Thanks for watching. The center of mass calculation is correct. It is L/3 from the bottom. The stick is of mass 2M, considered to be at y= L/2. The ball is of mass M considered to be ar y=0. Since the stick is twice as massive as the ball, the center of mass would be 2 times closer to the center of the stick than to the ball at the bottom. Thus, it is L/6 below center, or 2L/6, otherwise known as L/3, from the bottom.
@@dr.piercesphysicsmath9071 Thank you. I was doing a similar problem and it wasn’t working but I forgot to do mass x dist when considering CoM balancing (I only did a mass sum on both sides). I’ve re-worked it now and it does work.
so helpful thank you so much!
Awesome! Glad to hear it.
Your CoM calculation doesn’t work as it puts 1.6666 M below your centre and only 1.33333 M above it.
Thanks for watching. The center of mass calculation is correct. It is L/3 from the bottom. The stick is of mass 2M, considered to be at y= L/2. The ball is of mass M considered to be ar y=0. Since the stick is twice as massive as the ball, the center of mass would be 2 times closer to the center of the stick than to the ball at the bottom. Thus, it is L/6 below center, or 2L/6, otherwise known as L/3, from the bottom.
@@dr.piercesphysicsmath9071 Thank you. I was doing a similar problem and it wasn’t working but I forgot to do mass x dist when considering CoM balancing (I only did a mass sum on both sides). I’ve re-worked it now and it does work.