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It would have been rather good if she was actually knowing all the concepts and solving it. She is just replicating what is written in her reference book.
Thank you ma'am I don't watch all your videos, but I learn form your channel what I need by watching all your videos, you explain very well, thank you very much for your support to every student by this platform
Mam, I think you should have first plotted the asymptotes and then proceeded on plotting the root locus, because that would have helped in giving a sense of direction the locus would take, as it moves after the breakaway point.
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Step 4 : 3x²+10x+6 after solving I got s= -0.589 and s= -1.911 how did u solve to get s=-0.784 and s= -2.549 I solved by quadratic method . Plz tell me
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Good evening.... Explanation is not perfect , because there is no terms like centeroid and asymptotes was explained... So how do we finalize the movement of path exactly.???
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Draw the root locus of a closed-loop system with the following characteristics: Process: 𝐺𝑝(𝑠) = 1 (𝑠+1)(2𝑠+1) Controller: 𝐺𝑐(𝑠) = 𝐾𝑐 Measuring device: 𝐺𝑚(𝑠) = 1 Final control element: 𝐺𝑓 (𝑠) = 1 Indicate what segments of the root locus (i.e, values of 𝐾𝑐 ) yield,
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Hello Friends
Please watch the updated version here - ua-cam.com/video/qToRmEv3ZA8/v-deo.html
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Very useful this video for control system
kitne confidence se chaap rahi hai bro "impressive"
It would have been rather good if she was actually knowing all the concepts and solving it. She is just replicating what is written in her reference book.
Abe aukat me reh chakke UA-cam warrior
Thank you ma'am I don't watch all your videos, but I learn form your channel what I need by watching all your videos, you explain very well, thank you very much for your support to every student by this platform
Mam, I think you should have first plotted the asymptotes and then proceeded on plotting the root locus, because that would have helped in giving a sense of direction the locus would take, as it moves after the breakaway point.
One of the best explanation of Root Locus, thank you
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thanks mam all concept cleared in one video
Very thanks mam, to clear difficulty in easy manner...🙏
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Thanks!
Thank you
Thank you ma'am, .....
Thank you
Helped alot.
Tq mam
Superb explanation
thankyou mam
Whatever the notes ur writing during the video make it available as pdf n provide it in discription box so that it is useful for everyone
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thank you :')
Thanks mam.
Thanks mam!
aplacığım çok iyi anlattın teşekkür ederim.
@27:27, the sum of angles on a line can be maximum of 180 deg.....plz rectify.
nice
thankuu mam i am satisfied your ans
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Wowww very useful
Why root locus doesn't exist between -3 and -2 nd how do we know?
Graphical representation is some what confusing
Well explained
Nice way of teaching
Thank you!
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mam herself is confused
28:31 How is that 300 degrees ?
Pura to Side mai padke bol rahi hai
Ussko bhi nahi pata
🔥🔥🔥
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Step 4 : 3x²+10x+6 after solving I got s= -0.589 and s= -1.911 how did u solve to get s=-0.784 and s= -2.549 I solved by quadratic method . Plz tell me
Try it on Scientific Calculator .... I got it correct
Hello mam 👋👋 why u private most of the videos of cs
Dear its basic concepts of root locus . What about real life application of root locus ! and its importancy .
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There are some error in angle of asymptotes
climax is in the end
Good evening....
Explanation is not perfect , because there is no terms like centeroid and asymptotes was explained... So how do we finalize the movement of path exactly.???
Appne ye s^3+ 5s^2+6s+k ka eqn kaise banaya
Step 6 ka
When we find angle of departure ??
When there is complex pole in formx+iy
Can any body say
How 6 value converted into 2.5 in
Ie 2.5j
@22:05, how do you get +/-6 when you divide -30 by 6...??? You have wronged at many steps. Please rectify.
Mam i dont understand step no 3 of plotting
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Confusing
Maam you are not teaching, it seems that you are just reading from the reference book and writing on the paper. Not satisfied with your content.
Then wer is angle of departure??
angle of departure is only found if you have complex poles or complex zeros
Aise kaise 30-k>0
Ko 30-k=0 kar diya? Any reason?
Manipulation techniques to get answer??
Hello
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Mem aap 205EE pdao na
Thanks centroid is missing
how get value of x and x step four ?
Ye equation solve karne ke baad ye answer ata hai aise bolne se accha wo kaise solve kiya wo bata deti , digest me dekhke 5 std ka ladka bhi sikha de
😢
Dont Waste Time here
Draw the root locus of a closed-loop system with the following characteristics:
Process: 𝐺𝑝(𝑠) =
1
(𝑠+1)(2𝑠+1)
Controller: 𝐺𝑐(𝑠) = 𝐾𝑐
Measuring device: 𝐺𝑚(𝑠) = 1
Final control element: 𝐺𝑓
(𝑠) = 1
Indicate what segments of the root locus (i.e, values of 𝐾𝑐
) yield,
Hello
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Teach yourself first.
300 and 60 on a straight line?
I think she made a mistake
Your step 4 is completely wrong ... Don't teach wrong concept to the students.
Breakaway point is found by equating dk/ds to 0 . Not by dG(s)/ds = 0 .
Direction kese nikala bola hi nhi
youre showing the direction right and telling this this this direction! stop teaching in this way
Really confusing...
not good to be honest plz explain it from the root
step 3 ,logic is not clear!!
Yes right
Step 3 is totally wrong....
Yes
Only half knowledge
Less confident
niche dekhke chap rahe hai madam
Break away point calculation is wrong ,we get 3s^2+10s+5
Your explaination was very poor
This channel wastes time exorbitantly
Thank u ma'am
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Thank you mam