Solution Stoichiometry tutorial: How to use Molarity + problems explained | Crash Chemistry Academy
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- Опубліковано 11 лип 2024
- A tutorial on aqueous solutions and molarity, and then a detailed explanation of how to set up calculations for five example problems of solution stoichiometry involving molarity -- how to use molarity in stoichiometric conversions. Also includes problems using density and mass conversions!
CC Academy videos are crash course tutorials for step by step Chemistry help on your chemistry homework, problems, and experiments.
-More on Stoichiometry | Wikipedia-
"Stoichiometry...is the calculation of relative quantities of reactants and products in chemical reactions.
Stoichiometry is founded on the law of conservation of mass where the total mass of the reactants equals the total mass of the products leading to the insight that the relations among quantities of reactants and products typically form a ratio of positive integers. This means that if the amounts of the separate reactants are known, then the amount of the product can be calculated. Conversely, if one reactant has a known quantity and the quantity of product can be empirically determined, then the amount of the other reactants can also be calculated....
Here, one molecule of methane reacts with two molecules of oxygen gas to yield one molecule of carbon dioxide and two molecules of water. Stoichiometry measures these quantitative relationships, and is used to determine the amount of products/reactants that are produced/needed in a given reaction. Describing the quantitative relationships among substances as they participate in chemical reactions is known as reaction stoichiometry. In the example above, reaction stoichiometry measures the relationship between the methane and oxygen as they react to form carbon dioxide and water.
Because of the well known relationship of moles to atomic weights, the ratios that are arrived at by stoichiometry can be used to determine quantities by weight in a reaction described by a balanced equation. This is called composition stoichiometry.
Gas stoichiometry deals with reactions involving gases, where the gases are at a known temperature, pressure, and volume and can be assumed to be ideal gases. For gases, the volume ratio is ideally the same by the ideal gas law, but the mass ratio of a single reaction has to be calculated from the molecular masses of the reactants and products. In practice, due to the existence of isotopes, molar masses are used instead when calculating the mass ratio."
Wikipedia contributors. "Stoichiometry." Wikipedia, The Free Encyclopedia. Wikipedia, The Free Encyclopedia, 27 May. 2016. Web. 27 May. 2016.
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William Milligan one year later when the online classes don’t teach it right
5 years later for the same reason 🤣
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7Years now
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You made that so easy to understand! I think I learn more on UA-cam than I do in class. Thank you!
This is the best solution stoic video! Thank you
This was very helpful. I have a test tomorrow and this has made me feel much more confident. Now if only you can teach me EVERYTHING about thermodynamics, at least when it comes to chemistry **pulling my hair out** haha
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This is an excellent extension of stoichiometry. You saved my stoich test.
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Thanks! I'm a high school chemistry teacher in Evanston IL.
Thank you, I have been struggling to understand the concept of stoich and somehow made it this far, in this video, you made it clear so thanks : )
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Beautiful. Love the example problems.
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The problem was that my instructor havent done a great job explaining that we can use M as a relationship with L as a conversion factor! so thank you for making it clear!!
thank you, This is the best tutorial on stoi but i need help n
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i just failed a quiz on this and decided i needed some help from someone other than my teacher, found this and i think i get it! thank you! let's hope i remember how to do it on my final!
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AWESOME TEACHER 🏆🏆 You make the difficult concept so easy. Please could you make a video on finding the ph without using the calculator. The exam I am preparing for does not allow calculators. 🙏🙏
in this i cant understand the first problem why we should divide na2co3 M
bless you
Hi, Wonderful explanation. Can you tell me how do you decide which chemical from the equation will become A and which one will become B while using the formula bridge. Is it that given is A and wanted is B?
Yes, A is given and B is wanted. Thanks for your comment!
that is great video ! i gotta introduce to my friends. Yet, I have a Q. At 4:40, i thought that 0.3 M AlCl3 has a 5 L of solution so what i am thinking is 0.3 mol AICI3 / 5.0 L AICI (aq).
Can you explain why it is 0.3 M AlCl3 per 1 L AlCl3 ?
ok so it's kind of late but, molarity (M) = moles / L (volume), so basically .30 moles AlCL3 / 1L (volume) = .30 M because M is moles over liter. IDK if this helps but if there is confusion feel free to ask. So to get to moles from M and L just multiply both. and get moles and do mole to mole ratio
For problem 1. Can we use c1v1=c2v2. If I use the dilution formulae I get a different answer since I am not using the mole ratio.
The c1v1=c2v1 formula does not work because you are changing the compound, which means changing the amount of particles in a way that is different than a simple dilution. This is why the mole ratio is used. On the other hand it might work only if the coefficients (the mole ratio) are the same, giving a 1:1 ratio. Better to stick with the mole ratio.
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Why did you remove the other videos on stoichiometry?
I'm not aware of removing any. The stoichiometry video is still up at ua-cam.com/video/XnfATaoubzA/v-deo.html, limiting reactants is at ua-cam.com/video/c11YBShZnmA/v-deo.html, and percent yield is at ua-cam.com/video/L7NEeVY4-P0/v-deo.html. I also have mole conversions at ua-cam.com/video/t1pjGbwqt9o/v-deo.html. Was there something else you are looking for?
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This has no sig figs?
for example 2, shouldn't the number of sig figs be 2?
Yes you are right, the answer should be 4.3 L due to the two sig figs of the 0.45 M FeCl2.
9:45. Where did "241.9 g Fe(NO3)3 over 1 mol" came from?
molar mass
❤
chem final is in 8 hours, and my teacher has barely prepared me so here I am. Ill update with my exam score
update: I failed the exam: I got a 18/50 :I
How it went?
@@juandiegoquirosgomez9405 pretty sure I failed :( but I haven't gotten my score back yet so i'll comment when I get it
Pls make it easier
isn't Al 26.98 g/mol, which would give us 4.34 L FeCl2 (rounded to 3 sig figs)
Yes. Since the volume of FeCl2 has only 3 sig figs, I rounded the Al mass to 3 sig figs. It does not matter, either way is correct.
@@CrashChemistryAcademy okay, thank you.
6:50
I am pretty sure that your molar mass of Fe(NO3)3 is incorrect. Fe= 55.85 + N =14.01*3+ O = 16*6 = 198.88g Fe(NO3)3
There are 9 oxygens, not 6. Those details can be annoying! So my molar mass is correct. Thanks for checking.
like like like
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I love AP chem. Think about it. Chemistry is the basis for our entire lives.
@@aesarahypatia3482 yeah but it sucks tho