = ye^(y) and x = (-2ln(3)/5)
Great! Thanks for the rigorous approach! Greetings from Italy!👍👍👍👏👏👏👏
You are most welcome sir, and thank you for watching our video tutorial and leaving a comment behind.
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Sir,please express of W
So, what's is the numerical value of x that you sought now?
x ≈ 2.0049 - 1.3435 i
Interesting exercise, rigorous approach...
Thanks ! Congrats ! Keep it up ! Good luck with your work !
😍😍😍 Thanks so much for this wonderful comment you dropped here.
@@onlineMathsTVut lambda ₩ 👍؟؟????🦧🦧
@@onlineMathsTVs this college level math? If so what class is it? I never seen this in high school
Nice sir
Please make more such videos on harder algebra.
But which exam contains like this type of questions please tell me because I want to know?,
Does the answer approve x^5= 9^× ?
Спасибо учитель,я не понемаю твое слова,но понемаю твое решения задач,я блогадарень тебя,очень хочу с тобой обшатся,я из УЗБЕКИСТАНа,знешли ты такое государства
But the image of 9^x does not intersect with the image of x^5
x is a complex number; see Demetrius above !
See answer of Ratko Dinic.
Nice video
Thanks for watching and finding some values in our video sir.
Much love master.
Thank you professor
Good one
But how could you find the numerical value of W-n ( -- ln 9/5)??? For this, you must have to apply Newton Raphson method / graphic method.
But won't it have multiple solutions? As the input is negative?
I'm pretty sure there is no solution to this equation since if u plot the curve of x^5 and 9^x, they don't have any intersecting points!
I only watched the video because I couldn't solve it and I realised that it probably has no solution because the graphs of Y = x^5 and y = 9^x do not intersect. I thought I will be impressed if he can solve it and tell us the solution but he didn't give us any solution at all, he simply played with symbols. He should have been honest from the beginning and said this actually has no solution.
@averycleverman But fewer people would watch a video called "I cannot solve an equation that has no solutions."
Well it has no real solutions but It actually 5 imaginary solutions and this is one of them
17 years old account 😮woww that's great 👍 🎉
There are no real solutions, but they are complex.
Just found that the general solution for "xᴬ = Bˣ" is:
x = - W(ln b/a) / (ln b/a)
Obviously I haven't really paid attention to W domain subjects.
so what is the value in decimal form? I want to substitute it to double check.
You can get that from your Wolfram Alpha calculator sir.
La wolframalpha no da un valor numérico en es te caso
@@gerar2158 claro que sirve: 2.0049 - 1.3435 i
The first time I understand the Lambert functions
asnwer=3 isit hmm no math matter like isit 😂🤣😆😅
What is the numerical value of W(-ln9/5? Which is the exponent of e?
x = e^(2ln3/5) in the real plane
W₀(-ln9/5) ≈ -0.88102 + 0.59038 i
W₋₁(-ln9/5) ≈ -0.88102 - 0.59038 i
W₁(-ln9/5) ≈ -2.9052 + 7.4837 i
W₋₂(-ln9/5) ≈ -2.9052 - 7.4837 i
...
Great work, sir it was vey hard challenge, bt any way thanks.
Thank you for watching and appreciating our small effort so far.
We love you sir❤️❤️💕💕
Teacher what does mean w in this equation?
So what is X in numerical values?
The domain of the Lambert_W function in R is all z s.t z >= -1/e but -ln(9)/5 < -1/e, therefore -ln(9)/5 is not a solution and the ‘equation’ has no solution. Graph x^5 and 9^x in Desmos ad you will see that they do not intersect.
im really confused about this function , i saw that its defined on [-1/e,+oo[ so yhere is no solution , but my calculator shows there are two solutions, one of them is ~ -0.72 , and the other is complex
@@SCOrganisation Graph the two curves in Desmos. They do not intersect.
@@padraiggluck2980 i know , i discovered that calculater makes mistakes here , -0.7 is not true at all , cuz (-0.7)⁵= -(9-⁰'⁷) ≠ 9-⁰'⁷ , but the complex solution is true , they actually do not intersect in real plane
@@SCOrganisationx=-0.72 can't be a solution, for x^50. I wouldn't trust that calculator.... The complex solution might be (approximately) correct, however.
@@WK-5775 yes, when i tried to put x=-0.72 the two numbers were identical but in different signs, i use a calculator app and it is very strong, but i think it is an error in the app that it does not take the sign into account in complex (no relation to the complex numbers 😅) equations, but the other solution is correct 😁
Find the answer.not in Lambert function.
Great! But inconclusive.
The Lambert function of a negative value (-log(9)/5 < 0 always) will result a not real value. So, there is no x € |R that satisfy x⁵ = 9^x.
Compute the Integral x^2024/(x^2+1)^2023 dx please.
So what is x that solves the equation? Give us the value.
Plotting f(x) = x^5 - 9^x I have satisfied myself that f(x) is always < 0, with the maximum of about -0.34 occurring near x = -0.6, i.e. there is no real solution to f(x) = 0.
Am I wrong?
no, you are correct. There is no real solution. But, for some equation of the "n^x = x^n" sort, it is very useful to keep the W in mind. There are infinite solutions in the complex plane, meaning there is no single solution( because the lambert function takes in a number for its power, but in this case the number is absent, meaning it can be anything from the real plane.)for the equation, rather a set of infinite ones. there is a total of 5 formulas for solutions, hence 5 infinite sets of solutions(not counting the lamber power). I can give you one right now, approx. 7.92822 -31.61131 i, where i=√-1.
Какой приятный парень.
Но я не понял решения в конце - что за функцию он ввел, когда приравнял А на Е в степени А к просто А? Чему же равен Х? Что за функция в решении?
Dear professor! What is ld function?
but what is the value of λ?
very nice approach
Glad you liked it and thanks for watching and commenting sir.
Much love 💖💖💕💕💕
Thank you for the video!! Turn my maths fear and anxiety earn in the past 15 years from a teacher I had…to an opening in mathematics again
Its a pleasure serving you in this regards and we are glad you gained some values from this video tutorial sir. We will do our best possible to serve you and others better in this endeavor.
Maximum respect sir...🙋🙋
Thank you Sir, your response is so overwhelming. Thank you
Would you please make a video on Lambert Function, professor!?
it is simple
Sure master, it shows you are the master here and you are good at what you do sir.
Respect👍👍👍.
does x = e ^ -W(- ln9/5) valid?
🇩🇿🇩🇿 شكرا
Prof. Are u from Nigeria?
Well, when I first saw this I thought “there’s no way 9^x ever meets x^5 , right? Cause a power function is always above the x-axis…and there’s no way for any x^a (a>0) to catch it since such functions flatten out from 0 to 1…so…what is this guy smoking?”
Perhaps I’m missing something? Like a good hit. :p
三八弟
Am smoking maths hahaha...🤣🤣😂
@@onlineMathsTV Oh I see your solution must be an element of the Complex numbers...ok..haha...This is all new math for me, but I get it now. ps You can google "Wolfram Alpha" and then enter "productlog(A)" ...which is equal to W(A) pps Can I offer a little unsolicited advice? Let your audience know the domain of your x whenever you introduce a function. Also, point out that W(A) will only have real number solutions if A is greater than 1/(-e).
Where did the W on the left go? 🤔
This is the real solution and no doubt about it x = -(5 W_n(2/5 (-1)^(3/5) log(3)))/(2 log(3)), n element Z or
One of the solution of x
x≈-2.2756
负数不能取对数吧
Sir; can you explane that rules name 6:32
how can i find that
Hmm, he divided "mindlessly" by x on both sides of the equation (video 3:10 ), so he basically assumed x to always be positive. I guess you could do that if you consider that logarithm functions are defined for positive values of x only, am I right?
وظائف الوغاريتم غير محدودة في مجموعة الاعداد المركبة يا صديقي
you can check that 0 isnt in question. and the fact that X can be negative is not to be underminded. in fact, x has a possibility to be negative, as there are infinite solutions for the equation. Since we are solving a complex equation, its not necessary to check if x
Does the equation have a solution?
Yes, but only complex.
It's interesting, that in according a formula
e^nW (x) = [x/W(x)]^n:
n = -1 and
e^-1 W(-ln 9/5) = [(-ln 9/5)/W(-ln 9/5)]^-1 =
W(-ln 9/5)/(-ln 9/5)
I can prove that x^5
When the question asked for value of x, it didn't ask for real value only
W(-ln9 / 5 ) is a real number itself?
What X meaning in Math
How to evaluate W(- ln9/5)?
Use the Wolfram Alpha calculator, it will give you the numerical value
It's beyond my ability to understand
Base =9
Power : 5
I got that the risult is approximatively 0,34+0,23i 😞 what does that means? That the solution is irrational?
what is W?
What does mean w ?
Is a function known as "Lambert W"
Was für ein Geschmiere ....numerical value now ?
.x=3
X=9
Nice explanation and thanks for this video Jakes.
Thanks for appreciating our little effort sir
Much love from Onlinemathstv 💖💖💖💕💕💕
*Do not fear, the Lambert W function is here!*
What is w(a.e^a)=a
The lamber W function. Basically, when you have an expression alike "x*(e^x)" you can extract the "x" by applying the W function. hence W(a*e^a)=a. The function is really hard to understand and doesnt operate on one single formula, so you just have to take it for granted.
WHAT IS THE MEANING OF LM
Ln not LM sir. It means natural logarithm
This is only one of the 5 solutions. Can you share the other 4 solutions? I listed all 5 solutions using log function below in the reply to my comment. If you can show the full solutions that will be helpful.
This great but I think this math is beyond my level. Anyway, thanks for dropping this nice video sir.
You are most welcome
You have not yet checked whether your solution is correct or not