Hybridization of Atomic Orbitals - Sigma & Pi Bonds - Sp Sp2 Sp3
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- Опубліковано 21 лис 2024
- This organic chemistry video tutorial explains the hybridization of atomic orbitals. It discusses how to determine the number of sigma and pi bonds in a molecule as well as determining if a carbon is sp, sp2, or sp3 hybridized. The full version of this video contains plenty of examples and practice problems.
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The electronic configuration of carbon is 1s2 2s2 2p2. Coz carbon had 6 electrons.
So one electron from 2s2 will go to the vacant p orbital and form the hybrid orbital which is sp3.
So 1 2s orbital and 3 2p orbital will participate !
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Thank you! what confused me was 2s drawn as having two electrons during the part where the hybridization of carbon was being discussed. I thought I had maybe missed something while watching the video.
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bruh 2 weeks to go over hybridization lucky i got an hour and a half lecture
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@@gagemal5 then I’m screwed cause idk what is happening with hybridization. I get the concept but I don’t know how to actually like calculate it lol
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Professor Organic Chemistry Tutor, thank you for another fantastic explanation of Hybridization of Atomic Orbitals in AP/General Chemistry. The examples/practice problems continue to increase my understanding of sigma and Pi bonds.in a given molecule as well as determining if a carbon is sp, sp2 or sp3 hybridized. Thanks to the viewers for finding and correcting the error(s) in this video.
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When he did the electron configuration of Carbon, shouldn't there only be 2 electrons on the p level? Even if the carbon was to absorb another electron, promoting one of the electron from 2s into 2 p, that would only leave 1 electron on 2s and 3 on 2p
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Yes ! And that’s why the 3 p orbitals and 1 s orbital overlap and form hybrids. Because none of them is full
According to Humd’s rule
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