Limiting Reactants Tutorial: How to find Limiting Reactants/Limiting Reagents using Stoichiometry

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  • Опубліковано 30 січ 2016
  • Limiting Reactant: Meaning and Calculations: how to calculate limiting, excess, leftover excess, and amount of product. Contents:
    1. 0:00 meaning of limiting reactants; 2. 2:01 limiting reactant demonstration; 3. 3:43 limiting reactants molecular simulation; 4. 5:26 limiting reactant calculations explained using a recipe; 5. 10:03 mole-mole limiting reactant calculations explained; 6. 13:50 stoichiometry in limiting reactant calculations explained
    -More on Limiting Reactants | Wikipedia-
    "The limiting reagent (or limiting reactant) in a chemical reaction is the substance that is totally consumed when the chemical reaction is complete. The amount of product formed is limited by this reagent, since the reaction cannot continue without it. If one or more other reagents are present in excess of the quantities required to react with the limiting reagent, they are described as excess reagents or excess reactants.
    The limiting reagent must be identified in order to calculate the percentage yield of a reaction, since the theoretical yield is defined as the amount of product obtained when the limiting reagent reacts completely. Given the balanced chemical equation, which describes the reaction, there are several equivalent ways to identify the limiting reagent and evaluate the excess quantities of other reagents."
    Wikipedia contributors. "Limiting reagent." Wikipedia, The Free Encyclopedia. Wikipedia, The Free Encyclopedia, 29 May. 2016. Web. 3 Jul. 2016: The limiting reagent (or limiting reactant) in a chemical reaction is the substance that is totally consumed when the chemical reaction is complete. The amount of product formed is limited by this reagent, since the reaction cannot continue without it. If one or more other reagents are present in excess of the quantities required to react with the limiting reagent, they are described as excess reagents or excess reactants.
    The limiting reagent must be identified in order to calculate the percentage yield of a reaction, since the theoretical yield is defined as the amount of product obtained when the limiting reagent reacts completely. Given the balanced chemical equation, which describes the reaction, there are several equivalent ways to identify the limiting reagent and evaluate the excess quantities of other reagents.

КОМЕНТАРІ • 19

  • @sk8terbluetoo
    @sk8terbluetoo 7 років тому +4

    GREAT! last 8-10 minutes GREAT examples of HOW-TO problems in limiting, especially using stoichiometry, first half is great if this is your first exposure to limiting. Thanks-- SUBSCRIBED!! Great chanel, thanks for your time!

  • @carolinacollins1181
    @carolinacollins1181 7 років тому +4

    Once again, Professor, THANK YOU SO MUCH FOR THIS ONE-- you really are an angel to help students like me :-)

  • @mariennemercado366
    @mariennemercado366 8 років тому +3

    THANK YOU SO MUCH FOR THIS VIDEO. I'm so happy I can now solve stoich problems! :)

  • @waterandtrees471
    @waterandtrees471 6 років тому +2

    Thank you bro.. it really helped a lot.. I can understand ur teachings easily.... u have great teaching skills ..

  • @kitpat3801
    @kitpat3801 2 роки тому

    I rarely comment on any videos but this video REALLY helped me. I've watched tons of chem vids about stoichiometry but when our unit exam came, I cried in the middle of solving cus the questions were unfamiliar and was not discussed in other videos. It was broken down and discussed here and now I understand stoichiometry. A million thanks!

  • @aesarahypatia3482
    @aesarahypatia3482 3 роки тому

    amazingly thorough and perfectly explained. Thank you very much!!

  • @bubbahotep6316
    @bubbahotep6316 7 років тому

    Love this video! Thanks so much!! Very thorough, and I now thoroughly understand limiting. I am going to get an A on the test, thanks to this and your stoich vid. THANKS!!

  • @dmaulick2873
    @dmaulick2873 6 років тому +2

    Great teacher u r

  • @xXRock11StarXx
    @xXRock11StarXx 7 років тому

    Super great job at explaining

  • @SuzyLia
    @SuzyLia 7 років тому

    THANK YOU YOU'RE AWESOME OMGGG FOR REALS

  • @thoughty4257
    @thoughty4257 7 років тому

    thank you,dear sir :) subscribed

  • @joeljames4875
    @joeljames4875 3 роки тому

    Thank you sir

  • @conradburghardt2916
    @conradburghardt2916 8 років тому +1

    Salami sandwiches for the win

  • @prajitvishnukarthik8886
    @prajitvishnukarthik8886 7 років тому

    without converting from mass to mole is there any direct method to find without conversion

  • @batmunkhn6666
    @batmunkhn6666 7 років тому

    Suppose 316.0 g aluminum sulfide reacts with 493.0 g of water in a double replacement reaction. What mass of hydrogen sulfide is produced? Assume reaction is 71.2% efficient. HELP ME

    • @CrashChemistryAcademy
      @CrashChemistryAcademy  7 років тому

      The reaction produces aqueous aluminum hydroxide and hydrogen sulfide gas, so from there you should be able to get the coefficients and solve for amount of product expected.

  • @returnofthemomos
    @returnofthemomos 7 років тому

    First!