The equation (q=smdT) is from the perspective of the water, not the reaction. We know this because the value of s is for water, the mass is of the water, and the temp change is being calculated for the water.
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If “heat is leaving” the water, you have a negative q, which gives you a negative delta T. This allows you to use the standard equation of “delta T = final T - initial T”
thank you for breaking it down with quick explanations as to why you do what you do! very helpful
Isnt the heat flowing out of the flask and into the bath a exothermic reaction? making q negative not positive.
The equation (q=smdT) is from the perspective of the water, not the reaction. We know this because the value of s is for water, the mass is of the water, and the temp change is being calculated for the water.
so if calculating the delta temp is dividing the heat flow by the heat capacity by the mass, why is everything in parenthesis? This was confusing.
Click here to learn how to understand parentheses in math: study.com/learn/lesson/parentheses-math-rules-examples.html#:~:text=Parentheses%20in%20math%20are%20sets,solved%20first%2C%20followed%20by%20exponents.
I got it wrong because it said I had to subtract the initial from the total because "the heat is leaving" ;-;
If “heat is leaving” the water, you have a negative q, which gives you a negative delta T. This allows you to use the standard equation of “delta T = final T - initial T”