How to Solve the Challenging Radical Equation?
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- Опубліковано 17 чер 2024
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How to Solve the Challenging Radical Equation?
Are you ready to solve some challenging radical equations? 🧠✨ In this video, we'll break down the steps to tackle even the toughest radical equations. Perfect for students gearing up for exams or math enthusiasts seeking a challenge! Join us to enhance your problem-solving skills and master these complex equations. Don't forget to like, comment, and subscribe for more math challenges and tutorials. 📏🔢
Topics covered:
Algebra
Radical Equation
Substitution
Algebraic identities
Algebraic manipulations
Quadratic equations
Binomial expansion
Pascal triangle
Math Tutorial
Math Olympiad Preparation
Timestamps:
0:00 Introduction
0:30 Substitution
3:30 Pascal triangle
4:10 Binomial expansion
10:25 Solutions
11:01 Verification
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@infyGyan
Nice explanation
A WONDERFUL explanation.....x= 63/32
X=63/32
Domain cannot be a>0 and b>0. The solution (x=63/32) itself is making a=0.
Yes, the domain is a≥0 and b≥0 and 2-x≥0 (x≤2).
Consequently p≥0 and q≥0. The equation 6p²+8q²+15pq=0 has the solution p=q=0 what implies a=b=0 but a and b cannot be =0 simultaneously (65-32x cannot be equal to 63-32x).
@@StaR-uw3dc Makes perfect sense.