You dont have to put down something just to appreciate some other thing! Professor Dave is awesome and so is Hank Green. They both have different styles of teaching. Prof. Dave teaches in a calm & composite manner. Hank teaches in a more fun & hands-on kinda manner. And I think both are amazing in their own unique ways.
you're a mother born teacher. Your teaching techniques easily stays above all other fancy channels. Please create more series. I'm watcging many of your series entirely.
This was explained exceptionally well! The visuals you provided along with the simple explanations made these formulas soooooo much easier to understand. Thanks You Professor Dave!
i’m refreshing up on my chemistry as i’m planning on taking it next year in college, but i haven’t actually done anything in over a year 1/2. your videos are amazing and they’re great for getting me back into it!
Myghadddd U R AN ANGEL SENT FROM HEAVEN. WE HAVE A TRIMESTRAL EXAMINATION TOMORROW AND OUR TEACHER’S PPTs DOESN’T EVEN MAKE SENSE TO ME. BUT THEN I FOUND YOUR VIDEO AND FOR A SPAN OF 11 MINS (cause i watched 2) I UNDERSTOOD EVERYTHING RIGHT AWAY. YOU DESERVE A MILLION SUBSCRIBERS 🙌🙌🙌
Currently enrolling in Canadian high school as an international student. My dream is to be a tutor like you in my country. You are truly an inspiring figure, Prof. Dave. Thanks for all the contents, I cannot thank you enough.
i used to know this material when i was in university. Such a joy to have it all come back in a few minutes. And Prof. Dave is very easy on the eyes too. Love him
Professor Dave, I can't tell you how much your face on a UA-cam video gave me relief when I saw this in chemistry. As soon as I saw the intro I was like "Hey, isn't this the guy that completely destroyed flat Earth?" amazing. I just went back through my google classroom, and rewatching this is so much better than having to go back through all slideshows for everything. Thanks professor Dave for existing.
Just because the actor portraying Jesus in a movie looks like that, short hair with a beard and all, doesn't mean that's what Jesus really looks like. Only the people in his time on earth knows what he looks like lol.
@@glennmnte9488 If you don't know what the other person is exactly talking about then better not to comment. The word "Messiah" means - A leader regarded as the saviour of a particular country, group, or cause and here she is not referring to 'jesus'.
الغازات المثالية - مميزاتها : ١) الجسيمات في الغاز هي تقاط بلا أبعاد في حركة عشوائية . ٢) لا تتفاعل بغض النظر عن التصادمات فهي مثل كرات البلياردو . اربع اشياء للمناقشة ١) الضغط . ٢) درجة الحرارة ، ومدى سرعة حركتها ؟ ٣) الحجم . ٤) المولات . كلما قلَّ الحجم ازداد الضغط ويمكن التعبير عنه بقانون بويل : P¹V¹=P²V² اي انه اذا انحفض أحدهما ارتفع الآخر . مثال القانون : 1atm • 1L = 2atm • 0.5L اذا ازدادت درجة الحرارة ازداد الحجم . قانون تشارلز : V1\T1 = V2\T2 . 1 كلفن= 1 درجة سيلزية K = C° + 273 للحصول على كلفن C = K° - 273 للحصول على درجة سيليزية قانون افاغاردو V1\N1=V2\N2 قانون الغاز المثالي : PV = nRT R = ثابت الغاز R = 0.0821 • L•atm\mole•K . اذا قلنا ان درجة الحرارة 313k والحجم 2.3L والضغط 1.5atm . فإن القانون PV=nRT صالح للتنفيذ ، هكذا : نعوض (1.5atm)(2.3L)=n(0.0821•L•atm\mole•K)(313k) بإختصار الناتج : 0.13moles . اذا حصلت على ثلاثة متغيرات من أصل اربعة استخدم قانون الغاز المثالي واذا لم تحصل عليها استخدم القوانين القديمة : P1V1=P2V2 V1\T1=V2\T2 P1v1\T1=P2V2\T2
Can you please check am I right ( my answers are 1,3,4): For an ideal gas which of the following statements are correct: 1. Increasing the temperature of a gas at a constant pressure increases its volume 2. Increasing the pressure of a gas at a constant temperature increases its volume 3.Increasing the temperature of a gas at constant volume increases its pressure 4.At the same temperature and pressure one mole of helium gas occupies the same volume of one mole of argon gas 5.The ideal gas law applies only to monoatomic gases. thank you :-)
As a planetary astronomer dealing with atmospheres, I'm much more comfortable using SI units, a weird unit we thought up for atmosphere chemistry called the kilomole (1 kmol = 1,000 mol), and an appropriately adjusted SI value of R (8,314.4598 J K^-1 kmol^-1). But I suppose if I had to deal with amounts of gas that could fit in vessels and tubes in a chem lab, I'd use the units you use here!😁
These videos are beneficial for everyone in the internet, I applaud your efforts to educate people! I have one small question. How did scientists calculate the conversion between Kelvin and Celsius?
when i watched crash course i was sure i was gonna have an especially hard time with this topic, but after watching ur video i feel way more confident about all this lol
The way of your explanation is tooo good in one explanation I understand all the topic sir thank you very much for uploading this video in youtube I'm ur new subscriber you r explaining the whole topic in 5 min which my teacher explains in one hour once again thank u very much sir for uploading this video 👍🏾
3:23 I still don't understand how the gas constant works. EDIT 1: I mistakenly thought that 'R' equals '0.0821 multiplied by whatever fraction shown on the right'. Am I correct in saying that the fraction at the end of the equation symbolises the many units for the number '0.0821'? Like, for example, the user can freely choose to use the unit 'L', making 'R = 0.0821L'? EDIT 2: Okay, I get it now. At 4:29, in the longest equation under the second question, the aforementioned units are necessary for the other units to cancel out in both the numerator and denominator of the fraction. To quote Professor Dave himself at 3:26, the gas constant (R) "makes these calculations intelligible in our man-made units."
Can't believe I watch physics videos because I play a computer game where I do something that requires knowing of gas laws 😂 Nice video btw, I looked for visualization of the gas behavior and this one was perfect.
Oskar Olszewski i don’t know if this could help but maybe bc the problem is not at STP? So maybe it’s not acceptable to assume that the volume and mole is 22.4L and 1mol, initially
Hey guys, I wanted to ask you something. I’m a foreign student and in my country we don’t use decimal numbers much. Instead, near whole numbers are given in the questions. therefore, we don’t need nor use calculators while solving questions. Given these circumstances, I realized I don’t really know how to do these calculations 🫠 I was wondering if the calculations in checking comprehension part require a calculator, or am I expected to be able to do the calculations without it? It’d be greatly appreciated if you could answer me 🫶🏻
You can see that when the balloon expand the molecules inside began to slow down it mean the temperature goes down so its inversely and not directly proportional
BeatsByGuillermo well I believe that God’s creation is a big work of art, and the science of His creation is like the simple, yet extravagant detail (like shading, brushstrokes, etc. that one would see on a drawing or painting) that bring beauty and life to the bigger picture 😊
Hi Professor! Thank you so much for your videos!!. I have a question. Is it possible to *increase the pressure* and at the same time *not to increase the temperature* as a result of this? I think about the diesel motors (for example) that use high pressure for diesel to ignite within the piston and cause the explosion, which I think is because the increase in pressure *heats* the diesel enough as for this to explode (the increase in pressure increases, *consequently,* the temperature).
sure one can definitely keep temperature constant! compression will not always be accompanied by temperature increase. this is called an isothermal process.
thank you for replying professor! This is a bit counterintuitive to me though. I found something on Wikipedia _en.wikipedia.org/wiki/Isothermal_process_ _...Doing work on the gas increases the internal energy and will tend_ _to increase the temperature..._ it says (to me) that the increase in pressure increases the internal energy, which needs to leave the system for the temperature not to change (going to the environment as heat). So there is an increase in temperature just that the system makes up for this by releasing such heat. Is there any instance in which increase in pressure would not make us deal with heat production (for us not even to need to get rid of any produced heat?)
yes that would be an adiabatic process! and in fact, boyle's law talks about pressure and volume changing with temperature remaining constant. so it's just about tweaking the parameters.
Sir, Very nice and clear explanation I have no doubts at all thankyou so much for this lesson. I'm B.sc Ist year student I haven't join any coaching for physics Sir, I beg to you... please make more about physics chapters plsss!!!!
I like the calm and concise delivery. No zany personality, no senseless entertainment gimmick. Just a solid breakdown of what, how, and why.
Gracias.
Better than Crash Course, if I may. Less drama, more facts delivered in a calm and composed manner.
I love both of these channels.Yeah there is much drama by Hank but information and its explanation isn't a dumb one because of that.
Legit
Aadithya Hrudhay hank makes me anxious
You dont have to put down something just to appreciate some other thing! Professor Dave is awesome and so is Hank Green. They both have different styles of teaching. Prof. Dave teaches in a calm & composite manner. Hank teaches in a more fun & hands-on kinda manner. And I think both are amazing in their own unique ways.
Composed* lol
Thank You for taking a 3hr lecture and compressing it into 5 mins! You're doing great Prof!
Yeah, but he's way too fast. Don't you think so?
@@mideafinni-jegede8829 Yeah, but its also a video... you could always go back.
Yeah i do.....Thanks for the reply.
@@andynguyen6341 absolutely agreed
This is brief nd very comprehensible ....but I think you must have studied to an extent to grab this real quick....a starter won't really get it
you're a mother born teacher. Your teaching techniques easily stays above all other fancy channels. Please create more series. I'm watcging many of your series entirely.
This was explained exceptionally well! The visuals you provided along with the simple explanations made these formulas soooooo much easier to understand. Thanks You Professor Dave!
i’m refreshing up on my chemistry as i’m planning on taking it next year in college, but i haven’t actually done anything in over a year 1/2. your videos are amazing and they’re great for getting me back into it!
I've never learned chemistry so efficiently. Your 5 min vid > a full lecture.
Professor never stop uploading videos... Because your videos are a big help... Thank you
can't stop don't stop won't stop!
Professor Dave Explains hahaha you are the best professor, no lie 😁😂
Myghadddd U R AN ANGEL SENT FROM HEAVEN. WE HAVE A TRIMESTRAL EXAMINATION TOMORROW AND OUR TEACHER’S PPTs DOESN’T EVEN MAKE SENSE TO ME. BUT THEN I FOUND YOUR VIDEO AND FOR A SPAN OF 11 MINS (cause i watched 2) I UNDERSTOOD EVERYTHING RIGHT AWAY. YOU DESERVE A MILLION SUBSCRIBERS
🙌🙌🙌
Currently enrolling in Canadian high school as an international student. My dream is to be a tutor like you in my country. You are truly an inspiring figure, Prof. Dave. Thanks for all the contents, I cannot thank you enough.
i used to know this material when i was in university. Such a joy to have it all come back in a few minutes. And Prof. Dave is very easy on the eyes too. Love him
thanks sir! i didn’t get it when my teacher told us about this but your short and to the point method really works for me :^D
giveyouthesun m
Same as here thanks much
Another 5 minutes of pure genius.
Thank you Professor Dave !
Dave you are literally saving my life THANK YOU
What a teacher! Taught me something in 5 minutes which couldn't be explained by my school teacher in 1 hour! 😆😇😈
If u listen ur teacher will also say in 5 min
Relatable
your is 1hr,mine is for years now
@@lakshmikallam8204 Not necessarily true
Professor Dave, I can't tell you how much your face on a UA-cam video gave me relief when I saw this in chemistry. As soon as I saw the intro I was like "Hey, isn't this the guy that completely destroyed flat Earth?" amazing. I just went back through my google classroom, and rewatching this is so much better than having to go back through all slideshows for everything. Thanks professor Dave for existing.
I just farted and here I ended up at the Ideal gas law.
Thank you so much Professor Dave! I had a hard time understanding our chemistry class and this video really helps me a lot😊
You look great just like a Chemistry Messiah.
Just because the actor portraying Jesus in a movie looks like that, short hair with a beard and all, doesn't mean that's what Jesus really looks like. Only the people in his time on earth knows what he looks like lol.
@@glennmnte9488 yeah 😄😄
Doesn't mean He even exist😂
@@glennmnte9488 If you don't know what the other person is exactly talking about then better not to comment. The word "Messiah" means - A leader regarded as the saviour of a particular country, group, or cause and here she is not referring to 'jesus'.
Not look, he is
Wow for 5 minutes I've learnt more than my lecture notes, amazing.
This guy is better than my physics teacher!
What a lifesaver
thanks for the explanation bruhh!!!!!
الغازات المثالية - مميزاتها :
١) الجسيمات في الغاز هي تقاط بلا أبعاد في حركة عشوائية .
٢) لا تتفاعل بغض النظر عن التصادمات فهي مثل كرات البلياردو .
اربع اشياء للمناقشة
١) الضغط .
٢) درجة الحرارة ، ومدى سرعة حركتها ؟
٣) الحجم .
٤) المولات .
كلما قلَّ الحجم ازداد الضغط ويمكن التعبير عنه بقانون بويل :
P¹V¹=P²V²
اي انه اذا انحفض أحدهما ارتفع الآخر .
مثال القانون :
1atm • 1L = 2atm • 0.5L
اذا ازدادت درجة الحرارة ازداد الحجم .
قانون تشارلز :
V1\T1 = V2\T2 .
1 كلفن= 1 درجة سيلزية
K = C° + 273 للحصول على كلفن
C = K° - 273 للحصول على درجة سيليزية
قانون افاغاردو
V1\N1=V2\N2
قانون الغاز المثالي :
PV = nRT
R = ثابت الغاز
R = 0.0821 • L•atm\mole•K .
اذا قلنا ان درجة الحرارة 313k والحجم 2.3L والضغط 1.5atm .
فإن القانون PV=nRT صالح للتنفيذ ، هكذا :
نعوض
(1.5atm)(2.3L)=n(0.0821•L•atm\mole•K)(313k)
بإختصار الناتج : 0.13moles .
اذا حصلت على ثلاثة متغيرات من أصل اربعة استخدم قانون الغاز المثالي واذا لم تحصل عليها استخدم القوانين القديمة :
P1V1=P2V2
V1\T1=V2\T2
P1v1\T1=P2V2\T2
Thank you professor Jesus
Thank you science Jesus
Broooooo😂
😂😂true
?🤣🤣
I love your videos. Straight on point, simple and concise
Can you please check am I right ( my answers are 1,3,4): For an ideal gas which of the following statements are correct:
1. Increasing the temperature of a gas at a constant pressure increases its volume
2. Increasing the pressure of a gas at a constant temperature increases its volume
3.Increasing the temperature of a gas at constant volume increases its pressure
4.At the same temperature and pressure one mole of helium gas occupies the same volume of one mole of argon gas
5.The ideal gas law applies only to monoatomic gases.
thank you :-)
you're correct!
Professor Dave Explains Thank you for your lectures! Very helpful!!!
You explained this very visually and rationally. Thank you!
I must applaud you for explaining this in a very much simple manner. Thank you professor Dave!
Thank you, For your Precise Explanation Professor. Keep up the Good Work👏💖
As a planetary astronomer dealing with atmospheres, I'm much more comfortable using SI units, a weird unit we thought up for atmosphere chemistry called the kilomole (1 kmol = 1,000 mol), and an appropriately adjusted SI value of R (8,314.4598 J K^-1 kmol^-1). But I suppose if I had to deal with amounts of gas that could fit in vessels and tubes in a chem lab, I'd use the units you use here!😁
the most simplified on youtube... short video and complete information
best channel for high school science
this video was insanely helpful
Probably the best explanation of kinetic theory. Thanks prof!
These videos are beneficial for everyone in the internet, I applaud your efforts to educate people!
I have one small question. How did scientists calculate the conversion between Kelvin and Celsius?
Prof is a blessing fr. The scientific saviour
when i watched crash course i was sure i was gonna have an especially hard time with this topic, but after watching ur video i feel way more confident about all this lol
man you are doing perfectly, what you are supposed to.
Sir your teaching skills are better then best
who else is watching tons of Professor Dave's videos morning before a test?
The way of your explanation is tooo good in one explanation I understand all the topic sir thank you very much for uploading this video in youtube I'm ur new subscriber you r explaining the whole topic in 5 min which my teacher explains in one hour once again thank u very much sir for uploading this video 👍🏾
You explain things so easily and simply! Thanks for saving my chemistry grade :)
The best teacher online ❤️❤️❤️❤️
Ultimate clarity brother
Wow! 1M subscriber congrats 🎊🎉
2 million coming soon
Sir Dave I love ur Explaining Style.. Awesome
you know you should have a lack million quadrillion subscribers because you teach soo well
i'll take a quadrillion subscribers please! tell all your friends!
Amazing explanation
thank you professor
3:23 I still don't understand how the gas constant works.
EDIT 1: I mistakenly thought that 'R' equals '0.0821 multiplied by whatever fraction shown on the right'.
Am I correct in saying that the fraction at the end of the equation symbolises the many units for the number '0.0821'?
Like, for example, the user can freely choose to use the unit 'L', making 'R = 0.0821L'?
EDIT 2: Okay, I get it now. At 4:29, in the longest equation under the second question, the aforementioned units are necessary for the other units to cancel out in both the numerator and denominator of the fraction.
To quote Professor Dave himself at 3:26, the gas constant (R) "makes these calculations intelligible in our man-made units."
Explanation I was looking for. Thanks.
This was really really helpful
Thank you ❤
straight to the point! everything is so clear. I m ur big fan
always find your videos easy to understand than any other's
Professor Dave, you're the best. Thank you!
Thank you Proff. You're a life saver
Thank you so much sir . you delivered in a calm way.
This is well explained and easy to understand thank you sir
Thank you professor Dave!😌
I understood so well
Thank you sir.
I now have an understanding on Gas😊
Can't believe I watch physics videos because I play a computer game where I do something that requires knowing of gas laws 😂
Nice video btw, I looked for visualization of the gas behavior and this one was perfect.
which game you had played ?
@@harshsuthar7178 Stationeers
Why if you use the ideal gas law you get 13L and if you just use volume and moles (22,4 × 0.785) ÷ 1 = 17,6L?
Oskar Olszewski i don’t know if this could help but maybe bc the problem is not at STP? So maybe it’s not acceptable to assume that the volume and mole is 22.4L and 1mol, initially
That's alot you explained really nice and you made me understand without any hesitation.
This was taught very well, thx
Finally you got another subscriber
Thank you. This was real helpful.
Awesome and uis probably one of the best education channels
Sir, your videos are used for our lecture! Thank you
Love your work
hey professor dave i guess u and ur team can start some kind of online courses.It would really be helful for us
really interesting and easy to understand
Thanks... This was amazing... I'm satisfied with ur teaching...... You're better than crash course
hey dave thanks for making videos ....
I can’t explain how easy and fast understanding this vedio
Thanks big man ur helping me pass my science final
very good explanation
Hey guys, I wanted to ask you something. I’m a foreign student and in my country we don’t use decimal numbers much. Instead, near whole numbers are given in the questions. therefore, we don’t need nor use calculators while solving questions. Given these circumstances, I realized I don’t really know how to do these calculations 🫠 I was wondering if the calculations in checking comprehension part require a calculator, or am I expected to be able to do the calculations without it? It’d be greatly appreciated if you could answer me 🫶🏻
You can see that when the balloon expand the molecules inside began to slow down it mean the temperature goes down so its inversely and not directly proportional
yeah, don't go by this animation.
who knew Jesus taught chemistry!!
well Jesus is the author of life and kinda created chemistry, so He'd be the best teacher for it, right?
@@ECjj33 I don't understand how one could adhere to science and believe in god/heaven/miracles at the same time
BeatsByGuillermo well I believe that God’s creation is a big work of art, and the science of His creation is like the simple, yet extravagant detail (like shading, brushstrokes, etc. that one would see on a drawing or painting) that bring beauty and life to the bigger picture 😊
He knows a lot about the science stuff, its professor jesus explains
@@ECjj33 I might be wrong but isn't Jesus the son of God and god made chemistry and stuff in genesis. IDK i might be completely wrong
The Messiah Of Chemistry
Hi Professor! Thank you so much for your videos!!. I have a question. Is it possible to *increase the pressure* and at the same time *not to increase the temperature* as a result of this? I think about the diesel motors (for example) that use high pressure for diesel to ignite within the piston and cause the explosion, which I think is because the increase in pressure *heats* the diesel enough as for this to explode (the increase in pressure increases, *consequently,* the temperature).
sure one can definitely keep temperature constant! compression will not always be accompanied by temperature increase. this is called an isothermal process.
thank you for replying professor! This is a bit counterintuitive to me though. I found something on Wikipedia _en.wikipedia.org/wiki/Isothermal_process_
_...Doing work on the gas increases the internal energy and will tend_
_to increase the temperature..._
it says (to me) that the increase in pressure increases the internal energy, which needs to leave the system for the temperature not to change (going to the environment as heat). So there is an increase in temperature just that the system makes up for this by releasing such heat. Is there any instance in which increase in pressure would not make us deal with heat production (for us not even to need to get rid of any produced heat?)
yes that would be an adiabatic process! and in fact, boyle's law talks about pressure and volume changing with temperature remaining constant. so it's just about tweaking the parameters.
OK profesor!! Thank you for replying!
Thank you so much sir
I was so confused 5 minutes ago and now I feel ready for the ACS😎
this 5 minutes were better than my 3 months of school
I loved the working in chemistry 🔥🔥🔥🔥
Sir, Very nice and clear explanation I have no doubts at all thankyou so much for this lesson.
I'm B.sc Ist year student I haven't join any coaching for physics Sir, I beg to you... please make more about physics chapters plsss!!!!
You’re love professor dave❤️❤️
Thank you so so much
Great videos!
Love the video keep making it.
If I had such teachers 20 years ago...
You’re a genius
This was excellent!!
much helpful thanks😄
My students and Iove professor Dave! Always just right👩🏻🔬
Very useful thank you!
How I wish you have a cut on my instructor's salary because he orders us to watch your videos
Very nice teaching skils
i hate chemistry, i hate physics, i hate biology, i hate maths methods, i hate essays. but this made it more interesting. thanks