Your teaching method is much better than all other channels ever exist in UA-cam who make Enginneering Videos.Please continue uploading relevant lecture.
I have seen so many vedios on this topic but I feel all difficult but finally I gone through your explanation is very very easy and you made the questions as very easy thank you sir
thanks you actually covered an example with complex poles that nobody else seems to want to do, this is the only sort of problem that matches my homework lol
very very useful video, helped a lot, u r so greatt, so much efforts u have taken to bring such wonderful output, may god bless you , u will reach great heights
while calculating centroid, shouldn't we only consider the real parts of poles and zeros ? in this particular problem the imaginary parts are getting cancelled out but in other cases it will be a problem...won't it ?
doubt: to check root locus point are we supposed to consider only real poles or for example there is a conjugate in 2+4j 2 is on real line so 2 also shall i consider?
I think that you are asking about finding the root locus on the real line. If so the complex roots don't matter because they always appear in conjugate pairs anyways. So if you add them in you will always get an even number (2) added to what ever poles and zeros are to the right of the point you are evaluating. Since adding 2 to an odd number leaves it odd and adding 2 to an even number leaves it even you can ignore the complex roots for this purpose.
You should consider only the on real axis.(i.e. only real numbers) not the complex poles that lies on the s- plane. 2+4j is a complete pole. You should not consider only 2.
clear all; clc; s = tf('s'); disp('The given transfer function is,'); Gs = (s+9)/(s*(s^2+4*s+11)) rlocus(Gs,'k'); axis([-6 2 -6 6]); sgrid; I think it is like this... Just try this in Matlab
Zeros are two know because u considered S= 0 in poles Z1=0 Z2=-9 Replay bro I want clarity ????????????????????????? And zero is even num But u considering it's an odd number? Replay 😊
You explain everything without confusing the student. It's very rare and very valuble skill.
Your teaching method is much better than all other channels ever exist in UA-cam who make Enginneering Videos.Please continue uploading relevant lecture.
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Yes sirrr
@@srivallipadhamavathi😂😂🎉
I have seen so many vedios on this topic but I feel all difficult but finally I gone through your explanation is very very easy and you made the questions as very easy thank you sir
Welcome 😊
U are always a magical teacher...thanks a lot
Thank you so much
Seriously he is
thanks you actually covered an example with complex poles that nobody else seems to want to do, this is the only sort of problem that matches my homework lol
Sir you are a Smart Engineer indeed. Thank you for saving my life, all the way from South Africa ✌
Even explained those terms which were not asked in this question but we may need in some other questions👏👏, Thank you!!
Thankyou sir, for explaining every detail, without confusing
gone through lot of videos but this one is the right one. nice explanation
Do share to your class group
@@smartEngineerShinton Ok bro!
small doubt if zero is there in b/w poles then how to calculate break away or in point?
@@abhiramambati3346 break away point exists btw two adjacent poles ,break in point exists btw two adjacent zeros ,btw pole and zero they don't exist
sir number of asymtotes is not the number of poles .It is poles-zeros(p-z)
This was extremely well explained! Love from Canada.
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I'm blessed.......as i found this video.
Thanku you so muchhhhhh sir.
Прекрасный урок! Спасибо огромное!
Control System Needs So Much Attention. Active Mind Whole Book.
very very useful video, helped a lot, u r so greatt, so much efforts u have taken to bring such wonderful output, may god bless you , u will reach great heights
Made my day 😇
Sir, your explanation was clear and satisfyng thank you
thanks a lot brother
helped me a lot before the exam
ua-cam.com/video/r3TlKbs7TKQ/v-deo.html
Thanks Biradar
✌🤟❤
U make it simpler
Now I can complete my assignment. 😜
Really thanks
ua-cam.com/video/r3TlKbs7TKQ/v-deo.html
Why u have take plus or minus 180 in asymptodes , as in first problem it's not there
The best video I saw on this topic 👏
Like on of the best explainations i have watched ❤️
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Explained well thank you sir..
Is the angle of arrival/departure measured from the centroid?
Sir ur channel didnt show up for some days I was worried what had happened. Thank God finally it came back.
Got hacked😭
@@smartEngineerShintonthen how did you get back bro because i too last my account how did you recover
Explanation is tooo Good👏👏👏
This is the best video I have ever seen on this. Also much better than anything my professor explains, she confuses me lol
sir why we take +-90 and +-270....It should we 90 and 270 ?
Sir please reply
ur... our garden angle 🔥
Do share to your class group
Sir angle of departure value is -16⁰
at 19:38 ans= -16
Deserves more subscribers
Super Bhayya..Well Explained
Thank you so much!! I understand so much better now!
God level explaination
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how you got angle of departure 17 degree, it is 58 degree according to that formula you have calculated
Ur are the 🔥 fire sir no words to tell about ur teaching sir
The best teacher 👍❤️ i😭 iam madly searching for the best video then I found u tqq uu best video
Welcome 🤗 and do share to your class group
Why +- only in this question...in asymptote
while calculating centroid, shouldn't we only consider the real parts of poles and zeros ? in this particular problem the imaginary parts are getting cancelled out but in other cases it will be a problem...won't it ?
Osm lecture sir continue uploading...
Extraordinary bhaiya
you are good teacher thank you......
Welcome 🤗
@@smartEngineerShinton never
GREAT VIDEO, keep doing this
Brother this video very good, but slove difficult problem to solve
Aiml medha job's gurinchi oka video chy Anna skills ame narchukovalo chappu anna
Plz do a qustion with zero exist and non comblex
Thank you for really helpful this video
sir if we got the zero at rightside to the pole then what is the root locus on real axis
Brilliant man
It helped a lot.
Awesome video
sir what about lack of zeros? how does it affect my test point?
I think angle of departure is -57.79 degree
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Yes you are right 👍
sir why you consider 90* and 270* as same angle with same line
Yaa I'm also confuse
Thank you so much sir 🙏
Super explanation 👌
ua-cam.com/video/r3TlKbs7TKQ/v-deo.html
Thank you so much sir❤
In finding centroid only real part of the poles and zeroes is to be taken
Ma Man thank u sm
sir if we got k value is negative then what we need to do sir?
great explain bro
what if a pole present on right side of real axis can we find gain stability
Sir i have options with root locus part and time response steady state analysis which shall i choose
Your lecture is exllent sir👏🙏 but the marker pen your are using is not good please do explain with good marker🙂sir
Sir dsp videos (teaching) continue karoo
Excellent lecture sir. Is this from nagoor kani text book sir
While finding q why you are doing p-z-1
ua-cam.com/video/r3TlKbs7TKQ/v-deo.html
doubt: to check root locus point are we supposed to consider only real poles or for example there is a conjugate in 2+4j 2 is on real line so 2 also shall i consider?
I think that you are asking about finding the root locus on the real line. If so the complex roots don't matter because they always appear in conjugate pairs anyways. So if you add them in you will always get an even number (2) added to what ever poles and zeros are to the right of the point you are evaluating. Since adding 2 to an odd number leaves it odd and adding 2 to an even number leaves it even you can ignore the complex roots for this purpose.
You should consider only the on real axis.(i.e. only real numbers) not the complex poles that lies on the s- plane. 2+4j is a complete pole. You should not consider only 2.
@@saineethureddy6195 thanks but it's been 2 months since I've completed my xam
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@@mallamgurudeep1341 😂
nicely explained ☺️
Sir how imaginary part solve in caslo fx-991EX plz tell them...
Sir, what if the k value is negative is that okay?
Thank you sir🙏
Thank you 🤗
Angle of departure is 58 or 59 degree ,your calculated ans is wrong
how to know poles are complex or not ?
Thank you so much sir 💥🥰
When zero is ended with in real axis
Then there is no need to draw root locus from o to infinity?
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So angle of departure and break away point pass through same point as per cross imaginary axis sir?
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Amazing video
ua-cam.com/video/r3TlKbs7TKQ/v-deo.html
Thank you 💖
ua-cam.com/video/r3TlKbs7TKQ/v-deo.html
Sir how can we do code of this in the matlab ???
clear all;
clc;
s = tf('s');
disp('The given transfer function is,');
Gs = (s+9)/(s*(s^2+4*s+11))
rlocus(Gs,'k');
axis([-6 2 -6 6]);
sgrid;
I think it is like this... Just try this in Matlab
Thanks for clean explanation.
When is break away point?
Only if two poles are in adjacent
Thank you sir but u sound like a student :)
best video 😇
14:00 need link
Thank you so much 😊
Can teach today I have an exam tomorrow
Love you sir
Centroid will be -2.5 not 2.5
Superrrrrrrrrrrrrrrrrrrrrr explanation
Sir thee thanne 🎉
Athe athe... Mattanal alle mwuthe 😌
@@akaparz4109 mattannal endha machaa
Thank u souch sir
Thank you so much sir
VERRRRRY GOOOD
3 poles not 1 pole ... That's why odd
thankyou sir
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Thank you
thank you sir
Thanks a lot
Zeros are two know because u considered S= 0 in poles
Z1=0
Z2=-9
Replay bro I want clarity ?????????????????????????
And zero is even num
But u considering it's an odd number?
Replay 😊
ua-cam.com/video/r3TlKbs7TKQ/v-deo.html
.
Don't we write asymptotes as P-Z???
Thats the number of asymptots