dimensional analysis

Поділитися
Вставка
  • Опубліковано 5 лют 2025
  • This video shows what dimension analysis is.

КОМЕНТАРІ • 83

  • @christianmorgan4757
    @christianmorgan4757 9 років тому +22

    You explained this so much better then my physics instructor! thank you so much!

  • @andyquanmusic1
    @andyquanmusic1 2 роки тому +1

    Learned more through this video in 7 minutes than my professor in 2 hours. Thank you sir.

  • @baneebee
    @baneebee 5 років тому +6

    Thank you so much. I am not from science background. Still, I am able to understand your explanation. You are a great teacher. Thanks for making such a helpful video!

  • @friendofcanisgirl
    @friendofcanisgirl 10 років тому +15

    Thank you so much, you're a lifesaver! I understand the concept much better now.

  • @TraumaticGravy
    @TraumaticGravy 10 років тому +10

    just to point out those are not the only fundamental dimensions, they are the fundamental dimensions used in mechanics but there is also luminosity, current, substance amount and temperature :)

  • @nacerlifa
    @nacerlifa 2 роки тому

    Good video. Keep it up

  • @igciroc0478
    @igciroc0478 3 роки тому +1

    thanks I am in class right now and I could not understand, but you made everything so easy to understand.

  • @fahadahmed5338
    @fahadahmed5338 3 роки тому +1

    If anyone wants to do it another way, you can use Work = Force x Distance for the Energy part (Work is a form of energy)

  • @jordanhodge8069
    @jordanhodge8069 8 років тому +4

    Awesome video, really clarifies the concept.

  • @geraldshamulanga
    @geraldshamulanga 2 роки тому

    Great video well explained

  • @ThomasOfori-yb3jr
    @ThomasOfori-yb3jr Рік тому

    I really get rightfully thanks ur a magnificent and a great teacher🎉

  • @juliet5951
    @juliet5951 12 років тому +3

    "einstein was of corse right"...the best part!!!....nice vid...respect man!!!

  • @seringasuslaptop133
    @seringasuslaptop133 4 роки тому

    wow! i love the video.

  • @roselineofundem3082
    @roselineofundem3082 3 роки тому

    Thanks for that dude I appreciate you so much man

  • @englisheducationchannel2579
    @englisheducationchannel2579 2 роки тому +1

    Thank you so much it was so informative...was not it??even after 11 years ❤

  • @KSMM-153
    @KSMM-153 5 років тому +1

    Its very easy M se mass or C speed of light in vacuum & speed =distance/time so distance is L and time is T then we get LT^-1but we are given that mc^2 so (distance/time)^2 so we get L^2T^-2. So the dimension of E=mc^2 ML^2T^-2

  • @advaitmarde4599
    @advaitmarde4599 7 років тому +1

    Thank you because of you I was able to write the test

  • @TechDecryptor
    @TechDecryptor 3 роки тому +1

    Me watching this after eleven years!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! 😂😂

  • @mutungafrankline1181
    @mutungafrankline1181 4 роки тому

    you made me understand this thing better thanks

  • @ThomasOfori-yb3jr
    @ThomasOfori-yb3jr Рік тому

    Really this helped thanks sir

  • @snackdonw
    @snackdonw 8 років тому +4

    Thank u sirrrrrr......!!!!!!
    Thank u very muchhhhhh......!!!!!!!

  • @amjadkashmire4613
    @amjadkashmire4613 7 років тому +3

    thanks bro
    it's really help full

  • @hiteshsharma2814
    @hiteshsharma2814 3 роки тому

    Thanks sir love from india

  • @makeadifference7804
    @makeadifference7804 5 років тому

    DAMN!! I love you bro thanks

  • @zacharysylvester8349
    @zacharysylvester8349 6 років тому

    Velocity is the rate of displacement isn't it? As oppose to distance. Speed is the rate of distance. Velocity is a vector quantity and Speed is a scaler. In which case it would be [dLT^1]? But now that I think about it, delta length is still a length. Anyway some clarification would be great.

  • @bakugokatsuki48
    @bakugokatsuki48 7 років тому +1

    Oh thank you so much for this.

  • @jiogoguy8199
    @jiogoguy8199 3 роки тому +1

    👍👍👍👍👏👏👏🤜🤛

  • @stanleydrones
    @stanleydrones 5 років тому

    This was very helpful. Thank you!

  • @johnmusonda692
    @johnmusonda692 5 років тому +1

    i greatly appreciate

  • @chicken_land
    @chicken_land 10 років тому

    Thank you very much. ....you help me a lot

  • @TheNerd96
    @TheNerd96 9 років тому

    Great vid mate !

  • @ayanarafaat9253
    @ayanarafaat9253 6 років тому

    It's really helpful

  • @ibrahim--
    @ibrahim-- 3 роки тому

    Helped a lot

  • @Thexaxisacademy2023
    @Thexaxisacademy2023 4 роки тому +1

    O nthusitse fela thata 😌❤️ tanki

  • @ayanarafaat9253
    @ayanarafaat9253 6 років тому

    Wow thanks brother

  • @shahlaalfrih6230
    @shahlaalfrih6230 4 роки тому

    Thank you so much, now I get it ♥️

  • @johnmckiernan987
    @johnmckiernan987 Рік тому

    what about charge, is it dimensional?

  • @harvanshsahai1144
    @harvanshsahai1144 8 років тому +4

    Is 1/2 in KE ignored in such cases and if so,why??

    • @sasquashownz1
      @sasquashownz1 7 років тому

      Think it was just because the purpose was to show they have the same dimensions. (i.e. 0.5 is a unitless dimension, and therefore wouldn't affect it in terms of dimensional analysis). I know this is very late lol but just incase someone can reply an correct me

    • @firdauspuzi1145
      @firdauspuzi1145 6 років тому +1

      constant are ignored :)

    • @hrvojeduvnjak3676
      @hrvojeduvnjak3676 4 роки тому

      @@firdauspuzi1145 constants are not ignored if they have dimensions e.g ideal gas constant.

  • @JBone4eva
    @JBone4eva 13 років тому

    Thanks man, this really helped ! I appreciate it.

  • @tinisha401
    @tinisha401 7 років тому +2

    For KE, shouldn't it be = [ M x L^2 x T^-2 / 2 ] ?

    • @vanshrai7071
      @vanshrai7071 7 років тому

      tinisha bawa I

    • @DonjaDude
      @DonjaDude 6 років тому

      the constant has no dimension so the 1/2 isn't factored in at all

  • @erenlothbrok4736
    @erenlothbrok4736 5 років тому

    v.helpful thanks

  • @M7j3
    @M7j3 6 років тому

    Thanks bro you helped me

  • @abbasiabdulwahid9546
    @abbasiabdulwahid9546 6 років тому

    Thank you so much bro solved!!!!

  • @roseflower6132
    @roseflower6132 8 років тому

    dimensional analysis for frequency formula?????

  • @paulshakya4733
    @paulshakya4733 7 років тому

    THANK YOU SIR.......................

  • @bokamosothebe4243
    @bokamosothebe4243 8 років тому

    THANK YOU VERY MUCH SIR!

  • @nancynancysajiaji7451
    @nancynancysajiaji7451 6 років тому

    Thank you sir.

  • @SamirKastrati
    @SamirKastrati 10 років тому +1

    You are big :D

  • @morgsgg
    @morgsgg 8 років тому

    How do I solve this problem: A swimming pool measures 20 ft, by 10 ft, by 4 ft. If water has a mass of one gram per milliliter how many tons of water are in the pool? Do I go from feet to grams to ounces to pounds to tons? Also, I can't figure out how to go from feet to grams because I don't think you can do that since there is no conversion factor... SOS I just started physics and I'm dying.

  • @pantvaibhav8613
    @pantvaibhav8613 3 роки тому

    Its good.

  • @MajidEgypt
    @MajidEgypt 13 років тому

    i love you man

  • @alphacentary
    @alphacentary 11 років тому

    Sir I think you.You have explained dimensional analysis in 8 mins. It took my professor a good 3 hours to do the same. Note he never really answered he just jumped around it giving vague explanations.

  • @thefairyletters4152
    @thefairyletters4152 8 років тому

    I see, sounds easier than before. You are way (100 times) better than my physics teacher, Thank you. But I have a doubt, can you please clear it to me? Ke=1/2(mv)2 but why didn't 1/2 had any sort of effect in the dimension? I guess real numbers are usually ignored in dimensions... Please correct me if I'm wrong.

    • @anush7386
      @anush7386 8 років тому

      No is constant also pie is constant can br changed

  • @manuelcastaneda7838
    @manuelcastaneda7838 2 роки тому

    M[1]
    S[10]
    K[100]
    Q[1000] Coulomb
    D[10000] Temperature
    L[100000] Mole

  • @joelsaboimvula7431
    @joelsaboimvula7431 7 років тому

    Thanks

  • @zamelankuna7677
    @zamelankuna7677 9 років тому

    nice

  • @zackteb8648
    @zackteb8648 11 років тому +1

    thankssssssssss

  • @robertoperezzavala4403
    @robertoperezzavala4403 8 років тому

    Anybody knows how to solve this . . .
    Kinetic Energy, KE has dimensions (kg)(m^2)/(s^2). It can be written in terms of the momentum P, and mass m
    KE=p^2/2m
    a) determine the proper units for momentum using dimensional analysis

    • @yashrajsinghsolanki5487
      @yashrajsinghsolanki5487 7 років тому

      Roberto Perez Zavala MLT-1

    • @KisemboPhysicsAndMath
      @KisemboPhysicsAndMath 5 років тому

      watch some worked examples here ua-cam.com/video/rsz4PRAOiTg/v-deo.html, they could help you figure out how to solve the number

  • @honeybird956
    @honeybird956 9 років тому

    you saved my life xD

  • @kiwi.10th
    @kiwi.10th 3 роки тому +1

    lmao, uses dimensional analysis to prove Einstein right.. nah bro.. you used Einstein to prove dimensional analysis right

  • @CM-oy2kd
    @CM-oy2kd 6 років тому

    My brother

  • @mdmujahidali_shk5682
    @mdmujahidali_shk5682 5 років тому

    Nahi Sama g ai

  • @تقوىالرحمان-ح2ب
    @تقوىالرحمان-ح2ب 4 роки тому

    مفهمت والوا بخلاف المكتوب أما مايقوله الأستاذ لم أفهمه

  • @amyweber8669
    @amyweber8669 9 років тому +4

    like a someboo0o0o0o0o0dee tank u for duh help

  • @zamelankuna7677
    @zamelankuna7677 9 років тому

    nice

  • @aaronprice4608
    @aaronprice4608 4 роки тому

    nice