Thevenin's Theorem with Dependent Sources
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- Опубліковано 5 сер 2024
- Network Theory: Thevenin's Theorem with Dependent Sources
Topics discussed:
1) Calculation of Thevenin's Equivalent Voltage Vth when a dependent source is present in the network.
2) Calculation of Thevenin's Equivalent Impedance Rth when a dependent source is present in the network.
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SIR THE WAY OF EXPLAINING EACH AND EVERY CONCEPT IS EXCELLENT AND CLEARLY UNDERSTANDABLE.PLEASE MAKE MORE VEDEOS FOR US.ITS A HAPPY AND EASY WAY OF LEARNING.TQ SIR HAVE A GOOD DAY.
Much appreciated Sir 😊
3secs
Eov=40v(I=0A,0.8I open)
Isc :short current 40=6I+10(0.8I+Isc),I=Isc
So 40=24Isc
Isc=5/3A
Rth=Eov/Isc=40/5/3=24 ohm
Dependent sources? More like “Dynamite this is!” Thanks for sharing all of these amazing videos; they’re super helpful.
Legends are watching this while going to gate exam 😁
😯 noted
They are not legend...they are just chutiya
True
Bhai, unka GATE qualify hoga kya? Jo aisi legend baazi karte hei!?
True 😅
Awesome video! Thank you!
thank you, sire!
sir your video are really helping me. i got test tomorrow , its actually my final test for semester 3. I hope you wish me the best to do it and your videos really help me with my exams tomorrow.
How’d your final go?
he failed@@PunmasterSTP
@@kromokyptians5g51 Yeah, maybe, but I'll still hold out hope. It's just what I do. And sometimes the OP does reply to some of my similar comments!
Wao great sir...
Very useful content...thanx
Very helpful thanks
Nice. In place of 1 V, a test source V_0 can also be put such that it is giving a current I_0. Then R_{th} can be found by finding V_0 / I_0.
I put a current source of I0 = 1 there, but I did not get the same Rth. As I = 1, the current going through the 10ohm resistor would be 0.2; the current going through the 0.8I current source would be 0.8, which means the equavalent resistance of the current source would be 2ohm. Since Rth would be 10||2 + 6 = 23/3. Why is that the case?
Can someone help me, I would really appreciate it
@@kristonwang6779I tried but got different result myself. Current across 10Ω resistor was indeed 0.2A, thus the principle node has 2V potential voltage and voltage at the positive edge of the 1A source would be equal to 2+6*1=8V while the negative edge of the source would be 0V because it is connected to the ground and finally R_Th=(8-0)/1=8Ω, not 24Ω. I am not sure why that is...
@@lapisbrainprint9607 I got the same answer even with current source.
Introduce 1A current -> I = -1A -> -0.8A (dependent source) -> solve nodal eq to get V_x = 18V ->. know that V_Th = V_x + V_(6ohm).
V_(6ohm) = 6ohm*1A = 6V
so V_Th = 18+6 = 24V thus R_Th = 24/1 = 24ohm
amazing explanation
usefull explanation thank you sir take love
I tried it by myself and it took me about 3 minutes and mentally done. I'm trying to formulate a new method that can be applied to dependent sources. Wish me luck
Please share it with us😊
Very good question sir thanku
Sir when you calculate RTH, why don"t you use the dependent source zero (since I=0) that is open circuit
Good work bro
Sujeet Sir is the best
Another solution is to find norton current by short circuiting load, then finding Rth=Vth/In
Thank you sare
How did you remove that dependent source sir??
It's dependent on a part of the circuit that has an open node (Node A isn't connected to anything), though open nodes can have electrical potential difference (voltage), without the wires being connected, the current is zero, so the dependent current is 0 * 0.8, which is zero.
Think about how if a wire is live, there's no current, but you don't want to touch the wire because it has an electrical potential (Voltage) that will send a current through you IF you complete the circuit by touching it with your hand. But if nothing ever connects, then nothing happens, no electrons move, no current in that part of the circuit.
Because he used a simple as fubbernuck circuit for this demonstration, just like colleague profs, but in reality, you will never encounter a circuit this simple if you are dealing with dependent source, and therefore equations become way harder to deal with and I think no prof. has time to show it(or talent to solve it).
@@aidanabregov1412 Hello Sir, How do we know that this dependent source is depends on that open path only. Because this dependent source is connected to voltage source as well. Kindly guide me...
@@babajighule1964 1:22 gives the explanation. It's because there is no current if there's nothing grounding node A. There's infinite resistance at the open node, and if resistance is infinite, current, I, is zero. If the electrons have nowhere to go, then they can't "flow" or generate current.
Thanks
PLEASE SIR PUT ALL VIDEOS NETWORK. And other ELECTRICAL subjects also.
for rth cant we take o.o8i as o as it is dependent source
great video Sir, you make it easier to understand
Sir 🙌
Nice❤
how 0.8 i is zero
Sir आप इतना अच्छा पढ़ाते हो बस आप का lecture पूरा nahi है अगर आप का lecture पूरा मिल जाए तो student को लाखो रुपए gate exam के लिए दिल्ली खर्च नही करने पड़ेगे
Koshish kar rahe hai subjects complete karne ki.
Sir how are you simplying?
Would i(NORTON) be 1.67 Amps?
why do we assume that vx has the highest voltage?
🔥🔥🔥
If I didn't mistake then there maybe a calculation problem in equation 1. Maybe u are supposed to write 1.8I instead of 18I.
i also though there was a mistake but , its 18 , he is correct, he just skipped a step , (i guess)
how could vx - 1v? i dont understand
why is the current source reduced to 0
Sir, actually we can put Is to be o.c and Vs as s. c na sir
Then we get different Rth
Will u pls explain sir
Nope we will get the same ans by that method too, i did it myself.
Isn’t 1.8 i1 instead of 18 i1?
🙏
Sir can you please explain again how did you get the value "I=0" ?While calculating the value of Vth
there is the open circuit na so I =0
Thanks
Greatest 👌 thank u
❤️❤️❤️
Sir ,when V=0(short circuit) across element but we have v=ir which is i=0 (open circuit).can u explain it how???
V=IR
If V=0, current flows unimpeded across the wire with no build up of electrons making an electric potential difference (Voltage).
But if I=0, then no current can flow across at all, so it is represented by an open circuit. You could also imagine a really really large resistor is there. Think about the electrons going across a wire as current. If current is zero, then the electrons cannot move any further, as if the wire was cut open.
'i' isn't equal to zero but rather it'll be 0/0 (indeterminate form). When do you get v=0? When r=0. So when you'll apply v=i*r to find i then i=v/r which would be 0/0.
when finding Vth, can anyone elaborate how the current dependent source is reduced to 0?
Coz it was dependent to the I given in the first diagram which is O in an open loop
@@chefcarry2902 isnt the dependent current source dependent on the independent voltage sources and not just the current only?? if so thhen why equal it to zero??
@@estherkatentazimba4322 The dependent Current source was specified as "0.8I" which means it is dependent to the I stated in the circuit which is in an open loop.
@@chefcarry2902 ohh 😯 now i see it
@@chefcarry2902 Do you know why I is not zero in case of finding Rth while it is zero in case of finding Vth although in both cases we find voltage or equivalent resistance across the terminals?
Sir how can u use kvl to find vth since it is not a closed loop
Are you referring to an open circuit in the loop?
just assume it is a closed loop and use KVL
Is it valid to consider a dependent current source as an open circuit?
My engineering professor said this isn’t possible
The value of the dependent source is 0.8i. since I is equal to zero hence the value of the source becomes zero
😂
Why can't we make the dependent current source's value equal to 0 while finding Rth. It'll make Rth=16 Ohm. The current source's value must be zero because it'll be dependent on 'I' for all time and 'I' will be zero like it was while finding Vth.
Exactly
Thodi difficult circuits solve kro
Introductory lectures me nahi kar sakte, sabko nahi aayega samajh. Baad me GATE ke questions solve hue hai.
@@nesoacademy Pura Playlist kaha Hai?. Also, where can I find the entire content?
Vx=1/4 V, hence I= 1/8A,u did a little calculation mistake at 6:52
I made the same mistake as you, but it's actually correct as you need to distribute 3 to both terms when multiplying the fraction
bhai mushkil question liya karo thoda .......... aise sirf yehi question hoga ........baki nahi
What a terrible selection of example where I is 0