Really amazing sir... seriously i haven't find such material any where neither in books nor on Internet. I am glad i watched this. Thankyou so much sir. I will share it as much as i can.
19:34 no.of Skeletal electron pairs that come out using formula correspond to the geometry written. On solving [Rh6 (CO)16] SEP= 7 means pentagonal bipyramidal. ?? But it is Octahedron.
As per your taught if normal boranes then we should apply formula as T.v.e- 2n divided by 2 then we get SE pairs which tells geometry but in case of B5H9 it not follow it is square planer why? Kindly regards me! But we get 7 SE pairs it corresponds to pentagonal bipyrmidal but answer is square pyramidal why ? kindly sir! Regards as soon as
Sir how to find SEP for [Rh6C(CO)15]2- complex..it contains both transition metal as well as non transition..what would be the geometry and cluster structure? Plz reply sir!
I have doubt in geometry, for SE Pairs , number of vertices is less than one eg SEP= 4, number of vertices are 3 and geometry is triangular Please explain
Sir....i was going through zintl ionS....there was 2 category...lower series ..that u taught in the video...there was higher series also....i.e 4n+0=monocapped, 4n-2 bicapped....it goes. Till 4n-10=hexacapped... Ex...Bi3Cr2(CO)6-3 Pls rply...it is important...or study only lower series
shyam sharan Tripathi, I think the question wi not contain 2-, it could be 3- or 1- bcoz with 2- we will get odd electrons and wade rule will not apply there. If you're trying to ask question from CSIR June 2017,then it was Bi³+ there
if you see tunabe sugano diagram for LS d6 configuration there it is clearly written that there willbe two spin allowed transitions. check james E huhyee for this. one more request, i think you have'nt subscribed the channel bcoz your replies are kept in "held for review" section, if so then i request you to subscribe it so that i can get notified when you comment.
[Rh6C(CO)15]2- structure is trigonal prism.. Not what you mentioned tricapped trigonal prism.. And you said that CSIR is mistakenly did this.. No.. It's actual answer is given.. Geometry calculation from SEP-1 is not right.. It don't obey for all the cases.. We have to figure it out from TVE count
![[Simplest TRICK] to find Geometrical and Optical Isomers of Inorganic Complexes](/img/n.gif)
Superb explanation. You made me to solve many questions. Thanks a lot
sir, easy to understand and revising is made easy by your videos.
Really amazing sir... seriously i haven't find such material any where neither in books nor on Internet. I am glad i watched this. Thankyou so much sir. I will share it as much as i can.
Osm sir
...I only watch ur videos to clear my doubts....keep uploading more videos.... thanks sir
Amazing video sir..keep making videos for NET and GATE.
In question 1) C2=(BH)2; B3H5+(BH)2=B5H7 means 5+7=12 Same do in other examples it will come right. U r teaching very good I like it.
Thanku so much sir for making this video 🥳🥳very clr👍
Thank you very much for making it this simple.
Keep up the good work sir ☺
isha9560, thanks for the appreciation 😊😊
Superrr sirrr. Thank u soo much sirr. We want more physical chemistry important topics in too easy methods
videos are already there, please check them :)
19:34 no.of Skeletal electron pairs that come out using formula correspond to the geometry written. On solving [Rh6 (CO)16] SEP= 7 means pentagonal bipyramidal. ?? But it is Octahedron.
What does eta denotes please calrifies please i got stuck in it
So nice sir you solved all my problems thanks alottt sir
You're welcome. 😊
Please subscribe the channel and share with your friends too... 😊😊
Please give the link of the paper related to [Re(H)9]2-
Good explanation
Really fabulous getting short of adjectives.
thank you
Thank you so much sir. ur explanation very useful me
I m really thankful to you sir
kashmina akhtar, you're welcome 😇
Plz subscribe the channel and share with your friends
kashmina akhtar .
Amazing video sir..pls keep making videos four NET and GATE..
Thanku so much sir.. Keep helping us
Simarneet Kaur, you're welcome. Keep following the videos
Very nice sir, thanks
As per your taught if normal boranes then we should apply formula as T.v.e- 2n divided by 2 then we get SE pairs which tells geometry but in case of B5H9 it not follow it is square planer why? Kindly regards me! But we get 7 SE pairs it corresponds to pentagonal bipyrmidal but answer is square pyramidal why ? kindly sir! Regards as soon as
Thanks for this video
Wat an explanation sir ji
really Very good work
thank you :)
Sir how to find SEP for [Rh6C(CO)15]2- complex..it contains both transition metal as well as non transition..what would be the geometry and cluster structure? Plz reply sir!
thnku so much sir for this ....👌👌👌
Is this videos enough to cover topics in organometallic expect rxn mechanicm of organometallics??
I have doubt in geometry, for SE Pairs , number of vertices is less than one
eg SEP= 4, number of vertices are 3 and geometry is triangular
Please explain
Fabulous great work !
thank you
Really too gd.... Thnks a lot....
Sir please make video on electroneutrality principal
Thank you so much sir..
Very very Thanku so much sir.
My request to you is
Please make videos on most important formulas of physical chemistry for csir net, gate exams.
Alright 👍
Thank you so much sir.if you see this comment please upload some questions for practice at least 2or3 questions.once again thank you
For [Rh C (CO)6]2-, you have not subtracted 2 for the C atom in the last step.. if we do that then the skeletal electron pair comes as 8..
Mam,can you explain why 2 have to substracted
Negative charge means ..addition...
great explain really good
Thank you 😊
Plz subscribe and share with your friends
Definitely
Iam government Teacher. I like ur videos. Pl dont stop ur videos i will prepare For csir exam
Sn92- i got Nido ..but skeletal electrons i got 11 pairs ...means- Oct docodecahedran???
Pls rply sir
At 29:27 in Mn ques there is B3H6.....so total is B4H8 not B4H10
that is B3H8 only, maybe bcoz of my handwriting it is appearing as B3H6,
where is the links that you mentioned in right corner?
very good video sir thanks
Waoo..superb..Sir
plz tell Re is one not participate, what about remaining
Good work
Sir
Geometry is based on no.of skeletal electron pair or no.of vertices..pls help
nice as usual dear bro
umendra khokhar,
Thank you so much brother 😊
Can u plz solve ds C2 B2 H12- its structure closo. Nido. Arachno or hypho... Ds question came in dec 2014 csir
Thank you very much sir
you're welcome :)
Excellent..
Sir how to know that rhenium is exceptional case in ReH9 type question
some exception you should know, it will come by reading books
OK sir and which book
Sir I mean for 7 it is also square pyramidal geometry adopt
Sir....i was going through zintl ionS....there was 2 category...lower series ..that u taught in the video...there was higher series also....i.e 4n+0=monocapped, 4n-2 bicapped....it goes. Till 4n-10=hexacapped...
Ex...Bi3Cr2(CO)6-3
Pls rply...it is important...or study only lower series
sir can you please tell us how to calculate number of multiple metal-metal bond in Fe3O4 and Cr2(CH3COO)4
how to calculate number of bridging carbonyls in Cp2Fe2(CO)4
physical chemistry part is very useful for CSIR I request more lectures
Alright.. I'll try to make more
17.17 sec ka 22= 4×5+2 closo kyo ny hua sir
4×4+2 =22. Archna hi kyo hoga
n= number of phosphorus here, since we have 5 that's why 4×5+2=22
@@AllBoutChemistry thank u sir I understand..
Sir where is the link of [Reh9]2- of ACS publication
pubs.acs.org/doi/abs/10.1021/jp412003s
Super sir
Thank you sir....
Plse make more video on organometallics imp topics
I'll try to make... Till then You can also watch other videos on Organometallics uploaded by me...
Thanku sir
what is the geometry of Me2C2B10H10
This question is from GATE exam and I think I've already solved it, you can check in my GATE 2017 Playlist.
@@AllBoutChemistry answer bta dete to kya ho jata sir jiii ye acche teacher ki Nisani nhii h
In isolobal ability from metal clusters how 14 electrons isolobal with 4 didn't got
Please apply Wade rule on (Bi3)2- and give it's structure
shyam sharan Tripathi, I think the question wi not contain 2-, it could be 3- or 1- bcoz with 2- we will get odd electrons and wade rule will not apply there. If you're trying to ask question from CSIR June 2017,then it was Bi³+ there
Thanks sir😊
Can u please solve qus no 74 of Dec 2017 set B
i think the answer should be option 2 (one and two)
But sir for LS d6 spin will be zero.how there will be e transfer..This will b spin forbidden
if you see tunabe sugano diagram for LS d6 configuration there it is clearly written that there willbe two spin allowed transitions. check james E huhyee for this.
one more request, i think you have'nt subscribed the channel bcoz your replies are kept in "held for review" section, if so then i request you to subscribe it so that i can get notified when you comment.
Sjort trick v batao
Sir can u solve cluster type for (B10H13(Au(Pph3)))
Thank you🙂
Sb4-2 is example for closo
[ReH8]2- in second question
But u described very well
Thanks nice video
😊
Thank u sir
You're welcome 😇
Tq so much
Thank u
Physical chemistry csir important topics in easy methods sirr
I've already uploaded, plz watch my other videos
Plz make a video on reductive elimination reaction sir.
yes sure...
And plz solve 88 question of december 2016
Please sir video banate rahna
[Rh6C(CO)15]2- structure is trigonal prism.. Not what you mentioned tricapped trigonal prism.. And you said that CSIR is mistakenly did this.. No.. It's actual answer is given.. Geometry calculation from SEP-1 is not right.. It don't obey for all the cases.. We have to figure it out from TVE count
okk sir
Is this portion for pgt trb also sir
If it is there in your syllabus, then YES
U can solve all these questions on plane paper, please actually too massive here
Sorry sir square pyramidal
There is one wrong answer make it correctly 😂
Write clearly and bigger size,
Amazing video sir..pls keep making videos four NET and GATE..
Thank you so much sir
Thank you sir
Thank you so much sir
Thank you sir
You're welcome 😇
Thank you Sir
Thank you sir