Bom dia professor Reginaldo Moraes 👏👍 Infelizmente eu nunca estudei Lim muito menos derivada Porém vejo sua explicação que é muito excelente dá gosto ser sua aluna Eu aprendi muita coisa boa de matemática com suas aulas 😃👍🙏🙇🙌 Gratidão que Deus te abençoe grandemente 🙌 like sempre
Nice problem. I was able to eliminate 9, 27, and 81 as solutions quickly. In my head I was able to factor the 2 from the numerator. I could see that the rest was a difference of cubes and without factoring it completely I could see it would cancel with the factor in the denominator. The expression would be 2 times a polynomial expression and evaluated at 3 must be an even number. Thanks again!
nossa deveria fazer uma aula de 1 hora resolvendo exercicios , fatorando , simplificando, ia ser otimo. É so com a pratica que o cara pega essa manhâs de fazer essas simplificações
There is an indeterminate form 0/0. We have two ways to solve this : The first way : 2x^3-54=2(x-3)(x^2+3x+9) The fraction becomes 2(x^2+3x+9) whose limit when x goes to 3 is 54. The second way is to use the Hospital's rule : The derivative of 2x^3-54 is 6x^2 The derivative of x-3 is 1 So, it is the limit when x goes to 3 for 6x^2 which is 54 as well.
You can resolve this equation for five seconds by looking on answers. In numerator you move out 2. All other number are naturally. Thats means that result you can devide for 2. In test only one number 54
В общем сразу бросается в глаза что 2 выноситься за скобки а знаменатель сократится. Все дальнейшие числа будут целые, а ответ четный. Следовательно под ответ подходит только 54
The difference of cubes factorization unnecessary. It is in 0/0 form, so one application of lhospitals rule gives lim x approaches 3, 6x^2/1 = 54. Presented way got job done purely algebraically not having to appeal to Calculus.
Have you turned on English subtitles? Why it was activated you must have understood the reason why I didn't apply L'Hospital! But I'll explain to you, to use L"Hospital the student needs to know derivative, but if the student learns a limit first and then learns derivative, how is he going to apply L'Hospital? It doesn't make sense!
@@profreginaldomoraes нам в школе объяснили что такое простейшие производные (x^n)'=n*(x^(n-1)). А уже сложное дифференцирование изучали в университете. Возможно у Вас сначала проходят лимит, а потом уже производные) Спасибо)
Resolvido na thumbnail. X = 54 Tive aula anterior com um mega prof. Revelo agora: Reginaldo Moraes. +aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
Muito obrigado por mais esta linda aula !
Um forte abraço e um excelente domingo !
Muita saúde e paz !!
Obrigado Eliseu! Pra você também!
Fenomenal professor Reginaldo Moraes!
Tks
Vc é fera professor Reginaldo Moraes!
Obrigado
Sensacional professor Reginaldo Moraes!
Tks
Fantastico apreciado professor. Um gran abraço
Muito bom o exercício limites, a " pprta de entrada" para o estudo do "cälculo". Como fica bem o sinal de igual escrito na altura correta!
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Fantástico, professor! Tive cálculo em 1992-1994. Seria muito mais fácil aprender com a sua ajuda. Muito obrigado!
Show 😊
Bom dia professor Reginaldo Moraes 👏👍
Infelizmente eu nunca estudei Lim muito menos derivada
Porém vejo sua explicação que é muito excelente dá gosto ser sua aluna
Eu aprendi muita coisa boa de matemática com suas aulas 😃👍🙏🙇🙌
Gratidão que Deus te abençoe grandemente 🙌 like sempre
Oi Líbia, é conteúdo de matemática superior! Mas foi usado matemática básica! Obrigado! Amém! Deus te abençoe também!
Parabéns pela aula, muito didática e organizada.
Obrigado Anderson
Que maravilha! Sábado de manhã um vídeo sobre limites pra alegrar o isolamento. Muito obrigado! ☺️✌️
Valeu Fernando! Bons estudos!
Ótima explicação.
Valeu
Valeu!
Obrigado
Aula maravilhosa. Grande professor
Valeu Janderlan! Abraço
Nice problem. I was able to eliminate 9, 27, and 81 as solutions quickly. In my head I was able to factor the 2 from the numerator. I could see that the rest was a difference of cubes and without factoring it completely I could see it would cancel with the factor in the denominator. The expression would be 2 times a polynomial expression and evaluated at 3 must be an even number. Thanks again!
Very good! You're welcome! Hug
esse prof. é o cara viu
Abraço Lopes!
nossa deveria fazer uma aula de 1 hora resolvendo exercicios , fatorando , simplificando, ia ser otimo. É so com a pratica que o cara pega essa manhâs de fazer essas simplificações
Valeu mestre!!! Sempre surpreendendo as nossas expectativas 👍👍👍
Valeu Francisco! Abraço
Ótima aula viu
Obrigado
There is an indeterminate form 0/0.
We have two ways to solve this :
The first way : 2x^3-54=2(x-3)(x^2+3x+9)
The fraction becomes 2(x^2+3x+9) whose limit when x goes to 3 is 54.
The second way is to use the Hospital's rule :
The derivative of 2x^3-54 is 6x^2
The derivative of x-3 is 1
So, it is the limit when x goes to 3 for 6x^2 which is 54 as well.
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Ans : 54
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great math teacher
Thank you so much
Professor, poderia fazer uma questão de limite envolvendo seno? Tipo: lim x->0 (sin2x) / x
Limite fundamental trigonométrico? Posso sim!
Absolutely easy. By using L. Hospita's rule, it takes a minute to solve.
That's what I said in the video, it doesn't make sense to use L'Hospital, because the student who is studying limits doesn't know derivatives yet!
54 é 2×3³
Por simple inspección es 54, el único número par. Dos es factor común y no se puede simplificar.
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You can resolve this equation for five seconds by looking on answers. In numerator you move out 2. All other number are naturally. Thats means that result you can devide for 2. In test only one number 54
В общем сразу бросается в глаза что 2 выноситься за скобки а знаменатель сократится. Все дальнейшие числа будут целые, а ответ четный. Следовательно под ответ подходит только 54
Eu só fiz a divisão dos polinômios
(2x³-54)/(x-3)
Também dá
Tá aí um trem que nunca aprendi na escola
Só na universidade! 👊
@@profreginaldomoraes tá explicado, eu estudei até o ensino médio
Matéria de Cálculo Diferencial e Integral
With L'Hôpital's Rule it's done in 15 seconds
Nem precisava produto notável, bastava dividir e chegar a 2x^2 + 6x + 18,
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The difference of cubes factorization unnecessary. It is in 0/0 form, so one application of lhospitals rule gives lim x approaches 3, 6x^2/1 = 54.
Presented way got job done purely algebraically not having to appeal to Calculus.
Have you turned on English subtitles? Why it was activated you must have understood the reason why I didn't apply L'Hospital! But I'll explain to you, to use L"Hospital the student needs to know derivative, but if the student learns a limit first and then learns derivative, how is he going to apply L'Hospital? It doesn't make sense!
@@profreginaldomoraes I do understand your point. Until one proves why Lhospital’s rule is true, algebraic simplification is the the only way
That's right! A hug! Have a great week
Стесняюсь спросить: а для чего квадратные скобки?
Отделить умножение и развитие от разницы между двумя кубиками!
@@profreginaldomoraes зачем?
@@profreginaldomoraes двойку можно было вообще вынести сразу за знак предела
54 obviamente
1.01.22.
Правило Лопиталя не проще ли?
Конечно, но как применить правило, если студент, изучающий лимит, еще не знает производной?
@@profreginaldomoraes нам в школе объяснили что такое простейшие производные (x^n)'=n*(x^(n-1)). А уже сложное дифференцирование изучали в университете. Возможно у Вас сначала проходят лимит, а потом уже производные) Спасибо)
lim(x->3) (2х^3 - 54)/(х-3)
0/0?
2x^3-54 = f(x)
x-3 = g(x)
lim(x->3) f(x)/g(x) = lim(x->3) f'(x)/g'(x) = lim(x->3) 6x^2 = 6*(3)^2 = 54
Resolvido na thumbnail. X = 54
Tive aula anterior com um mega prof. Revelo agora: Reginaldo Moraes.
+aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
Opa! Aí sim! Parabéns! Tmj Márcio! Abraço
AS IDENTIDADES DE WARRING APARECENDO :D
tks
Lt=54
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Answer: ( c) 2.3.9
54
=54 ans
tks
g(x) = 2(x² + 3x + 9), x -> 3 => L = 54.
tks
= lim x➡3. 2(x^2 +3X+9)
= 54
tks
Quando eu vi o x-3 em baixo ja sabia que em cima ia ter x-3 pra dividir com ele. Questao malandra
Eu nunca vi isso me sinto burro
Magina, é conteúdo de nível superior!