excuse me,may i ask something.for question b..why we must find the pka?why we not just use pkb?because in that question we use weak base solution ,right?thank you
well technically a neutralization reaction is "A neutralization reaction is when an acid and a base react to form water and a salt and involves the combination of H+ ions and OH- ions to generate water.", meaning it can occur between weak base and acid, as you see there all of the H+ is going to neutralize the NH3, think of it as an attacker and a defender, the H+ is attacking the base so the base in return goes after the H+ and it neutralizes it to stop the attack, and it ends up consuming itself. tl;dr it can occur between weak base and acid, also damnnnn post it on the forum, (what a small world) [Or small video selection] {or common problem}
Yea but NH4Cl is, you see they didnt include the Cl- because its netural, but if they were to write the whole thing, it would be NH4Cl, and that is a salt
can I use the same equations used for 20 mL of HCL for adding any amount of HCL (other than 0mL) before the equivalence point ? like when adding 1mL, 2 mL, 3 mL.....39mL HCL.
One small suggestion (unless I am wrong). During solving this question, I realized it was an half equivalence point since half of the moles of the solution was titrated. Then, pH = pKa. However, I started to struggle to figure out how to go from here, since nothing else was given. I assumed I may be doing something wrong, and started to just go in circles and plugged in numbers. What it have been bad if the question gave us the ka value like many questions do? I thought we had to somehow find out the Ka despite not having given it somehow...I got everything correct up to toward the end except having to use the HH equation. I know I am still learning acid bases and it is tough, but this whole set up made me feel like I was suppose to get a problem that simply did not provide enough information. Other than that, your videos really helped me learn this. Of all sciences, this topic is one of few I never was able to conquer, until these videos! :)
Good explination
excuse me,may i ask something.for question b..why we must find the pka?why we not just use pkb?because in that question we use weak base solution ,right?thank you
at 13:30, how is A- NH3, shouldn’t A- be the conjugate base which is NH4+
can you explain more why you changed HCl into H3O in the reaction?
HCl is a strong acid and dissociates almost completely into H30+ in the pressence of water.
H3O+ can be said to be H+ as well but H3O+ shows the reaction with water to balance out the equation :)
How is ammonia reacting with hydronium a neutralization reaction? 8:25
Laila S. yeah, arent neutralization reactions between a strong acid and strong base?
well technically a neutralization reaction is "A neutralization reaction is when an acid and a base react to form water and a salt and involves the combination of H+ ions and OH- ions to generate water.", meaning it can occur between weak base and acid, as you see there all of the H+ is going to neutralize the NH3, think of it as an attacker and a defender, the H+ is attacking the base so the base in return goes after the H+ and it neutralizes it to stop the attack, and it ends up consuming itself.
tl;dr it can occur between weak base and acid, also damnnnn post it on the forum, (what a small world) [Or small video selection] {or common problem}
Hussein Shareef but NH4+ isn't a salt
Yea but NH4Cl is, you see they didnt include the Cl- because its netural, but if they were to write the whole thing, it would be NH4Cl, and that is a salt
is this the voice of ratatouille?
+Sarafina Henderson i like to think it is
anyone can be a mathematician
Lifehack: put it at the speed 1.5 and Khan Academy will speak like normal human 😄
😁😁
God's work. Thank you very much
can I use the same equations used for 20 mL of HCL for adding any amount of HCL (other than 0mL) before the equivalence point ? like when adding 1mL, 2 mL, 3 mL.....39mL HCL.
bless
One small suggestion (unless I am wrong). During solving this question, I realized it was an half equivalence point since half of the moles of the solution was titrated. Then, pH = pKa. However, I started to struggle to figure out how to go from here, since nothing else was given. I assumed I may be doing something wrong, and started to just go in circles and plugged in numbers. What it have been bad if the question gave us the ka value like many questions do? I thought we had to somehow find out the Ka despite not having given it somehow...I got everything correct up to toward the end except having to use the HH equation. I know I am still learning acid bases and it is tough, but this whole set up made me feel like I was suppose to get a problem that simply did not provide enough information. Other than that, your videos really helped me learn this. Of all sciences, this topic is one of few I never was able to conquer, until these videos! :)
I really really hate how they just drop the x from the reactants in the ICE equation...
Dr Gonzo its so that u wont have to use quadratic formula and it wont change the answer but much because the number is usually insignificant
*by much
our teacher phrased it like "raise your hand if you want to do a quadratic, anybody?"
bad explination
heyyy dude,,, u do something but with so slow voice...make ur voice high..loudlyyyyy
i can not tolerate
Speed it up.
:/ get the fuck out here
@@isihummetli4671 what a loser you are lol
@@roflwaffles902 no u