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The way he runs.... He doesnt even wait for 'thank you sir'.
2:08 I laughed at " do not put a +C because this is not integration ".
Thx gangsta. i love u daddy blackpen
Thank you You are making the point
3!=6 so can you skip a step? More specially the step where you take 6 out of the inverse Laplace transformation and put 3!/3! in the equation. Just introduce 6=3!
I guess it's in order to teach the general solution to these things...
Thank you man!!! That’s what I wanted!!
Thank you
THANK YOU
Find Laplace inverse of 2s+3/(s+3)^3 and S^2/(s-1)^4
did you ever find it? xDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDD
thanks
Magnificent
Thank u sir
You said you recommend doing it this way ...is there any other way?
Convolution
@@mallakbasheersyed1859 how he said it i knew there was a way to kill it too..haha thanks
@@brianramz6681 wlcm
Actually it is integration, but improper
What if it was a 2 instead of a 6, how will it be solved?
Multiplying the constant 1/3 to the final solution would do, if you multiplied 3/3 to the initial problem and only removed 1/3 from the equation
are you god
Inverse Laplace of {1/p²(p-5)²}
=(2/5 + t -2e^5t/5+te^t)/25
First you need to use Partial Fraction and then solve, it would become easy.
Is it helpful?
I dont think putting the 6 at the front is more "systematic." Who cares? If it works it works.
The way he runs.... He doesnt even wait for 'thank you sir'.
2:08 I laughed at " do not put a +C because this is not integration ".
Thx gangsta. i love u daddy blackpen
Thank you
You are making the point
3!=6 so can you skip a step? More specially the step where you take 6 out of the inverse Laplace transformation and put 3!/3! in the equation. Just introduce 6=3!
I guess it's in order to teach the general solution to these things...
Thank you man!!! That’s what I wanted!!
Thank you
THANK YOU
Find Laplace inverse of 2s+3/(s+3)^3 and S^2/(s-1)^4
did you ever find it? xDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDD
thanks
Magnificent
Thank u sir
You said you recommend doing it this way ...is there any other way?
Convolution
@@mallakbasheersyed1859
how he said it i knew there was a way to kill it too..haha thanks
@@brianramz6681 wlcm
Actually it is integration, but improper
What if it was a 2 instead of a 6, how will it be solved?
Multiplying the constant 1/3 to the final solution would do, if you multiplied 3/3 to the initial problem and only removed 1/3 from the equation
are you god
Inverse Laplace of {1/p²(p-5)²}
=(2/5 + t -2e^5t/5+te^t)/25
First you need to use Partial Fraction and then solve, it would become easy.
Is it helpful?
I dont think putting the 6 at the front is more "systematic." Who cares? If it works it works.