Japanese|A math Olympiad algebra problem| can you solve this?

This is a math Olympiad algebra question involving substitution #matholympiad #algebraicequations #matholympiadproblem

[@Voice_of_Nature37]

Nice to watch 👏👏👏

[@JJONLINEMATHSCLASSchannel]

Thank you! 😃

[@RyanLewis-Johnson-wq6xs]

Input
14/15 = 0.1 (9 + 0.3/0.9)
Result
True
Logarithmic form
log(15, 14) - log(15, 15) = log(15, 0.1) + log(15, 9 + 0.3/0.9)

[@RyanLewis-Johnson-wq6xs]

(a b)/(a + b) + (b c)/(b + c) + (c a)/(c + a) = 6 {a = 2 - 2 i, b = -2 + 4 i, c = -2/15 + (14 i)/15}{a = 2 + 2 i, b = -2 - 4 i, c = -2/15 - (14 i)/15}

[@tosinolawole5878]

Waoh.... You are well done...

[@JJONLINEMATHSCLASSchannel]

Thanks

[@RyanLewis-Johnson-wq6xs]

c=-12 b=1.714285 recurring a=2.4

[@husseinobeid8121]

better to take c from second and third after c=c so we get relation a and b , so we put in first will get a after b . after c

[@JJONLINEMATHSCLASSchannel]

Thanks for the suggestion

[@RyanLewis-Johnson-wq6xs]

Input
-2/15 = -0.1 (1 + 0.3/0.9)
Result
True

[@user-yo2xs8mw2e]

أحببت هذا بشغف في الشباب و ما يزال دماغي يعمل. شكرا علي هذا الطرح.

[@JJONLINEMATHSCLASSchannel]

U are welcome