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at 6:45 how did u even find the gradients???
Pick a value either side of the turning point. Then substitute those values into dy/dx. That gives you the gradients.
@@MathsDeity you mean for example at 6:22, if x = -0.7 then we will substitute it in the equation 3x^2 - 4x - 4 = 0, doing but not getting same gradient value?
@@Science.719 its basically the second derivative here
at 6:45 how did u even find the gradients???
Pick a value either side of the turning point. Then substitute those values into dy/dx. That gives you the gradients.
@@MathsDeity you mean for example at 6:22, if x = -0.7 then we will substitute it in the equation 3x^2 - 4x - 4 = 0, doing but not getting same gradient value?
@@Science.719 its basically the second derivative here