You are amazing! I just saw your videos. I have been having problem on Laplace Transform, especially the Inverse Laplace...but the way you solve it is very simple and well understood. Thanks...Jude from Nigeria
Grabe naman po to maam! Napakalinaw po ng pagkakaturo nyo. May methods den po kayo na inintroduced na ngayon ko lang nalaman! Maraming salamat po maam. Sobrang malaking tulong po ito at may quiz kami mamaya abt Inverse Laplace! Rerecommend ko po tong channel nyo at mukha dito na ako lagi tatambay! Btw, new subscriber here!! Godbless you po Maam!
A great and subtle way to work the algebra in favor of a result consistent with Laplace tables. One thing I did not catch was why at aprox 45:54 you derive the denominator. Thank you!
thank you maam napaka linaw po ng turo nyo tanong lang po maam sa prob3 what if yong senet po na value ng s is s=1 :A((1)-1)=9-9 -->. 0=0 po ba maam? salamat po
Given: Y(s) = X(s)*(1-s^2)/(1+a*s)+X(s) Factor out X(s) on the RHS: Y(s) = X(s)*[(1-s^2)/(1+a*s) + 1] Divide both sides by X(s): Y(s)/X(s) = (1 - s^2)/(1 + a*s) + 1 We could stop here, as we've technically met your goal of isolating Y(s)/X(s). But, usually, it is desired to convert it to a single fraction. Simply form an equivalent fraction to replace 1, so we change to common denominators: Y(s)/X(s) = (1 - s^2)/(1 + a*s) + (1 + a*s)/(1 + a*s) Y(s)/X(s) = (1 - s^2 + 1 + a*s)/(1 + a*s) Simplify, and we have our result: Y(s)/X(s) = (-s^2 + a*s + 2)/(1 + a*s)
I know that I'm a month late, but might as well reply for someone else who needs it. On the left hand side, she took out "S" as common out of "AS+BS", resulting in (A+B) being the coefficient of "S". Then she compared said "A+B" with the S-coefficient on the left side of the equation ('1' in this case), resulting in A + B =1. Then she did the same thing for the constants and got 2A+B=4. Then simply subtracted both of the equations to get the value of A. Finally, she used the newly-obtained value of 'A' in one of those equations to obtain the value of B. Hope this helped.
What a tutor! Bar the minimal language barrier, what a lesson this was👏🏾
I love how you write out all the steps so that we can understand it clearly. Thank you!
Thank you for the playlist on Laplace Transform. I got a lot out of it.
Hello ma'am
I am from India
Your explanations on Laplace transform are so easy and simple
Thank you
You are amazing!
I just saw your videos. I have been having problem on Laplace Transform, especially the Inverse Laplace...but the way you solve it is very simple and well understood. Thanks...Jude from Nigeria
after all the videos I've watched, This one was the best
Thank you ma'am nadine, sobrang helpful turo nyo, sobrang makakatulong sa control engineering :>
I would like to thank you from my heart. You have become my hero ❤❤❤Best explanation ❤
Thanks alot dr....this will go along way in my studies......very simple and concise, easy to comprehend...i really appreciate
Watching this the night before my final exam in Differential Equations. Thank you po!
This is a great one and it is a super beneficial
Thanks Dr.
You are great 👍 👌
Following you from Iraq
Thank you for this ma'am. The explanations are all clear and madaling intindihin. Napakalaking tulong po ito para sa quiz namin😊
Slamat po ma'am xa video ninyo laking tulong po ito xa akin lalao magpaplano ng board exam. Maraming Salamat po
What a wonderful tutorial ,be blessed ma'am🙏🙏
this is super helpful thank you!
Galing, you make complicated lessons easy to understand maam, kudos. 👏
Grabi maam super gets ko po itong tinuro nyo sa video. I hope na magpatuloy pa po yung paggawa nyo ng mga video. New subscriber po.
Grabe naman po to maam! Napakalinaw po ng pagkakaturo nyo. May methods den po kayo na inintroduced na ngayon ko lang nalaman! Maraming salamat po maam. Sobrang malaking tulong po ito at may quiz kami mamaya abt Inverse Laplace! Rerecommend ko po tong channel nyo at mukha dito na ako lagi tatambay! Btw, new subscriber here!! Godbless you po Maam!
Thank you so much. I have understood laplace very well. Thank you again
A great and subtle way to work the algebra in favor of a result consistent with Laplace tables. One thing I did not catch was why at aprox 45:54 you derive the denominator. Thank you!
A fine video. Helped me pass my semester exams.
Sana po makagawa pa kayo ng mga videos with more examples. Salamat po ma'am ❤
♥️🤗thanks po. So clear. 😃
So beautifully explained.......thank you ma'am...
Good video! Please make laplace transforms of integral. I really need it. Thank you dr!!
Good video, I love you
Love u ❤ mam u are the best
thank you!
Thanks for this ☺️
Thank you so much
How did you enter numbers on the calculator for problem 3 I have a it-84plus
You did well
VERY NICE
may you help me with how to insert the values on the calculator to find the constants a,b,c
Go to complex mode and chose option 2 which is degree
tks very much
thank you po ma'am. 🥰
i like it
thank you maam napaka linaw po ng turo nyo
tanong lang po maam sa prob3
what if yong senet po na value ng s is s=1
:A((1)-1)=9-9 -->. 0=0 po ba maam?
salamat po
Love you ma'am
thank you maam
Thanks
ahahajhaha di ko narealize 1 hr vid pala to. Ito lang ata math vid na pinanood ko nang walang putol, thank you ma'am!
Thak U
Transfer function control system next vid :)
Ya good
can anyone help with this, laplace equation -> Y(s) = X(s)(1-s^2)/1+as+X(s). I want to get Y(s)/X(s) independent of X(s) on RHS
Given:
Y(s) = X(s)*(1-s^2)/(1+a*s)+X(s)
Factor out X(s) on the RHS:
Y(s) = X(s)*[(1-s^2)/(1+a*s) + 1]
Divide both sides by X(s):
Y(s)/X(s) = (1 - s^2)/(1 + a*s) + 1
We could stop here, as we've technically met your goal of isolating Y(s)/X(s). But, usually, it is desired to convert it to a single fraction. Simply form an equivalent fraction to replace 1, so we change to common denominators:
Y(s)/X(s) = (1 - s^2)/(1 + a*s) + (1 + a*s)/(1 + a*s)
Y(s)/X(s) = (1 - s^2 + 1 + a*s)/(1 + a*s)
Simplify, and we have our result:
Y(s)/X(s) = (-s^2 + a*s + 2)/(1 + a*s)
Nice video:) But I did`t understood how you found A & B from the S + 4 = AS+2A+BS+B. Anyone who can explain whats happening there? Thanks.
I know that I'm a month late, but might as well reply for someone else who needs it.
On the left hand side, she took out "S" as common out of "AS+BS", resulting in (A+B) being the coefficient of "S". Then she compared said "A+B" with the S-coefficient on the left side of the equation ('1' in this case), resulting in A + B =1.
Then she did the same thing for the constants and got 2A+B=4. Then simply subtracted both of the equations to get the value of A. Finally, she used the newly-obtained value of 'A' in one of those equations to obtain the value of B.
Hope this helped.
MA’AM PANO PO NAGING 1/s^2 nalang yung sa 38:11 po?
It is better to use complex partial fractions for calculating inverse Laplace transform
if we use real partial fraction decomposition we need convolution
Hi Nadine are you from Batangas City
Yes po. 😊
Who is watching from India dehradun
PINAY KA MA'AM?
Yes po. 😊
Omg why don't you use full english. I don't understand what you are talking abt
stop mixing languages in your videos NOTE your videos are international we cant understand the parts your explaining in your language
wtf r u talking about idiot?
r u payin something for this content?
you cannot say that.
But for us Filipinos it's kinda better, because we can understand her more clearly.
super helpful video🦹🏻♂️㈼