Solving Exponential Equation With Radicals | Japanese Olympiad Math Question | Mathematics.

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  • Опубліковано 25 лис 2024

КОМЕНТАРІ • 89

  • @اممدنحمظ
    @اممدنحمظ Рік тому +3

    تمرين جميل جيد . شرح واضح مرتب . شكرا جزيلا لكم والله يحفظكم ويرعاكم ويحميكم جميعا . تحياتنا لكم من غزة فلسطين

    • @onlineMathsTV
      @onlineMathsTV  Рік тому +2

      Many thanks to you for finding our videos very fascinating and thank you for your wonderful words of encouragement all the time to us on this channel sir.
      All of us @Onlinemathstv love you sir.
      Much love from everyone of us @onlinemathstv to you, your family and all the people of Gaza, Palestine ...💕💕💕❤️❤️💖💖

  • @hogec_enlightenmentarena6975
    @hogec_enlightenmentarena6975 Рік тому +3

    Nice 👍

  • @MunaCabdulaahi-z2e
    @MunaCabdulaahi-z2e Рік тому

    hope see you again
    My teacher thanks for everthing

  • @venky3867
    @venky3867 Рік тому

    I'm proud that I could do this in my mind

  • @albinonhabanga8066
    @albinonhabanga8066 Рік тому +1

    I think it's very important to check first the existence conditions of some functions, as this square root, to detect non valid solutions or include in your solving
    Anyhow you are a beast 😎

  • @ΔιονύσηςΤ-π5ρ
    @ΔιονύσηςΤ-π5ρ Рік тому +4

    I firmly believe that either we should have restrictions for the solutions of the equation or, at least, if we ommit the restrictions we should check the solutions before we accept them.

    • @onlineMathsTV
      @onlineMathsTV  Рік тому

      Thanks for this wonderful comment sir. I have checked the two solutions and they are correct.

  • @moulikraina2186
    @moulikraina2186 Рік тому +7

    Can u give more questions like this?As the question was amazing and also the way to explain .i enjoyed ur explanation

    • @onlineMathsTV
      @onlineMathsTV  Рік тому +3

      We are glad you enjoyed and gained something valuable from this video.
      Sure, we can make more of this sir.
      Thanks for the request.
      Much love 💖💖💖

  • @charlesmitchell5841
    @charlesmitchell5841 Рік тому

    Good problem. Good explanation. Thanks for the video lesson!

    • @onlineMathsTV
      @onlineMathsTV  Рік тому

      Thanks for the encouragement sir.
      And thanks for watching our contents sir.
      Much love❤️❤️💕💕💕

  • @teacherheng1688
    @teacherheng1688 Рік тому +2

  • @sepehrarkani6689
    @sepehrarkani6689 Рік тому

    Excellent videos. Greatly appreciated!

    • @onlineMathsTV
      @onlineMathsTV  Рік тому +1

      Glad it was helpful and thank you for appreciating our little effort sir.
      This is encouraging. Much love💕💕💕

    • @sepehrarkani6689
      @sepehrarkani6689 Рік тому

      @@onlineMathsTV you're very welcome 👍

  • @douglasjunior5062
    @douglasjunior5062 Рік тому +1

    Eu não fazia ideia de pra onde ir 😅😅 vídeo muito bom

    • @onlineMathsTV
      @onlineMathsTV  Рік тому +1

      😍😍😍 funny you sir.
      Coming here means you will definitely know where to go next time you come across any mathematical challenge/problem as u consistently visit OnlinemathsTV channel.
      Much love....💖💖💖

  • @danielfranca1939
    @danielfranca1939 Рік тому

    Great explanation. This is lovely sir.

    • @onlineMathsTV
      @onlineMathsTV  Рік тому

      Thanks @Daniel Franca
      Love you...💖💖💕💕

  • @StephieJoseph-io3wt
    @StephieJoseph-io3wt Рік тому

    Thanks for making this video sir.

    • @onlineMathsTV
      @onlineMathsTV  Рік тому

      You are welcome always ma.
      Love you...❤️❤️💕💕

  • @F.S.L.C.
    @F.S.L.C. Рік тому

    WOW - THANK YOU.

    • @onlineMathsTV
      @onlineMathsTV  Рік тому +1

      You're very welcome sir.
      We are glad you gained some values from this tutorial sir.

  • @youncheolshin6304
    @youncheolshin6304 Рік тому +2

    if you put 3^x =a, 4^x=b you can rewrite the question as this : a-b= root( ab-b^2)
    and square each side that can be (a-b)^2 = ab-b^2 ; a^2 - 2ab + b^2 = ab-b^2 ; a^2 - 3ab + b^2 = 0 ; (a-b) (a-2b) =0 ;
    a-b=0 or a-2b=0 ; a=b or a=2b ; 3^x= 4^x or 3^x = 2* 4^x ; its more simple what do you think?

    • @onlineMathsTV
      @onlineMathsTV  Рік тому +1

      Very concise sir. It is a welcome approach too.
      Nice work and we have learnt something new from your comment.
      Thanks for watching and dropping this comment too.
      Much respect and love to you sir...🙏🙏💕💕💕

  • @abhijitgangopadhyay8962
    @abhijitgangopadhyay8962 Рік тому

    Thank you Sir

    • @onlineMathsTV
      @onlineMathsTV  Рік тому

      You are most welcome sir, and thanks for watching our content sir.
      Much love 💖💖💕💕

  • @BN-hy1nd
    @BN-hy1nd Рік тому

    Hmm, I should try a graphical solution method without drawing a proper graph
    Sketch a graph of graph of y = 3^x -4^x .
    y = (12^x -16^x)^0.5 when x = 0, y=0, certainly. y will always be +ve when x is -ve. When x is positive will generate complex numbers
    so, by inspection, both graphs meet at x=0 and y=0
    Then try x = -1, -2 and -3 ; gradually the difference in y values get smaller and smaller
    In an exam, this sort of question requires an approximate answer for the second value

  • @desirekouame3946
    @desirekouame3946 Рік тому

    Congrats,bro !

    • @onlineMathsTV
      @onlineMathsTV  Рік тому

      Many thanks to you for encouraging us on what we are doing sir.
      Respect...👍👍

  • @HelenBlackG-xn9hf
    @HelenBlackG-xn9hf 6 місяців тому

    🎉🎉❤❤❤

  • @M.Davit613
    @M.Davit613 Рік тому +1

    I solved the exercise in 2 minutes․ x

    • @onlineMathsTV
      @onlineMathsTV  Рік тому +1

      Bravo👍👍👍
      You the master👌👌👌

    • @M.Davit613
      @M.Davit613 Рік тому +1

      @@onlineMathsTV Thank U

  • @sudhakaranpillai9623
    @sudhakaranpillai9623 Рік тому +6

    In case 1,there is no need to go for' ln' because raised to the power 0 only gives 1

  • @petermak3980
    @petermak3980 Рік тому +1

    You must set 3^x--4^x>=0 ...... x

  • @vansf3433
    @vansf3433 11 місяців тому

    It seems that you like solving children' s math-probs
    3^x - 4^x = sqrt(14^x -16^x). Notice that the expression inside the radical can not be negative, but 14^x < 16^x ---> 14^x - 16^x will always be negative. There is only 1 way to neutralise the negative result is to make the expression= O. since any value taken to pwer of 0 will become 1. If x = 0, 24^0 -16^0 = 1 - 1 = 0
    Checking whether x = 0 the solution:
    3^0 - 4^0 = sqrt(14^0 - 16^ 0)
    1 -1 = sqrt(1 - 1)
    0 = 0. Hence, x = 0 is the solution
    We're done

    • @onlineMathsTV
      @onlineMathsTV  11 місяців тому

      Ok sir, thanks for dropping this sir.
      We learn everyday from the best brains all around the globe and we sincerely believe you are one of these rare genius in mathematics. Nice to have you here sir,
      You are most welcome master.

  • @sans1331
    @sans1331 Рік тому

    3^x-4^x=sqrt(12^x-16^x)
    y=3^x-4^x
    y=sqrty*(sqrt4^x)
    =sqrty*2^x
    divide both sides by 2^x
    1.5^x-2^x=sqrty=y/2^x
    sqrty=y/2^x
    2^x=y/sqrty=sqrty
    square both sides
    y=4^x=3^x-4^x
    +4^x both sides
    2(4^x)=4^(x+0.5)=3^x
    z=ln4/ln3 [3^z=4]
    (3^z)^(x+.5)=3^x
    x=zx+0.5z
    *x both sides
    x^2=zx^2+.5zx
    -x^2 both sides
    (z-1)x^2+0.5zx=0
    [1 rough quadratic formula later]
    x=(-0.5(ln4/ln3))/((ln4/ln3)-1)
    =-ln4/((2ln3)((ln4/ln3)-1)
    (2ln3)((ln4/ln3)-1)=((2ln3*ln4)/ln3)-2ln3
    =2ln4-2ln3
    =>x=-ln4/(2(ln4-ln3))
    …and also x=0.
    edit: oh wow, different fractions yet the same constant

    • @onlineMathsTV
      @onlineMathsTV  Рік тому

      Wonderful and unique move.
      You are good at it sir, you the master here.
      Respect👌👌👌

  • @MeinhartKöster
    @MeinhartKöster Рік тому

    thank you very much, i suggest that the value of zero for u should be rejected, for otherwise the division by ( 3 px - 4 px) being equal to zero would not work

    • @onlineMathsTV
      @onlineMathsTV  Рік тому

      But 3 px - 4 px (i.e 1-1) will give us zero, which implies LHS = RHS.
      What do you think sir?

  • @honey-qqq
    @honey-qqq Рік тому

    🙏

    • @onlineMathsTV
      @onlineMathsTV  Рік тому

      Thanks sir for you comment.
      It is a symbol but a big symbol of encouragement to us sir.
      We are glad that you gained some values from our little effort and we promise to do more effective work here in order not to disappoint you and others who believe even in our little beginning.
      We love you sir.❤️❤️💖💖💕💕💕

  • @youncheolshin6304
    @youncheolshin6304 Рік тому +1

    how about 0 or 1/{ log2 (3) - 2}

    • @onlineMathsTV
      @onlineMathsTV  Рік тому

      Thanks for the encouragement sir.
      We love you for watching and commenting sir.
      Much love 💕💕💖💖

    • @tunneloflight
      @tunneloflight 10 місяців тому

      This also has the advantage that many calculators natively perform lg2, so x = 1 / (lg2(3) -2) is trivial to calculate. In RPN: 3 ; lg2 ; 2 ; - ; 1/x. {five keystrokes}

  • @SASS-yp8gu
    @SASS-yp8gu Рік тому

    X не может быть равен "0", так как -1 не равно sqrt(-1)

  • @marjaentrich7121
    @marjaentrich7121 Рік тому

    Выражение под корнем должно быть не меньше нуля. Те, когда возаодили корень в квадрат, должны были получить модуль и нужно рассмотреть 2 случая

  • @s.h.munasingha2590
    @s.h.munasingha2590 Рік тому

    ,X= log( 3/4 ) 2

  • @syedmdabid7191
    @syedmdabid7191 Рік тому

    What's is the meaning of Wn( 2) ?????

    • @brightjovanny
      @brightjovanny Рік тому

      Wn(z) is generally called the Lambert W function (or omega function or productlog) where the subscript n (an integer) represents the principal, positive or negative branch of the function with n = 0 being the principal branch.
      The Lambert W function is the inverse of the function:
      f(w) = we^w
      where w is any complex number and e^w is the exponential function.
      The function can also be written as:
      LambertW(n,z)
      ProductLog(n,z)

  • @ChristelleHilaire-lb6pu
    @ChristelleHilaire-lb6pu Рік тому

    ×=-3

  • @FractAlkemist
    @FractAlkemist Рік тому +1

    I tried my Genetic Algorithm with this; 'x' must be a negative number, and it needn't be an integer. There seems to be no real solution, the greater the (negative) number, the closer it gets. I scanned from 0-> -500 and the best I got was:
    X = -481.58408788993336
    Left side evaluates to: 1.6826575283911937e-230
    Right side evaluates to: zero (probably not real zero, the computer just doesn't display such a small number)
    Difference = 1.6826575283911937e-230 , effectively solving the equation (for engineers, not theoreticians!)
    (plus overflow errors and other Python squawking)
    Maybe I should watch the video ......
    .

    • @onlineMathsTV
      @onlineMathsTV  Рік тому

      Smiles....nice work from you boss.
      But most times AI fails to give the actual result to a mathematical challenge.
      I believe you have watched the video sir.
      Did you agree with the approach I applied here?
      I made a video on a similar challenge with a different approach.
      Below is the link to that video, you can as well flip through it to check it out if you don't mind sir.
      ua-cam.com/video/0cWjl5616pQ/v-deo.html
      And do not hesitate to make corrections where necessary because we are here to also learn from the best brains like you all around the world.
      Thanking in advance boss!!!
      Respect!!! 👍👍👍
      Much love....❤️❤️

    • @vicferrmat4492
      @vicferrmat4492 Рік тому

      Do you mean "generic" algorithm?

  • @РавильГарифуллин-щ5ж
    @РавильГарифуллин-щ5ж 3 місяці тому

    Ответ--6

  • @AloneStroller
    @AloneStroller Рік тому

    I disagree with x2 solition - it is superfluous as we should use straight definition of logarithm: X2=log(3/4)2. log(a)b.

  • @mahinofficial4671
    @mahinofficial4671 Рік тому

    If we use log instead of using ln ,then what will happen

    • @onlineMathsTV
      @onlineMathsTV  Рік тому

      same result sir.

    • @faithlesshound5621
      @faithlesshound5621 Рік тому

      Using logs to the base of 10, we can fill in the numbers (the logarithms of 2, 3 and 4, which are 0.3010, 0.4771 and 0.6020) from memory and then calculate the quotient by hand. I don't have natural logs in memory.

  • @shoshosalah3447
    @shoshosalah3447 Рік тому

    X1=0
    X2~ -2.41

  • @ilyashick3178
    @ilyashick3178 Рік тому

    ln 1 is equal 0 so x1=0

  • @johnwren6138
    @johnwren6138 Рік тому

    Easier to go m log7=log70

  • @MathsTuitionBangla
    @MathsTuitionBangla Рік тому

    Hello students

    • @onlineMathsTV
      @onlineMathsTV  Рік тому

      Hi master!!!
      Anything for the student/s?
      We are at your service as your wish is our command sir.

  • @DilaverHamzayeva-fs6fg
    @DilaverHamzayeva-fs6fg 8 місяців тому

    🤎

  • @loveharshvardhan4259
    @loveharshvardhan4259 Рік тому

    In this video, the respected teacher is attempting to divide by zero, the value for which remains undefined and unknown. Thereby, his method is wrong.

    • @onlineMathsTV
      @onlineMathsTV  Рік тому

      Sir, are you of the opinion that zero as a root to this math challenge is wrong? Kindly do the simple substitution and check if an undefined expression will emerge in this math challenge sir.
      Thanking you for a positive response in advance.

    • @nasrullahhusnan2289
      @nasrullahhusnan2289 Рік тому

      I think there is no division by zero. In [(3^x)-(4^x)]²=(4^x)[(3^x)-(4^x)] the teacher didn't divide the equation by (3^x)-(4^x), rather he let (3^x)-(4^x)=u and then move all terms to one side.
      Directly moving all terms to one side follow by factorizing we get
      [(3^x)-(4^x)][{(3^x)-(4^x)}-(4^x)]=0
      [(3^x)-(4^x)][(3^x)-2(4^x)]=0
      Hence: • (3^x)-(4^x)=0 --> x=0
      • (3^x)-2(4^x)=0 --> (¾)^x=2
      NO DIVISION BY ZERO

  • @Bertin-q3y
    @Bertin-q3y 10 місяців тому

    X=0

    • @onlineMathsTV
      @onlineMathsTV  10 місяців тому

      Correct boss, but that is just one of the solutions.
      Thanks for stopping by sir.
      Much love.

  • @유도겸-i2i
    @유도겸-i2i Рік тому

    빙빙 돌아가며 풀이해 지친다..
    무조건 자연로그로만 푸니 듣기가 힘듬

  • @vansf3433
    @vansf3433 11 місяців тому

    You don't have to copy all such lengthy steps of human -invented motions of algebra to arrive at the correct answer
    Again, logical reasoning can help you solve all sorts of problems, but not copying such lengthy formulas and steps, like a photocopying machine

  • @JohanNgoko
    @JohanNgoko Рік тому

    I already see 0 as solution 😅

  • @sobolzeev
    @sobolzeev Рік тому

    I wonder who is meant as the audience of this piece. A general mediocre pupil will not get even this long and overworded explanation. A bit developed one (1) does not need 2/3 of this wording, (2) guesses x=0 is a solution in the first 30 seconds, by substitution, (3) since a square root from a negative number is not real, gets any other root is negative. Finaly,
    3^x = 4^(x+1/2) can be trivially solved with much less wording.