Snell's Law & Index of Refraction Practice Problems - Physics
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- Опубліковано 3 жов 2024
- This physics video tutorial provides a basic introduction into snell's law which shows the relationship between the angle of incidence and the angle of refraction given the index of refraction of the two materials. This video explains how to calculate the speed of light of water given the index of refraction of water or how to calculate the index of refraction of diamond given the speed of light in diamond. It mentions how to calculate the wavelength of light in glass given the wavelength of light in a vacuum. This video on geometric optics contain plenty of examples and practice problems. As light moves from a material with a low index of refraction to a material with a high index of refraction, the light ray bends toward the normal line.
Law of Reflection - Geometric Optics:
• Law of Reflection - Ge...
The Mirror Equation:
• Spherical Mirrors & Th...
Refraction of Light:
• Refraction of Light
Snell's Law & Index of Refraction:
• Snell's Law & Index of...
Total Internal Reflection & Critical Angle:
• Total Internal Reflect...
Thin Lens Equation:
• Thin Lens Equation, Op...
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Ray Diagrams:
• Ray Diagrams
The Huygens Principle:
• Huygens Principle - Ph...
Young's Double Slit Experiment:
• Young's Double Slit Ex...
Single Slit Diffraction:
• Single Slit Diffractio...
Diffraction Grating Problems:
• Diffraction Grating Pr...
Polarization of Light Problems:
• Polarization of light ...
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I honestly believe I have spend over 24 hours watching videos from organic chem tutor starting with pre-cal through cal 2 and both physics 1 and 2
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Here to study for my test on EM spectrum and Optics on Friday for my Physics Class Thank you so much !!
thank you so much, you're a life saver.
Ur explanation is very much helpful 😁. If possible can u make a video on apparent depth and normal shift
Best explanations ,thank you.
You r thr best physics techer
Please make a video on thin-film interference
Could you make your voice louder while explaining, i had to put my headphones volume on FULL just to be able to hear what you were sayin innit? Thanks for having subtitles tho
Your voice was so romantic 😅
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Just to let you know, it is difficult to discern the dark blue color with the black background.
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@TheOrganicChemistry Tutor, Thank you for the explanations, they are very straightforward.I would appreciate if the questions are bolder.
Will the angle of refraction from diamond to air be equal to 60° in the air water diamond problem? 10:00
At 14:00 why can you just neglect n2sinθ2 from a physics standpoint?
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thank you very much Mr. organic chemistry.
x in the last problem should be 41.73 as 48.27 would be the other angle. 90-47.27 gives us the angle depicted as x.
does anybody know how to type it on calculator how did he find the angle of refraction😭 please i badly need help
What is the unit of measurement of the answer at 2:19?
n = index of refraction so there is no unit to it
it's just a ratio
@laceyharrison384, reason to this is because the units cancel out, thus becoming no units.
Very helpful! Thank You
Mukomerezaho ayamasomonimeza
miss malak said n is bigger in water so light is faster in water ur wrong smd
when i plug in 1Sin(30) into the calculator i get -.98, not .5 like in the problem, why is that??
you have your calculator in radians. it needs to be in degrees for these type of problems :)
You should be able to teach us this weekend way home through on -line
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how did it become22°?
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I did understood,but I'm kinda confused with sine -¹(........) Like what's the -¹ for?
The inverse sin of 1, ie sin-1 (1) is a very special value for the inverse sine function. Remember that sin-1(x) will give you the angle whose sine is x . Therefore, sin-1 (1) = the angle whose sine is 1.
Thank you!
dont you allways have to change the wavelength in meters?
Great vid I put the stuff on my notecard for exam appreciate the thorough video 😁
Thanks man
It's really useful for me .thank u
Thank you very much Sir for this information
Perfect
in my exams to
What is the value of sin-1
it helped me alot
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very useful
Amazing video ... thanks yet again!
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