inverse laplace transform, example#5, with completing the square
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- Опубліковано 4 жов 2024
- inverse laplace transform,
inverse laplace transform example,
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You just saved me several hours of going through textbooks; you've made this unit so simple! Thank you sir.
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Ur videos are awesome !!!! one year b4, Laplace was still a nightmare to me , but now, all things become easier and clearer after watching ur videos!!! Thanks !!!!
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blackpenredpen
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Never learned 1/2(xs)^2 to c.t.s
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from where did the exponential come in the end
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im confused, (e^-4t)*cos3^.5*t gives me a laplace of s/s^3 +4s^2 + 3s + 12,, how does that have s+4 on the numerator?
Awesome😎
THANKS
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Life saver 👏🏻
Valeu meu cria
if it was -8 instead of +8, do we multiply (1/2 * - 8)^2 or just multiply by 8 without the minus?
what do u mean by shifted?
In mathematics you have negative but in physics there is no negative but relative movement is considered negative.
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love you
excellent
Imran Ahmad ibne sayedah thanks!
math magic
Why the e^(-4t)? According to my chart i see why you got the sin and cos. Is it because of that +4?
By applying L^-1 {F (s - a)} = e^at f(t)
do you have a video where, we need to complete the square on the numerator now. because that is where im stuck
complete the square on the "numerator"? how come?
when you have a function of F(s)/G(s). on this case you have your function of F(s) stating with S^2(S to the exponent 2). i am not sure if i make any sense... Another question, do you have videos on CONVOLUTION PRODUCT AND INVERSE TRANSFORM. THANK YOU
thank u sir aswome
thank u sir awesome
how to calculate laplace for s/s+8
Richa Awasthi s/(s+8) = 1-8/(s+8). Inverse laplace wud be L^(-1)= delta function-8e^(-8t)u(t)
What if it is 5s/s^2-25 ?
Well, this is a bit late, but L^-1{5s/(s^2 - 25)} = 5 L^-1{s/(s^2 + (5i)^2)} = 5cos(5it) = 5cosh(5t).
In general, if you have the inverse laplace transform of s/(s^2 - a^2) then it leads to cosh(at), and if it's a/(s^2 - a^2) then it's sinh(at).
hello your videos are really helpful, can you make video of how to use these laplace transforms in matlab ltiview as well?!
Inverse Laplace transforms can't get harder than this, can they?
s/((s^2+4)(s+1)) how can I solve this with partial fraction
nicenice
zajebiscie
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I can't understand ur language pronouncesation so plz give the caption option